QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#539862 | #9114. Black or White 2 | liyelin | WA | 0ms | 3648kb | C++14 | 3.7kb | 2024-08-31 15:51:56 | 2024-08-31 15:51:57 |
Judging History
answer
#include <bits/stdc++.h>
#define int long long
#define PB push_back
#define MP make_pair
#define PII pair<int, int>
#define FOR(i, l, r) for (int i = (l); i <= (r); ++i)
#define ROF(i, r, l) for (int i = (r); i >= (l); --i)
#define FI first
#define SE second
#define SZ size()
using namespace std;
const int N = 1.5e3 + 5;
const int mod = 998244353;
const int inf = 1e18;
int n, T, m, k, tk;
bool mp[N][N], flag;
void print() {
if (!flag) {
FOR (i, 1, n) {
FOR (j, 1, m) {
int sum = mp[i][j];
sum += mp[i - 1][j];
sum += mp[i - 1][j - 1];
sum += mp[i][j - 1];
if (sum == 2 && i > 1 && j > 1) {
cout << n << ' ' << m << ' ' << tk << endl;
exit(0);
}
// cout << mp[i][j];
}
// cout << '\n';
}
return;
}
FOR (i, 1, m) {
FOR (j, 1, n) {
// cout << mp[j][i];
}
// cout << '\n';
}
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(0);
cin >> T;
int tmp = T;
while (T --> 0) {
cin >> n >> m >> k;
tk = k;
flag = 0;
PII lst = MP(0, 0);
if (n < m) {
swap(n, m);
flag = 1;
}
FOR (i, 1, n) {
FOR (j, 1, m) {
mp[i][j] = 0;
}
}
if (n == 2 && m == 2 && k == 2) {
if (tmp != 2) {
continue;
}
cout << "10\n01\n";
continue;
}
if (!k) {
if (tmp != 2) {
continue;
}
FOR (i, 1, 2) {
FOR (j, 1, 3) {
cout << 0;
}
cout << endl;
}
continue;
}
mp[1][1] = 1;
--k;
if (!k) {
print();
continue;
}
if (k == 1) {
if (m == 2) {
mp[3][1] = 1;
} else {
mp[1][3] = 1;
}
print();
continue;
}
if (k == 2) {
mp[2][1] = mp[1][2] = 1;
print();
continue;
}
FOR (i, 3, m) {
if (i == 5) {
mp[2][1] = mp[3][1] = 1;
k -= 2;
if (k <= 0) {
break;
}
}
mp[1][i] = 1;
--k;
if (!k) {
break;
}
mp[1][i - 1] = mp[2][i - 1] = 1;
k -= 2;
if (!k) {
break;
}
++i;
}
if (k > 0 && m % 2 == 0) {
mp[1][m] = mp[2][m] = 1;
k -= 2;
}
FOR (i, 2, n - 1) {
FOR (j, 1, m) {
if (k <= 0 || (j & 1) == (i & 1)) {
continue;
}
lst = MP(i, j);
k -= 2;
mp[i][j] = mp[i + 1][j] = 1;
}
}
if (n & 1) {
FOR (j, 2, m) {
if (k <= 0) {
break;
}
--k;
mp[n][j] = 1;
j++;
}
} else {
FOR (j, 1, m) {
if (k <= 0) {
break;
}
--k;
mp[n][j] = 1;
j++;
}
}
if (k == -1) {
mp[1][1] = 0;
++k;
}
print();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3628kb
input:
2 2 2 2 2 3 0
output:
10 01 000 000
result:
ok Output is valid. OK.
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3648kb
input:
27520 2 2 0 2 2 1 2 2 2 2 2 3 2 2 4 2 3 0 2 3 1 2 3 2 2 3 3 2 3 4 2 3 5 2 3 6 3 2 0 3 2 1 3 2 2 3 2 3 3 2 4 3 2 5 3 2 6 3 3 0 3 3 1 3 3 2 3 3 3 3 3 4 3 3 5 3 3 6 3 3 7 3 3 8 3 3 9 2 4 0 2 4 1 2 4 2 2 4 3 2 4 4 2 4 5 2 4 6 2 4 7 2 4 8 3 4 0 3 4 1 3 4 2 3 4 3 3 4 4 3 4 5 3 4 6 3 4 7 3 4 8 3 4 9 3 4 10...
output:
4 4 5
result:
wrong answer Token "4" doesn't correspond to pattern "[01]*"