QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#574826 | #9320. Find the Easiest Problem | winterl | WA | 1ms | 3980kb | C++20 | 1.1kb | 2024-09-19 01:06:19 | 2024-09-19 01:06:20 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
map<string, int> m;
auto solve() {
int n;
cin >> n;
vector a(27, 0);
vector vis(n + 5, vector(27, false));
// index_of_range
int j = 1;
for (int i = 1; i <= n; i++) {
string s1, s2;
char zm;
cin >> s1;
cin >> zm;
cin >> s2;
if (!m.contains(s1)) {
m[s1] = j++;
}
try {
if (!vis.at(m[s1]).at(zm - 'A' + 1) and s2 == "accepted") {
a[zm - 'A' + 1]++;
vis.at(m[s1]).at(zm - 'A' + 1) = true;
}
} catch (...) {
cout << '(' << n << ") - ([" << s1 << "]) - " << '[' << m[s1] << "] - [(" << vis.size() << ")]";
exit(0);
}
}
int ans = 0, ans_i = 0;
for (int i = 1; i <= 26; i++) {
if (a[i] > ans) {
ans = a[i];
ans_i = i;
}
}
cout << char(ans_i + 64) << endl;
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int64_t t;
cin >> t;
while (t--)
solve();
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3836kb
input:
2 5 teamA A accepted teamB B rejected teamC A accepted teamB B accepted teamD C accepted 4 teamA A rejected teamB A accepted teamC B accepted teamC B accepted
output:
A A
result:
ok 2 lines
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3980kb
input:
1000 44 WaiooyIXa O accepted WaiooyIXa P accepted ZYYsNWag P accepted DPIawQg D rejected IzPdjnM Z rejected Ra D rejected kwQyGxLo I rejected DPIawQg L accepted kwQyGxLo I accepted mmWxDuADCB D rejected PXwVAOgwiz P rejected ZYYsNWag U accepted IzPdjnM Z accepted TgBNO P rejected kwQyGxLo J accepted...
output:
Z E Z I B I G H S K J I H R Z C K O I P A B I A A N A B A O F O R T H G K E S D F D R C U V W P A O J E A B U M C T L G V A Z N E O Q F B (4) - ([TgBNO]) - [9] - [(9)]
result:
wrong answer 70th lines differ - expected: 'G', found: '(4) - ([TgBNO]) - [9] - [(9)]'