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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#587658#6837. AC Automatoncyj888WA 4ms52168kbC++115.9kb2024-09-24 20:58:352024-09-24 20:58:35

Judging History

你现在查看的是最新测评结果

  • [2024-09-24 20:58:35]
  • 评测
  • 测评结果:WA
  • 用时:4ms
  • 内存:52168kb
  • [2024-09-24 20:58:35]
  • 提交

answer

#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define ott(i,l,r) for (register int i = l; i <= r; ++ i)
#define tto(i,l,r) for (register int i = r; i >= l; -- i)
using namespace std;
using ll = long long;
inline int read () {
	int x = 0; bool f = 0; char c = getchar ();
	while (!isdigit (c)) f |= (c == '-'), c = getchar ();
	while (isdigit (c)) x = (x << 3) + (x << 1) + (c ^ 48), c = getchar ();
	if (f) x = -x; return x;
}
const int N = 3e5 + 110, inf = 0x3f3f3f3f;
int n, m, q, idx, B;
ll res;
int len; char pc[65];
void print () {
	ll x = res; len = 0; if (!x) putchar (48);
	while (x) pc[++ len] = x % 10, x /= 10;
	while (len) putchar (pc[len --] + 48); puts ("");
	return ;
}
vector <int> e[N], E[N];
int up[N], dn[N];
int dfn[N], dep[N], fa[N];
int lg[N << 1], f[N << 1][20];
char ch[N];
void dfs0 (int u) {
	f[dfn[u] = ++ idx][0] = u, dep[u] = dep[fa[u]] + 1;
	for (int v : e[u]) {
		dfs0 (v);
		f[++ idx][0] = u;
	}
	return ;
}
int lca (int x, int y) {
	x = dfn[x], y = dfn[y];
	if (x > y) swap (x, y);
	int z = lg[y - x + 1], f1 = f[x][z], f2 = f[y - (1 << z) + 1][z];
	return dep[f1] < dep[f2] ? f1 : f2;
}
struct OPT {
	int x; char c;
} a[N];
struct BLOCK {
	int ac, now, val, sum;//ac = 'A'count
	vector <int> s; vector <pair <int, int> > t;
	void upd (int i) {
		if (ch[i] == 'A') ++ ac;
		if (ch[i] == '?') {
			int v = dn[i] - up[i];
			if (v >= 0) ++ sum;
			if (-m <= v && v <= m) s.emplace_back (v);
		}
		return ;
	}
	void init () {
		t.emplace_back (-inf, 0);
		if (s.size ()) {
			sort (s.begin (), s.end ());
			ott (i, 0, s.size () - 1) {
	        	int cnt = 1; while (i + 1 < s.size () && s[i] == s[i + 1]) ++ i, ++ cnt;
	        	t.emplace_back (s[i], cnt);
			}
		}
		t.emplace_back (inf, 0);
		int l = 0, r = t.size () - 1, mid;
		while (l <= r) {
			mid = l + r >> 1;
			if (t[mid].fi >= 0) now = mid, r = mid - 1;
			else l = mid + 1;
		}
		return ;
	}
	void add (int v) {
		if (v == 1) {
			if (t[now].fi == val ++) sum -= t[now ++].se;
			res -= 1ll * sum;
		}
		if (v == -1) {
			res += 1ll * sum;
			if (t[now - 1].fi == -- val) sum += t[-- now].se;
		}
		return ;
	}
	void clear () {
		ac = now = val = sum = 0;
		vector <int> ().swap (s), vector <pair <int, int> > ().swap (t);
		return ;
	}
} b[N];
int id[N], val[N], FA[N];
inline int Max (int x, int y) {
	return x > y ? x : y;
}
inline bool cmp (const int &x, const int &y) {
	return dfn[x] < dfn[y];
}
void push (int u, int z) {
	b[z].upd (u);
	for (int v : e[u]) push (v, z);
	return ;
}
int Z, OTH;
void find (int x) {
	if (id[fa[x]]) {
		val[Z = id[x] = ++ idx] = x;
		return ;
	}
	find (fa[x]);
	b[Z].upd (fa[x]);
	for (int v : e[fa[x]]) {
		if (v == x) continue;
		if (!OTH) val[OTH = id[v] = ++ idx] = v;
		push (v, OTH);
	}
	return ;
}
void red (int u) {
	dn[u] = 0;
	for (int v : e[u]) {
		up[v] = up[u] + (ch[u] != 'C');
		red (v);
		dn[u] += dn[v] + (ch[v] != 'A');
	}
	if (ch[u] == 'A') res += 1ll * dn[u];
	if (ch[u] == '?') res += 1ll * Max (0, dn[u] - up[u]);
	return ;
}
void cup (int u, int V) {
	for (int v : E[u]) {
		if (val[v] < 0) {
			int tv = -val[v];
			if (ch[tv] == '?') res -= 1ll * Max (0, dn[tv] - up[tv]);
			up[tv] += V;
			if (ch[tv] == '?') res += 1ll * Max (0, dn[tv] - up[tv]);
		}
		else {
			b[v].add (V);
		}
		cup (v, V);
	}
	return ;
}
void cdn (int u, int V) {
	if (!u) return ;
	if (val[u] < 0) {
		int tu = -val[u];
		if (ch[tu] == '?') res -= 1ll * Max (0, dn[tu] - up[tu]);
		dn[tu] += V; if (ch[tu] == 'A') res += 1ll * V;
		if (ch[tu] == '?') res += 1ll * Max (0, dn[tu] - up[tu]);
	}
	else {
		b[u].add (-V), res += 1ll * b[u].ac * V;
	}
	cdn (FA[u], V);
	return ;
}
void sol () {
    ott (i, 1, m) val[++ idx] = a[i].x;
    sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
    sort (val + 1, val + 1 + idx, cmp);
    ott (i, 2, idx) val[idx + i - 1] = lca (val[i - 1], val[i]); val[idx += idx] = 1;
    sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
    ott (i, 1, idx) {
    	id[val[i]] = i;
    	val[i] = -val[i];//区分会修改的点
	}
	
    ott (i, 2, idx) {
    	if (val[i] > 0) break;
    	if (!id[fa[-val[i]]]) {
    		OTH = Z = 0, find (-val[i]);
    		if (OTH) E[FA[OTH] = i].pb (OTH);
    		E[FA[Z] = id[fa[val[Z]]]].pb (Z), E[FA[i] = Z].pb (i);
		}
		else E[FA[i] = id[fa[-val[i]]]].pb (i);
	}
	ott (i, 1, idx) {
		if (val[i] > 0) break;
		OTH = 0; for (int v : e[-val[i]]) {
			if (id[v]) continue;
			if (!OTH) {	
				val[OTH = id[v] = ++ idx] = v;
				E[FA[OTH] = i].pb (OTH);
			}
			push (v, OTH);
		}
	}
	ott (i, 1, idx) if (val[i] > 0) b[i].init ();
	ott (i, 1, m) {
		int x = a[i].x; char c = a[i].c;
		if (ch[x] != 'C') cup (id[x], -1); if (ch[x] != 'A') cdn (FA[id[x]], -1);
		if (ch[x] == 'A') res -= 1ll * dn[x];
		if (ch[x] == '?') res -= 1ll * Max (0, dn[x] - up[x]);
		ch[x] = c;
		if (ch[x] == 'A') res += 1ll * dn[x];
		if (ch[x] == '?') res += 1ll * Max (0, dn[x] - up[x]);
		if (ch[x] != 'C') cup (id[x], 1); if (ch[x] != 'A') cdn (FA[id[x]], 1);
		print ();
	}
	ott (i, 1, idx) {
		E[i].clear (), FA[i] = 0;
		if (val[i] < 0) val[i] = -val[i];
		else b[i].clear ();
		id[val[i]] = 0, val[i] = 0;
	}
	m = idx = 0, res = 0, red (1);
	return ;
}
int main () {
	//freopen ("data.in", "r", stdin); freopen ("res.out", "w", stdout);
	n = read (), q = read (), scanf ("%s", ch + 1); ott (i, 2, n) {
		e[fa[i] = read ()].pb (i);
	}
	B = 700, dfs0 (1), idx = 0, red (1);
	ott (j, 1, 19) {
		ott (i, 1, idx - (1 << j) + 1) {
			int f1 = f[i][j - 1], f2 = f[i + (1 << j - 1)][j - 1];
			f[i][j] = dep[f1] < dep[f2] ? f1 : f2;
		}
	}
	lg[0] = -1;	ott (i, 1, idx) lg[i] = lg[i >> 1] + 1;
	 ott (i, 1, q) {
		int x = read (); char c = getchar ();
		a[++ m] = {x, c};
		if (i % B == 0 || i == q) sol ();
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 51908kb

input:

5 3
AC??C
1 2 2 1
1 ?
4 A
2 ?

output:

4
3
3

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 4ms
memory: 52168kb

input:

1000 1000
AC?ACCCCC?CCA??CCCCC?A?AC?C??C?ACCCACC?C?CCC?CACACA???????C?????CC?C?AAAAACCA??AAAACACACA???AACAC?CCC?CAC?AAAACCAC???ACAA??A??A?CA?A?ACACACCAA?ACACA?AC??AC??ACAAACCC??CAA?A???CC?AA??AC???A?CCCC??CACCAACC?AA?C?AAACCCA?AAA??C?CC??CACCACAACCA?AACCC?A?CCC?CC???AA?CACCCAAC??CAA??C?AA??CA???CAAA...

output:

2344
2345
2340
2385
2780
2780
2793
2793
2793
2793
2793
2793
2793
2786
2786
2786
2786
2783
2798
2798
2826
2821
2817
2820
2825
2830
2830
2830
2830
2830
2830
2835
2835
2835
2835
2790
2786
2790
2798
2753
2754
2748
2704
2731
2733
2733
2733
2810
2812
2812
2856
2859
2859
2857
2932
2934
2937
2932
2939
2941
...

result:

wrong answer 3rd lines differ - expected: '2342', found: '2340'