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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#537227 | #9114. Black or White 2 | Insert_Username_Here | WA | 108ms | 3728kb | C++20 | 1.0kb | 2024-08-29 23:53:40 | 2024-08-29 23:53:41 |
Judging History
answer
#include <bits/stdc++.h>
#define f first
#define s second
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pii;
// const ll mod = 1e9 + 7;
// #include <brawlstars>
// FOR PAIN OR FOR GLORYYY ELLL PRIMOOOOOO
const int N = 1501;
int ans[N][N];
signed main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t, tringle[1501];
tringle[0] = 0;
for(int i = 1; i < 1501; i++) tringle[i] = tringle[i - 1] + i;
cin >> t;
while(t--) {
int n, m, k, flip = 0, cur = 0;
cin >> n >> m >> k;
if(k * 2 > n * m) k = n * m - k, flip = 1;
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) ans[i][j] = 0;
}
for(int i = 0; i < m; i += 2) {
if(cur == k) break;
ans[0][i] = 1, cur++;
}
for(int i = 1; i < n; i++) {
for(int j = i % 2; j < m; j += 2) {
if(cur + 2 > k) break;
ans[i - 1][j] = ans[i][j] = 1;
cur += 2;
}
}
if(k - cur) ans[n - 1][0] = 1;
for(int i = 0; i < n; i++) {
for(int j = 0; j < m; j++) {
cout << (ans[i][j] ^ flip);
}
cout << "\n";
}
}
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3600kb
input:
2 2 2 2 2 3 0
output:
10 10 000 000
result:
ok Output is valid. OK.
Test #2:
score: -100
Wrong Answer
time: 108ms
memory: 3728kb
input:
27520 2 2 0 2 2 1 2 2 2 2 2 3 2 2 4 2 3 0 2 3 1 2 3 2 2 3 3 2 3 4 2 3 5 2 3 6 3 2 0 3 2 1 3 2 2 3 2 3 3 2 4 3 2 5 3 2 6 3 3 0 3 3 1 3 3 2 3 3 3 3 3 4 3 3 5 3 3 6 3 3 7 3 3 8 3 3 9 2 4 0 2 4 1 2 4 2 2 4 3 2 4 4 2 4 5 2 4 6 2 4 7 2 4 8 3 4 0 3 4 1 3 4 2 3 4 3 3 4 4 3 4 5 3 4 6 3 4 7 3 4 8 3 4 9 3 4 10...
output:
00 00 10 00 10 10 01 11 11 11 000 000 100 000 101 000 101 100 010 111 011 111 111 111 00 00 00 10 00 00 10 00 10 11 01 00 01 11 01 01 11 11 11 11 11 000 000 000 100 000 000 101 000 000 101 000 100 111 010 000 000 101 111 010 111 011 010 111 111 011 111 111 111 111 111 0000 0000 1000 0000 1010 0000 1...
result:
wrong answer Output doesn't minimize loss.