QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#588683#7904. Rainbow SubarrayAlumin1um#TL 856ms9360kbC++202.5kb2024-09-25 14:01:012024-09-25 14:01:02

Judging History

你现在查看的是最新测评结果

  • [2024-09-25 14:01:02]
  • 评测
  • 测评结果:TL
  • 用时:856ms
  • 内存:9360kb
  • [2024-09-25 14:01:01]
  • 提交

answer

#include <bits/stdc++.h>
#define pii pair<int, int>
#define pll pair<long long, long long>
#define pdd pair<double, double>
#define vi vector<int>
#define vll vector<long long>
#define vpii vector<pair<int, int>>
#define vpll vector<pair<long long, long long>>
#define vpdd vector<pair<double, double>>
#define mp make_pair
#define fi first
#define se second
#define all(v) v.begin(), v.end()
#define pb push_back
#define endl "\n"
#define vvi vector<vector<int>>
#define vvll vector<vector<long long>>

using namespace std;
using LL = long long;
using ULL = unsigned long long;
const int N = 5e5 + 10, INF = 0x3f3f3f3f, mod = 998244353;
const LL bigINF = ((ULL)(1) << 63) - 1;
const double eps = 1e-6;
LL n, k;
vll a(N);

bool check(int x) {
    multiset<int> lo, hi;
    LL minus = 0, plus = 0;
    for (int i = 1; i < x; ++i)
    {
        lo.insert(a[i]);
        minus += a[i];
    }
    while (hi.size() < (x - 1) / 2)
    {
        minus -= *--lo.end();
        plus += *--lo.end();
        hi.insert(*--lo.end());
        lo.erase(--lo.end());
    }
    for (int i(x); i <= n; ++i)
    {
        if (lo.size() <= hi.size())
        {
            plus += a[i];
            hi.insert(a[i]);
            int mid = *hi.begin();
            hi.erase(hi.begin());
            lo.insert(mid);
            plus -= mid;
            minus += mid;
        }
        else
        {
            minus += a[i];
            lo.insert(a[i]);
            int mid = *--lo.end();
            lo.erase(--lo.end());
            hi.insert(mid);
            minus -= mid;
            plus += mid;
        }
        if (lo.size() * (*--lo.end()) - minus + plus - hi.size() * (*--lo.end()) <= k)
            return true;
        int old = a[i - x + 1];
        if (old <= *--lo.end())
        {
            minus -= old;
            lo.erase(lo.lower_bound(old));
        }
        else
        {
            plus -= old;
            hi.erase(hi.lower_bound(old));
        }
    }
    return false;
}

void Sol()
{
    
    cin >> n >> k;
    for(int i = 1; i<= n; i ++ ) {
        cin >> a[i];
        a[i] -= i;
    }
    int l = 1, r = n;

    while(l < r) {
        int mid = l + r + 1 >> 1;
        if(check(mid)) {
            l = mid;
        } else
            r = mid - 1;
    }
    cout << l << endl;
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr), cout.tie(nullptr);

    int t = 1;
    cin >> t;
    while (t--)
    {
        Sol();
    }

    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 2ms
memory: 7024kb

input:

5
7 5
7 2 5 5 4 11 7
6 0
100 3 4 5 99 100
5 6
1 1 1 1 1
5 50
100 200 300 400 500
1 100
3

output:

4
3
5
1
1

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 856ms
memory: 9360kb

input:

11102
2 167959139
336470888 134074578
5 642802746
273386884 79721198 396628655 3722503 471207868
6 202647942
268792718 46761498 443917727 16843338 125908043 191952768
2 717268783
150414369 193319712
6 519096230
356168102 262263554 174936674 407246545 274667941 279198849
9 527268921
421436316 3613460...

output:

1
4
3
2
6
5
7
2
4
1
4
1
1
3
2
2
7
8
7
7
1
7
6
2
4
3
1
6
7
7
3
4
3
9
3
8
6
6
3
1
6
3
1
2
4
6
4
6
4
1
4
7
1
6
3
5
6
6
1
7
5
3
1
6
4
5
3
2
2
6
2
3
10
1
4
3
2
4
5
1
7
5
5
5
8
5
3
6
3
5
5
8
5
4
5
2
1
5
2
3
3
4
8
1
3
1
2
2
8
3
1
6
8
1
8
4
5
6
6
8
4
8
3
2
8
4
5
6
2
6
2
4
1
5
4
5
3
2
4
1
2
1
4
5
8
3
7
3
3
3...

result:

ok 11102 lines

Test #3:

score: -100
Time Limit Exceeded

input:

1
500000 17244641009859
54748096 75475634 204928248 276927808 84875072 103158867 27937890 322595515 186026685 45468307 69240390 139887597 188586447 373764525 121365644 310156469 185188306 60350786 211308832 384695957 370562147 208427221 35937909 267590963 126478310 275357775 55361535 335993561 36696...

output:


result: