#include<bits/stdc++.h>
const int maxn = 2e3 + 5;
const int maxm = 1e6 + 5;
const int maxq = 1e6 + 5;
const int inf = 1e9 + 7;
using namespace std;
int n, T, Q, l;
int t[maxn][maxn], in[maxn], fa[maxn];
char s[maxm];
int dis[maxn], vis[maxn], ans[maxn][maxn];
vector<pair<int, int> > edge[maxn];
queue<int> q[maxn];
void dijkstra(int v0){
    for (int i = 1; i <= n; i++)
        dis[i] = inf, vis[i] = 0;
    dis[v0] = 0;
    q[0].push(v0);
    for (int i = 0; i <= l; i++){
        while(!q[i].empty()){
            int x = q[i].front();
            q[i].pop();
            if(vis[x])
                continue;
            vis[x] = 1;
            for (auto v : edge[x]){
                int y = v.first, w = max(v.second, dis[x]);
                if(dis[y] > w){
                    dis[y] = w;
                    q[w].push(y);
                }
            }
        }
    }
}
int find(int x){
    return (x == fa[x]) ? x : fa[x] = find(fa[x]);
}
void merge(int x, int y, int num){
    int fx = find(x), fy = find(y);
    if(fx == fy)
        return;
    edge[x].push_back({y, num});
    edge[y].push_back({x, num});
    fa[fx] = fy;
}
void solve(){
    scanf("%d %d %d", &n, &l, &Q);
    for (int i = 1; i <= l;i++){
        scanf("%s", s + 1);
        int m = strlen(s + 1);
        for (int j = 1, k = 1; j <= m; j += 2, k++)
            t[i][k] = (s[j] - '0') * 50 + (s[j + 1] - '0');
    }
    for (int i = 1; i <= n; i++)
        fa[i] = i, edge[i].clear();
    for (int i = 1; i <= l;i++){
        for (int j = 1; j <= n; j++)
            in[j] = 0;
        for (int j = 1; j <= n; j++)
            in[t[i][j]]++;
        int sz = 0;
        for (int j = 1; j <= n;j++)
            sz += (in[j] > 0);
        //cout << i << "--- " << sz << endl;
        if(sz <= n-2)
            continue;
        if(sz == n)
            for (int j = 1; j <= n;j++)
                merge(j, t[i][j], i);
        else{
            int x = 0, y = 0;
            for (int j = 1; j <= n;j++){
                if(in[j] == 0)
                    x = j;
                else if(in[j] == 2)
                    y = j;
            }
            for (int j = 1; j <= n; j++){
                if(t[i][j] == y && j != x)
                    edge[j].push_back({x, i});
            }
        }
    }
    for (int i = 1; i <= n; i++){
        dijkstra(i);
        for (int j = 1; j <= n; j++)
            ans[i][j] = dis[j];
        //for (int j = 1; j <= n; j++)
            //cout << dis[j] << " ";
        //cout << endl;
    }
    for (int i = 1, a, b, c; i <= Q; i++)
    {
        scanf("%s", s + 1);
        a = (s[1] - '0') * 50 + (s[2] - '0');
        b = (s[3] - '0') * 50 + (s[4] - '0');
        c = (s[5] - '0') * 50 + (s[6] - '0');
        if(ans[a][b] <= c)
            printf("1");
        else
            printf("0");
    }
    puts("");
}
int main(){
    scanf("%d", &T);
    for (; T;T--)
        solve();
    return 0;
}