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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#574888#2519. Number with BachelorsOthersAC ✓175ms97408kbC++143.5kb2024-09-19 07:57:232024-09-19 07:57:27

Judging History

你现在查看的是最新测评结果

  • [2024-09-19 07:57:27]
  • 评测
  • 测评结果:AC
  • 用时:175ms
  • 内存:97408kb
  • [2024-09-19 07:57:23]
  • 提交

answer

// 
#include <bits/stdc++.h>
#define ll __int128
#define int __int128
#define db long double
#define x first
#define y second
#define wdnmd const int mod=::mod;
#define eps 1e-12
#define lb(i) ((i)&(-(i)))
#define wr(x,ch) write(x),putchar(ch)
using namespace std;
typedef pair<int,char> paic;
typedef pair<int,int> pai;
typedef pair<pai,int> paii;
typedef pair<pai,pai> ppai;
typedef pair<ppai,int> ppaii;
pai operator+(const pai &x,const pai &y) {return pai(x.x+y.x,x.y+y.y);}
pai operator-(const pai &x,const pai &y) {return pai(x.x-y.x,x.y-y.y);}
#define gh() getchar()
inline long long read() {
	char ch=gh();
	long long x=0;
	char t=0;
	while(ch<'0'||ch>'9')   t|=ch=='-',ch=gh();
	while(ch>='0'&&ch<='9') x=x*10+(ch^48),ch=gh();
	return t?-x:x;
}
void write(ll x) {
    if(x<0) putchar('-'),x=-x;
    if(x>=10) write(x/10);
    putchar(x%10^48);
    return ;
}
const int one=1;
ll dp[2][45][1<<10],dp2[2][45][1<<16],sta[45],len;
int l,r,k;
char typ[12],Typ[12],num[105];
ll dfs1(ll x,ll f1,ll f0,ll S) {
	if(x==0) return 1;
	if(!f1&&dp[f0][x][S]!=-1) return dp[f0][x][S];
	ll ans;
	if(f0) ans=dfs1(x-1,0,1,0);
	else ans=(S&1)?0:dfs1(x-1,f1&(!sta[x]),0,S|1);
	for(ll i=1;i<10;i++) {
		if(S>>i&1) continue;
		if(f1&&i>sta[x]) break;
		ans+=dfs1(x-1,f1&(i==sta[x]),0,S|(1<<i));
	}
	if(!f1) return dp[f0][x][S]=ans;
	return ans;
}
ll dfs2(ll x,ll f1,ll f0,ll S) {
	if(x==0) return 1;
	if(!f1&&dp2[f0][x][S]!=-1) return dp2[f0][x][S];
	ll ans;
	if(f0) ans=dfs2(x-1,0,1,0);
	else ans=(S&1)?0:dfs2(x-1,f1&(!sta[x]),0,S|1);
	for(int i=1;i<16;i++) {
		if(S>>i&1) continue;
		if(f1&&i>sta[x]) break;
		ans+=dfs2(x-1,f1&(i==sta[x]),0,S|(1<<i));
	}
	if(!f1) return dp2[f0][x][S]=ans;
	return ans;
}
ll solve1(int x) {
	if(x==-1) return 0;
	len=0;
	while(x) sta[++len]=x%10,x/=10;
//	memset(dp[1],-1,sizeof(dp[1]));
	return dfs1(len,1,1,0);
}
ll solve2(int x) {
	if(x==-1) return 0;
	len=0;
	while(x) sta[++len]=x%16,x/=16;
//	memset(dp[1],-1,sizeof(dp[1]));
	return dfs2(len,1,1,0);
}
inline char id(int x) {
	if(x<10) return x+'0';
	return x-10+'a';
}
inline int id2(char x) {
	if(isdigit(x)) return x^48;
	return x-'a'+10;
}
inline int calc(char *a) {
	int l=strlen(a);
	int ans=0;
	for(int i=0;i<l;i++) ans=ans*16+id2(a[i]);
	return ans;
}
inline void print(int x) {
	if(x>=16) print(x/16);
	putchar(id(x%16));
	return ;
}
void solve() {
	scanf("%s",typ),scanf("%s",Typ);
	if(typ[0]=='d') {
		if(Typ[0]=='0') {//10th count
			l=read(),r=read(),l--;
			wr(solve1(r)-solve1(l),'\n');
		} else {//10th kth
			k=read();
			if(k>8877690) {
				puts("-");
				return ;
			}
			int l=0,r=10000000000,mid;
			while(l<r) {
				mid=l+r>>1;
//				wr(mid,' '),wr(solve1(mid),'\n');
				if(solve1(mid)<k) l=mid+1;
				else r=mid;
			}
			if(solve1(l)==k) wr(l,'\n');
			else puts("-");
		}
	} else {
		if(Typ[0]=='0') {//16th count
			scanf("%s",num),l=calc(num)-1;
			scanf("%s",num),r=calc(num);
//			wr(solve2(r)-solve2(l),'\n');
			print(solve2(r)-solve2(l)),putchar('\n');
		} else {//16th kth
			scanf("%s",num);
			k=calc(num);
			if(k>53319412081140) {
				puts("-");
				return ;
			}
			int l=0,r=one<<70,mid;
			while(l<r) {
				mid=l+r>>1;
				if(solve2(mid)<k) l=mid+1;
				else r=mid;
			}
			if(solve2(l)==k) print(l),putchar('\n');
			else puts("-");
		}
	}
	return ;
}
signed main() {
	memset(dp,-1,sizeof(dp));
	memset(dp2,-1,sizeof(dp2));
	int Test=read();
	while(Test--) solve();
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 56ms
memory: 97408kb

input:

6
d 0 10 20
h 0 10 1f
d 1 10
h 1 f
d 1 1000000000
h 1 ffffffffffffffff

output:

10
f
9
e
-
-

result:

ok 6 lines

Test #2:

score: 0
Accepted
time: 175ms
memory: 97268kb

input:

50000
h 1 147a
d 0 25 71
d 1 3587
d 0 26922 51887
d 1 711
d 0 3 5
h 0 7bf2defab442a0b1 f299a4cf1d4d9bed
d 0 6961 91018
d 1 4
d 1 876
h 1 12cc5d3370f99120
d 1 161315
h 0 25f 6959
d 0 467 516
d 1 298
h 1 70260cdc2da73281
h 1 928e17d65d764ca2
h 1 c8ec8a7b67605e51
d 1 91697
d 0 4941925161850941148 89850...

output:

1b36
43
6587
7710
953
3
8daab378500
26054
3
1356
-
946307
4681
40
387
-
-
-
491850
0
1
29
-
4605298
1
1
-
15b4
175f
9b944134000
124b7
6279
9
6257
-
39be22a900
5c636b59300
146ce
2a55
-
0
-
7
d
6
2041
-
1c94afe7300
0
5
9149
16540973
1389
125
0
-
3bc31189480
424
66800
7
-
-
1e6
0
0
48b6
9
-
2b0
5019
14...

result:

ok 50000 lines