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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#539847#9114. Black or White 2liyelinWA 114ms3648kbC++143.1kb2024-08-31 15:49:542024-08-31 15:49:57

Judging History

你现在查看的是最新测评结果

  • [2024-08-31 15:49:57]
  • 评测
  • 测评结果:WA
  • 用时:114ms
  • 内存:3648kb
  • [2024-08-31 15:49:54]
  • 提交

answer

#include <bits/stdc++.h>
#define int long long
#define PB push_back
#define MP make_pair
#define PII pair<int, int>
#define FOR(i, l, r) for (int i = (l); i <= (r); ++i)
#define ROF(i, r, l) for (int i = (r); i >= (l); --i)
#define FI first
#define SE second
#define SZ size()
using namespace std;
const int N = 1.5e3 + 5;
const int mod = 998244353;
const int inf = 1e18;
int n, T, m, k, tk;
bool mp[N][N], flag;
void print() {
    if (!flag) {
        FOR (i, 1, n) {
            FOR (j, 1, m) {
                cout << mp[i][j];
            }
            cout << '\n';
        }
        return;
    }
    FOR (i, 1, m) {
        FOR (j, 1, n) {
            cout << mp[j][i];
        }
        cout << '\n';
    }
}
signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin >> T;
    int tmp = T;
    while (T --> 0) {
        cin >> n >> m >> k;
        tk = k;
        flag = 0;
        PII lst = MP(0, 0);
        if (n < m) {
            swap(n, m);
            flag = 1;
        }
        FOR (i, 1, n) {
            FOR (j, 1, m) {
                mp[i][j] = 0;
            }
        }
        if (n == 2 && m == 2 && k == 2) {
            cout << "10\n01\n";
            continue;
        }
        if (!k) {
            print();
            continue;
        }
        mp[1][1] = 1;
        --k;
        if (!k) {
            print();
            continue;
        }
        if (k == 1) {
            if (m == 2) {
                mp[3][1] = 1;
            } else {
                mp[1][3] = 1;
            }
            print();
            continue;
        }
        if (k == 2) {
            mp[2][1] = mp[1][2] = 1;
            print();
            continue;
        }
        FOR (i, 3, m) {
            if (i == 5) {
                mp[2][1] = mp[3][1] = 1;
                k -= 2;
                if (k <= 0) {
                    break;
                }
            } 
            mp[1][i] = 1;
            --k;
            if (!k) {
                break;
            }
            mp[1][i - 1] = mp[2][i - 1] = 1;
            k -= 2;
            if (!k) {
                break;
            }
            ++i;
        }
        if (k > 0 && m % 2 == 0) {
            mp[1][m] = mp[2][m] = 1;
            k -= 2;
        }
        FOR (i, 2, n - 1) {
            FOR (j, 1, m) {
                if (k <= 0 || (j & 1) == (i & 1)) {
                    continue;
                }
                lst = MP(i, j);
                k -= 2;
                mp[i][j] = mp[i + 1][j] = 1;
            }
        }
        if (n & 1) {
            FOR (j, 2, m) {
                if (k <= 0) {
                    break;
                }
                --k;
                mp[n][j] = 1;
                j++;
            }
        } else {
            FOR (j, 1, m) {
                if (k <= 0) {
                    break;
                }
                --k;
                mp[n][j] = 1;
                j++;
            }
        }
        if (k == -1) {
            mp[1][1] = 0;
            ++k;
        }
        print();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3620kb

input:

2
2 2 2
2 3 0

output:

10
01
000
000

result:

ok Output is valid. OK.

Test #2:

score: -100
Wrong Answer
time: 114ms
memory: 3648kb

input:

27520
2 2 0
2 2 1
2 2 2
2 2 3
2 2 4
2 3 0
2 3 1
2 3 2
2 3 3
2 3 4
2 3 5
2 3 6
3 2 0
3 2 1
3 2 2
3 2 3
3 2 4
3 2 5
3 2 6
3 3 0
3 3 1
3 3 2
3 3 3
3 3 4
3 3 5
3 3 6
3 3 7
3 3 8
3 3 9
2 4 0
2 4 1
2 4 2
2 4 3
2 4 4
2 4 5
2 4 6
2 4 7
2 4 8
3 4 0
3 4 1
3 4 2
3 4 3
3 4 4
3 4 5
3 4 6
3 4 7
3 4 8
3 4 9
3 4 10...

output:

00
00
10
00
10
01
11
10
11
11
000
000
100
000
101
000
110
100
011
110
111
110
111
111
00
00
00
10
00
00
10
00
10
11
10
00
01
11
10
11
11
10
11
11
11
000
000
000
100
000
000
101
000
000
110
100
000
111
010
000
011
110
100
111
110
100
011
111
101
111
111
101
111
111
111
0000
0000
1000
0000
1010
0000
1...

result:

wrong answer Output doesn't minimize loss.