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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#539233#9114. Black or White 2Max_FWLTL 0ms19456kbC++141.0kb2024-08-31 14:19:292024-08-31 14:19:29

Judging History

你现在查看的是最新测评结果

  • [2024-08-31 14:19:29]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:19456kb
  • [2024-08-31 14:19:29]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

const int N = 2010;
int T, n, m, k, fl1 = 0, fl2 = 0, a[N][N];
int row;

void Solve(){
	memset(a, 0, sizeof(a));
	
	cin >> n >> m >> k;
	
	fl1 = fl2 = 0;
	if (n < m){
		swap(n, m);
		fl1 = 1;
	}
	if (k > ((n * m) >> 1)){
		k = n * m - k;
		fl2 = 1;
	}
	
	for (int i = 1; i <= m; i += 2){
		if (!k)
			break;
		
		a[1][i] = 1;
		k--;
	}
	
	for (int i = 2; i <= n; i++){
		if (k < m)
			break;
		
		for (int j = 1; j <= m; j += 2)
			a[i][j] = 1;
		
		for (int j = 2; j <= m; j += 2)
			a[i - 1][j] = 1;
		
		k -= m;
		row = i;
	}
	
	for (int i = 2; i <= m; i += 2){
		if (k < 2)
			break;
		
		a[row][i] = 1;
		a[row + 1][i] = 1;
	}
	
	a[n][m] = k;
	
	for (int i = 1; i <= (fl1 ? m : n); i++){
		for (int j = 1; j <= (fl1 ? n : m); j++)
			cout << ((fl1 ? a[j][i] : a[i][j]) ^ fl2) ;
		cout << endl;
	}
}

signed main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	
	cin >> T;
	
	while (T--)
		Solve();
	
	return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 19456kb

input:

2
2 2 2
2 3 0

output:

10
01
000
000

result:

ok Output is valid. OK.

Test #2:

score: -100
Time Limit Exceeded

input:

27520
2 2 0
2 2 1
2 2 2
2 2 3
2 2 4
2 3 0
2 3 1
2 3 2
2 3 3
2 3 4
2 3 5
2 3 6
3 2 0
3 2 1
3 2 2
3 2 3
3 2 4
3 2 5
3 2 6
3 3 0
3 3 1
3 3 2
3 3 3
3 3 4
3 3 5
3 3 6
3 3 7
3 3 8
3 3 9
2 4 0
2 4 1
2 4 2
2 4 3
2 4 4
2 4 5
2 4 6
2 4 7
2 4 8
3 4 0
3 4 1
3 4 2
3 4 3
3 4 4
3 4 5
3 4 6
3 4 7
3 4 8
3 4 9
3 4 10...

output:

00
00
10
00
10
01
01
11
11
11
000
000
100
000
100
001
110
100
011
110
011
111
111
111
00
00
00
10
00
00
10
00
01
11
10
00
01
11
10
01
11
11
11
11
11
000
000
000
100
000
000
101
000
000
101
000
001
101
010
012
010
101
103
010
111
110
010
111
111
011
111
111
111
111
111
0000
0000
1000
0000
1000
0001
1...

result: