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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#567880 | #9319. Bull Farm | ATM12345 | WA | 93ms | 8256kb | C++14 | 2.2kb | 2024-09-16 14:27:08 | 2024-09-16 14:27:09 |
Judging History
answer
#include <bits/stdc++.h>
#define ll int
#define LL long long
#define ls p<<1
#define rs p<<1|1
#define Ma 1000005
#define mod 1000000007
#define PLL pair<ll,ll>
#define PDD pair<double,double>
#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define fi first
#define se second
#define N 2005
#define pb push_back
#define ld long double
#define all(x) x.begin(),x.end()
#define inf 1e18
using namespace std;
ll n,m,q;
ll a[N][N];
ll ask(ll x,ll y)
{
return (x-48)*50+(y-48);
}
struct node{
ll a,b,c,id;
bool operator <(const node &A)const{
return c<A.c;
}
}t[Ma];
ll ans[Ma];
ll ru[N];
ll vis[N];
bitset <N> f[N];
void dfs(ll id,ll x)
{
bitset <N> res=f[x];
vis[x]=1;
vector <ll> v;
v.pb(x);
while (!vis[a[id][x]])
x=a[id][x],vis[x]=1,res|=f[x],v.pb(x);
for (auto z:v)
f[z]=res;
return;
}
void go(ll x)
{
for (ll i=1;i<=n;i++)
ru[i]=0;
ll cnt=0;
for (ll i=1;i<=n;i++)
{
ru[a[x][i]]++;
if (ru[a[x][i]]==2)
cnt++;
if (ru[a[x][i]]>2)
return;
}
if (cnt>=2)
return;
ll z=0;
for (ll i=1;i<=n;i++)
if (!ru[i])
z=i;
if (cnt)
{
for (ll ca=1;ca<=2;ca++)
for (ll i=1;i<=n;i++)
{
if (ru[a[x][i]]==2)
f[i]|=f[z];
}
return;
}
for (ll i=1;i<=n;i++)
vis[i]=0;
for (ll i=1;i<=n;i++)
if (!vis[i])
dfs(x,i);
return;
}
void sol()
{
cin>>n>>m>>q;
for (ll i=1;i<=n;i++)
for (ll j=0;j<N;j++)
f[i][j]=(i==j);
for (ll i=1;i<=m;i++)
{
string s;
cin>>s;
for (ll j=1;j<=n;j++)
a[i][j]=ask(s[j*2-2],s[j*2-1]);
}
/*printf("A=\n");
for (ll i=1;i<=m;i++)
{
for (ll j=1;j<=n;j++)
printf("%d ",a[i][j]);
printf("\n");
}*/
for (ll i=1;i<=q;i++)
{
string s;
cin>>s;
ll x=ask(s[0],s[1]),y=ask(s[2],s[3]),z=ask(s[4],s[5]);
t[i]={x,y,z,i};
}
/*printf("T=\n");
for (ll i=1;i<=q;i++)
printf("%d %d %d %d\n",t[i].a,t[i].b,t[i].c,t[i].id);*/
sort(t+1,t+q+1);
ll x=0;
for (ll i=1;i<=q;i++)
{
while (x<t[i].c) go(++x);
if (f[t[i].a][t[i].b]) ans[t[i].id]=1;
else ans[t[i].id]=0;
}
for (ll i=1;i<=q;i++)
printf("%d",ans[i]);
printf("\n");
return;
}
int main()
{
IOS
ll tt=1;
cin>>tt;
while (tt--)
sol();
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 7864kb
input:
2 5 2 4 0305040201 0404040404 030300 020500 050102 020501 6 2 4 030603010601 010203060504 030202 060402 050602 060401
output:
1011 0100
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 0ms
memory: 7808kb
input:
1 3 3 6 020202 030301 030201 020102 030203 010201 010303 020303 010202
output:
010101
result:
ok single line: '010101'
Test #3:
score: -100
Wrong Answer
time: 93ms
memory: 8256kb
input:
200 10 10 5000 01060:04020305080709 0103070:060204050908 09070503080401060:02 050308010204090:0607 03010502040607080:09 03080109020504060:07 06050:09040302080107 07080305010409060:02 030809010:0204060507 0:060908070201050304 060700 090:03 09080: 070405 010703 0:0100 080601 030600 070206 0:0:09 08040...
output:
011110001101101111111111111111110101111111110111011110110110111011010101111111111111111101111111111110111111110111111111111101111111111110111111111111111111110001100111111111111111111111111011101111111111111111111111111111111111111111011011110100111110111111110111111100111111101110111111111101111110...
result:
wrong answer 1st lines differ - expected: '011110001101101111111111111111...1111111111111111101111111111111', found: '011110001101101111111111111111...1111111111111111101111111111111'