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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#578664#9320. Find the Easiest Problemjk231528TL 0ms42644kbC++14671b2024-09-20 20:43:202024-09-20 20:43:20

Judging History

你现在查看的是最新测评结果

  • [2024-09-20 20:43:20]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:42644kb
  • [2024-09-20 20:43:20]
  • 提交

answer

#include<iostream>
#include<set>
#include<cstring>
#define sc scanf
using namespace std;
const int N=2e5+8;
int a[50][N];
int ans[50];
int main()
{
	int t;cin>>t;
	while(t--)
	{
		int n;cin>>n;
		int res,maxx=0;
		memset(ans,0,sizeof(ans));
		memset(a,0,sizeof(a));
		for(int i=1;i<=n;i++ )
		{
			string  s;cin>>s;
			int num=s[4]-'A'+1;
			char x;cin>>x;
			cin>>s;
			if(s[0]=='r')
				continue;
			else
			{
				int t=x-'A'+1;
				if(!a[t][num])
				{
					ans[t]++;
					a[t][num]++;
					if(maxx<ans[t])
						maxx=ans[t],res=t;
				}
				else
					continue;
			}
		}
		res=res+'A'-1;
		printf("%c\n",res);
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 42644kb

input:

2
5
teamA A accepted
teamB B rejected
teamC A accepted
teamB B accepted
teamD C accepted
4
teamA A rejected
teamB A accepted
teamC B accepted
teamC B accepted

output:

A
A

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

1000
44
WaiooyIXa O accepted
WaiooyIXa P accepted
ZYYsNWag P accepted
DPIawQg D rejected
IzPdjnM Z rejected
Ra D rejected
kwQyGxLo I rejected
DPIawQg L accepted
kwQyGxLo I accepted
mmWxDuADCB D rejected
PXwVAOgwiz P rejected
ZYYsNWag U accepted
IzPdjnM Z accepted
TgBNO P rejected
kwQyGxLo J accepted...

output:

Z
E
Z
O
B
I
G
H
T
K
Y
I
H
R
Z
X
W
O
I
V
C
Y
I
P
A
O
A
Z
F
O
F
O
R
T
H
G
K
E
S
D
H
D
R
Y
U
V
W
P
Z
O
T
E
A
U
U
M
J
T
L
Y
V
W
Z
N
E
O
Q
H
G
G
J
O
O
M
D
Z
J
K
K
W
J
S
E
W
Z
K
X
I
S
P
O
H
L
Z
H
W
I
P
T
D
O
P
F
N
X
S
Y
Z
S
G
J
H
Q
T
O
C
O
X
F
L
O
Y
E
J
P
S
Q
R
X
N
D
N
O
Q
L
M
X
R
H
Z
J
Z
Y
K
G
F
V
N
B
K
...

result: