QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#578142 | #9313. Make Max | fufufuf | WA | 0ms | 3524kb | C++14 | 1.0kb | 2024-09-20 16:55:47 | 2024-09-20 16:55:49 |
Judging History
answer
#include<bits/stdc++.h>
#define ll long long
using namespace std;
const ll maxn = (ll)2e5 + 7;
//求出左边第一个比他大的元素和右边第一个比他大的元素
ll a[maxn];
ll n;
void solve() {
cin>>n;
vector<ll> a(n + 2);
a[0] = a[n + 1] = 2e9;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
ll ans = 0;
//左边第一个绝对比他小的元素
vector<ll> stk={ 0 };
for (int i = 1; i <= n; i++) {
while (!stk.empty() and a[stk.back()] <= a[i]) {
stk.pop_back();
}
ans += i - stk.back() - 1;
stk.push_back(i);
}
//右边第一个绝对比他小的元素
stk = { n + 1 };
for (int i = n; i >= 1; i--) {
while (!stk.empty() and a[stk.back()] <= a[i]) {
stk.pop_back();
}
if (a[stk.back()] != a[i]) ans += stk.back() - i - 1;
stk.push_back(i);
}
cout << ans << '\n';
}
ll T;
int main() {
cin >> T;
while (T--) {
solve();
}
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3524kb
input:
4 2 1 2 2 2 2 7 1 1 1 2 2 2 2 3 1 2 3
output:
1 2 30 3
result:
wrong answer 2nd numbers differ - expected: '0', found: '2'