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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#592226#9319. Bull FarmlaonongminWA 88ms5176kbC++173.6kb2024-09-26 21:17:392024-09-26 21:17:44

Judging History

你现在查看的是最新测评结果

  • [2024-09-26 21:17:44]
  • 评测
  • 测评结果:WA
  • 用时:88ms
  • 内存:5176kb
  • [2024-09-26 21:17:39]
  • 提交

answer

#pragma GCC optimize(3)
#include <bits/stdc++.h>
#define ll long long
#define pii pair<int,int>
#define N 2005
#define MOD 998244353
using namespace std;

vector<int> e[N];
int dfn[N], low[N], tot, st[N], inst[N], top, fa[N];
void tarjan(int u, int last)
{
    dfn[u] = low[u] = ++tot;
    st[++top] = u; inst[u] = 1;
    for(auto &&v:e[u])
    {
        if(!dfn[v])
        {
            tarjan(v, u);
            low[u] = min(low[u], low[v]);
        }
        else if(inst[v]) low[u] = min(low[u], dfn[v]);
    }
    if(dfn[u] == low[u])
    {
        int v;
        do{
            v = st[top--]; inst[v] = 0;
            fa[v] = u;
        }while(v != u);
    }
}
int rt(int x)
{
    while(x!=fa[x]) x=fa[x]=fa[fa[x]];
    return x;
}

bitset<N> vis;
void dfs(int u)
{
    for(auto &&v:e[u])
    {
        if(vis[v]) continue;
        vis[v]=1;
        dfs(v);
    }
}

int t[N][N];
int nt[N];
bitset<N> ans;
struct query{
    int a,b,id;
};
vector<query> qs[N];
void solve()
{
    int n,l,q;
    cin>>n>>l>>q;
    for(int i=1;i<=n;++i) {e[i].clear(); fa[i]=i;}
    for(int i=1;i<=l;++i) {qs[i].clear();}

    for(int i=1;i<=l;++i)
    {
        string s;
        cin>>s;
        for(int j=1;j<=n;++j) t[i][j] = (s[2*(j-1)]-48)*50 + (s[2*(j-1)+1]-48);
    }
    for(int i=1;i<=q;++i)
    {
        string s;
        cin>>s;
        int a = (s[0]-48)*50 + (s[1]-48);
        int b = (s[2]-48)*50 + (s[3]-48);
        int c = (s[4]-48)*50 + (s[5]-48);
        // cout<<a<<' '<<b<<' '<<c<<'\n';
        qs[c].push_back({a,b,i});
    }

    for(auto &&[a,b,id]:qs[0]) ans[id]=(a==b);
    for(int c=1;c<=l;++c)
    {
        
        // add
        for(int i=1;i<=n;++i) nt[i] = 0;
        int t1=0,t2=0;
        bool ok=true;
        for(int i=1;i<=n;++i)
        {
            if(!nt[t[c][i]]) nt[t[c][i]] = i;
            else
            {
                if(t1) ok=false;
                t1=i; t2=nt[t[c][i]];
            }
        }
        if(!t1 && !t2)
        {
            for(int i=1;i<=n;++i) e[rt(i)].push_back(rt(t[c][i]));
        }
        else if(ok)
        {
            for(int i=1;i<=n;++i)
            {
                if(!nt[i])
                {
                    int z=i;
                    t1=rt(t1), t2=rt(t2), z=rt(z);
                    e[t1].push_back(z);
                    e[t2].push_back(z);
                    break;
                }
            }
        }

        // tarjan
        tot=0; top=0;
        for(int i=1;i<=n;++i) {dfn[i]=0; inst[i]=0;}
        for(int i=1;i<=n;++i) if(!dfn[i] && rt(i)==i) tarjan(i,0);
        for(int i=1;i<=n;++i)
        {
            if(rt(i) != i) 
            {
                for(auto &&v:e[i]) if(rt(v) != rt(i)) e[rt(i)].push_back(rt(v));
                e[i].clear();
            }
            else
            {    
                vector<int> pe = e[i];
                e[i].clear();
                for(auto &&v:pe)
                {
                    v=rt(v);
                    if(v != i) e[i].push_back(v);
                }
            }
        }

        // cal
        for(auto &&[a,b,id]:qs[c])
        {
            for(int i=1;i<=n;++i) vis[i]=0;
            a=rt(a); b=rt(b);
            
            vis[a]=1;
            dfs(a);
            ans[id] = vis[b];
        }
    }
    // for(int i=1;i<=n;++i) cout<<rt(i)<<'\n';
    for(int i=1;i<=q;++i) cout<<ans[i];
    cout<<'\n';
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    int T;
    cin>>T;
    while(T--)
    {
        solve();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3708kb

input:

2
5 2 4
0305040201
0404040404
030300
020500
050102
020501
6 2 4
030603010601
010203060504
030202
060402
050602
060401

output:

1011
0100

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3804kb

input:

1
3 3 6
020202
030301
030201
020102
030203
010201
010303
020303
010202

output:

010101

result:

ok single line: '010101'

Test #3:

score: -100
Wrong Answer
time: 88ms
memory: 5176kb

input:

200
10 10 5000
01060:04020305080709
0103070:060204050908
09070503080401060:02
050308010204090:0607
03010502040607080:09
03080109020504060:07
06050:09040302080107
07080305010409060:02
030809010:0204060507
0:060908070201050304
060700
090:03
09080:
070405
010703
0:0100
080601
030600
070206
0:0:09
08040...

output:

011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...

result:

wrong answer 1st lines differ - expected: '011110001101101111111111111111...1111111111111111101111111111111', found: '011110001101101111111111111111...1111111111111111101111111111111'