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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#587171#6837. AC Automatoncyj888RE 0ms0kbC++115.6kb2024-09-24 17:56:562024-09-24 17:56:56

Judging History

你现在查看的是最新测评结果

  • [2024-09-24 17:56:56]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:0kb
  • [2024-09-24 17:56:56]
  • 提交

answer

#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define ott(i,l,r) for (register int i = l; i <= r; ++ i)
#define tto(i,l,r) for (register int i = r; i >= l; -- i)
using namespace std;
using ll = long long;
inline int read () {
	int x = 0; bool f = 0; char c = getchar ();
	while (!isdigit (c)) f |= (c == '-'), c = getchar ();
	while (isdigit (c)) x = (x << 3) + (x << 1) + (c ^ 48), c = getchar ();
	if (f) x = -x; return x;
}
const int N = 3e5 + 110, inf = 0x3f3f3f3f;
int n, m, q, idx, B;
ll res;
vector <int> e[N], E[N];
int up[N], dn[N];
int dfn[N], dep[N], fa[N];
int lg[N << 1], f[N << 1][20];
char ch[N];
void dfs0 (int u) {
	f[dfn[u] = ++ idx][0] = u, dep[u] = dep[fa[u]] + 1;
	for (int v : e[u]) {
		dfs0 (v);
		f[++ idx][0] = u;
	}
	return ;
}
inline int lca (int x, int y) {
	x = dfn[x], y = dfn[y];
	if (x > y) swap (x, y);
	int z = lg[y - x + 1], f1 = f[x][z], f2 = f[y - (1 << z) + 1][z];
	return dep[f1] < dep[f2] ? f1 : f2;
}
struct OPT {
	int x; char c;
} a[N];
struct BLOCK {
	int ac, now, val, sum;//ac = 'A'count
	vector <int> s; vector <pair <int, int> > t;
	inline void ins (int v) {
		if (v >= 0) ++ sum;
		if (-m <= v && v <= m) s.pb (v);
		return ;
	}
	inline void init () {
		t.pb ({-inf, 0});
		if (s.size ()) {
			sort (s.begin (), s.end ());
			ott (i, 0, s.size () - 1) {
	        	int cnt = 1; while (i + 1 < s.size () && s[i] == s[i + 1]) ++ i, ++ cnt;
	        	t.pb ({s[i], cnt});
			}
		}
		t.pb ({inf, 0});
		if (t.size ()) tto (i, 0, t.size () - 1) if (t[i].fi >= 0) now = i;
		return ;
	}
	inline void upd (int i) {
		if (ch[i] == 'A') ++ ac;
		if (ch[i] == '?') ins (dn[i] - up[i]);
		return ;
	}
	inline void add (int v) {
		if (v == 1) {
			if (t[now].fi == val ++) sum -= t[now ++].se;
			res -= 1ll * sum;
		}
		if (v == -1) {
			res += 1ll * sum;
			if (t[now - 1].fi == -- val) sum += t[-- now].se;
		}
		return ;
	}
	inline void clear () {
		ac = now = val = sum = 0;
		vector <int> ().swap (s), vector <pair <int, int> > ().swap (t);
		return ;
	}
} b[N];
int id[N], val[N], FA[N];
inline bool cmp (int x, int y) {
	return dfn[x] < dfn[y];
}
void push (int u, int z) {
	b[z].upd (u);
	for (int v : e[u]) push (v, z);
	return ;
}
int Z, OTH;
void find (int x) {
	if (id[fa[x]]) {
		val[Z = id[x] = ++ idx] = x;
		return ;
	}
	find (fa[x]);
	b[Z].upd (fa[x]);
	for (int v : e[fa[x]]) {
		if (v == x) continue;
		if (!OTH) val[OTH = id[v] = ++ idx] = v;
		push (v, OTH);
	}
	return ;
}
void red (int u) {
	dn[u] = 0;
	for (int v : e[u]) {
		up[v] = up[u] + (ch[u] != 'C');
		red (v);
		dn[u] += dn[v] + (ch[v] != 'A');
	}
	if (ch[u] == 'A') res += 1ll * dn[u];
	if (ch[u] == '?') res += 1ll * max (0, dn[u] - up[u]);
	return ;
}
void cup (int u, int V) {
	for (int v : E[u]) {
		if (val[v] < 0) {
			int tv = -val[v];
			if (ch[tv] == '?') res -= 1ll * max (0, dn[tv] - up[tv]);
			up[tv] += V;
			if (ch[tv] == '?') res += 1ll * max (0, dn[tv] - up[tv]);
		}
		else {
			b[v].add (V);
		}
		cup (v, V);
	}
	return ;
}
void cdn (int u, int V) {
	if (!u) return ;
	if (val[u] < 0) {
		int tu = -val[u];
		if (ch[tu] == '?') res -= 1ll * max (0, dn[tu] - up[tu]);
		dn[tu] += V; if (ch[tu] == 'A') res += 1ll * V;
		if (ch[tu] == '?') res += 1ll * max (0, dn[tu] - up[tu]);
	}
	else {
		b[u].add (-V), res += 1ll * b[u].ac * V;
	}
	cdn (FA[u], V);
	return ;
}
void sol () {
    ott (i, 1, m) val[++ idx] = a[i].x;
    sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
    sort (val + 1, val + 1 + idx, cmp);
    ott (i, 2, idx) val[idx + i - 1] = lca (val[i - 1], val[i]); val[idx += idx] = 1;
    sort (val + 1, val + 1 + idx), idx = unique (val + 1, val + 1 + idx) - val - 1;
    ott (i, 1, idx) {
    	id[val[i]] = i;
    	val[i] = -val[i];//区分会修改的点
	}
	
    ott (i, 2, idx) {
    	if (val[i] > 0) break;
    	if (!id[fa[-val[i]]]) {
    		OTH = Z = 0, find (-val[i]);
    		if (OTH) E[FA[OTH] = i].pb (OTH);
    		E[FA[Z] = id[fa[val[Z]]]].pb (Z), E[FA[i] = Z].pb (i);
		}
		else E[FA[i] = id[fa[-val[i]]]].pb (i);
	}
	ott (i, 1, idx) {
		if (val[i] > 0) break;
		OTH = 0; for (int v : e[-val[i]]) {
			if (id[v]) continue;
			if (!OTH) {
				val[OTH = id[v] = ++ idx] = v;
				E[FA[OTH] = i].pb (OTH);
			}
			push (v, OTH);
		}
	}
	ott (i, 1, idx) if (val[i] > 0) b[i].init ();
	ott (i, 1, m) {
		int x = a[i].x; char c = a[i].c;
		if (ch[x] != 'C') cup (id[x], -1); if (ch[x] != 'A') cdn (FA[id[x]], -1);
		if (ch[x] == 'A') res -= 1ll * dn[x];
		if (ch[x] == '?') res -= 1ll * max (0, dn[x] - up[x]);
		ch[x] = c;
		if (ch[x] == 'A') res += 1ll * dn[x];
		if (ch[x] == '?') res += 1ll * max (0, dn[x] - up[x]);
		if (ch[x] != 'C') cup (id[x], 1); if (ch[x] != 'A') cdn (FA[id[x]], 1);
		printf ("%lld\n", res);
	}
	ott (i, 1, idx) {
		E[i].clear (), FA[i] = 0;
		if (val[i] < 0) val[i] = -val[i];
		else b[i].clear ();
		id[val[i]] = 0, val[i] = 0;
	}
	m = idx = 0, res = 0; red (1);
	return ;
}
int main () {
	freopen ("data.in", "r", stdin); freopen ("res.out", "w", stdout);
	n = read (), q = read (); ott (i, 1, n) ch[i] = getchar (); ott (i, 2, n) e[fa[i] = read ()].pb (i);
	B = 900; dfs0 (1);
	ott (j, 1, 19) {
		ott (i, 1, idx - (1 << j) + 1) {
			int f1 = f[i][j - 1], f2 = f[i + (1 << j - 1)][j - 1];
			f[i][j] = dep[f1] < dep[f2] ? f1 : f2;
		}
	}
	lg[0] = -1;	ott (i, 1, idx) lg[i] = lg[i >> 1] + 1;
	idx = 0, red (1); ott (i, 1, q) {
		int x = read (); char c = getchar ();
		a[++ m] = {x, c};
		if (i % B == 0 || i == q) sol ();
	}
	return 0;
}

Details

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Test #1:

score: 0
Dangerous Syscalls

input:

5 3
AC??C
1 2 2 1
1 ?
4 A
2 ?

output:


result: