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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#578282 | #9319. Bull Farm | mitthu | RE | 1ms | 8040kb | C++14 | 3.2kb | 2024-09-20 17:57:54 | 2024-09-20 17:57:58 |
Judging History
answer
#include<bits/stdc++.h>
const int maxn = 2e3 + 5;
const int maxm = 1e6 + 5;
const int maxq = 1e6 + 5;
const int inf = 1e9 + 7;
using namespace std;
int n, T, Q, l;
int t[maxn][maxn], in[maxn], fa[maxn];
char s[maxm];
int dis[maxn], vis[maxn], ans[maxq];
struct node{
int x, tim, num;
};
vector<pair<int, int> > edge[maxn];
vector<node> st[maxn];
priority_queue<pair<int, int>> q;
void dijkstra(int v0){
for (int i = 1; i <= n; i++)
dis[i] = inf, vis[i] = 0;
dis[v0] = 0;
q.push({0, v0});
while (!q.empty()){
int x = q.top().second;
q.pop();
if(vis[x])
continue;
vis[x] = 1;
for(auto v : edge[x]){
int y = v.first, w = v.second;
//cout << x << " " << y << " " << w << endl;
if(dis[y] > max(dis[x], w)){
dis[y] = max(dis[x], w);
if(!vis[y])
q.push({-dis[y], y});
}
}
}
}
int find(int x){
return (x == fa[x]) ? x : fa[x] = find(fa[x]);
}
void merge(int x, int y, int num){
x = find(x), y = find(y);
if(x == y)
return;
edge[x].push_back({y, num});
edge[y].push_back({x, num});
fa[x] = y;
}
void solve(){
scanf("%d %d %d", &n, &l, &Q);
for (int i = 1; i <= l;i++){
scanf("%s", s + 1);
int m = strlen(s + 1);
for (int j = 1, k = 1; j <= m; j += 2, k++)
t[i][k] = (s[j] - '0') * 50 + (s[j + 1] - '0');
}
for (int i = 1; i <= n; i++)
fa[i] = i, edge[i].clear();
for (int i = 1; i <= Q; i++)
st[i].clear();
for (int i = 1, a, b, c; i <= Q; i++)
{
scanf("%s", s + 1);
a = (s[1] - '0') * 50 + (s[2] - '0');
b = (s[3] - '0') * 50 + (s[4] - '0');
c = (s[5] - '0') * 50 + (s[6] - '0');
st[a].push_back({b, c, i});
}
for (int i = 1; i <= l;i++){
for (int j = 1; j <= n; j++)
in[j] = 0;
for (int j = 1; j <= n; j++)
in[t[i][j]]++;
int sz = 0;
for (int j = 1; j <= n;j++)
sz += (in[j] > 0);
//cout << i << "--- " << sz << endl;
if(sz <= n-2)
continue;
if(sz == n)
for (int j = 1; j <= n;j++)
edge[j].push_back({t[i][j], i});
else{
int x = 0, y = 0;
for (int j = 1; j <= n;j++){
if(in[j] == 0)
x = j;
else if(in[j] == 2)
y = j;
}
for (int j = 1; j <= n; j++){
if(t[i][j] == y && j != x)
edge[j].push_back({x, i});
}
}
}
for (int i = 1; i <= n; i++){
dijkstra(i);
for (auto x : st[i]){
if(dis[x.x] <= x.tim)
ans[x.num] = 1;
else
ans[x.num] = 0;
}
//for (int j = 1; j <= n; j++)
//cout << dis[j] << " ";
//cout << endl;
}
for (int i = 1; i <= Q; i++)
printf("%d", ans[i]);
puts("");
}
int main(){
scanf("%d", &T);
for (; T;T--)
solve();
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 7956kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 8040kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: -100
Runtime Error
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110001101101111111111111111111101111111110111011110110110111011010111111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...