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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#532675 | #9111. Zayin and String | ZYLZPP | TL | 0ms | 0kb | C++20 | 2.7kb | 2024-08-25 08:48:29 | 2024-08-25 08:48:30 |
answer
#include<bits/stdc++.h>
using namespace std;
#define For(i, l, r) for (int i = (l); i <= (r); ++i)
typedef long long ll;
typedef long double Lf;
const int N = 1e3 + 5, S = 4e3 + 5, Mo = 998244353;
const Lf eps = 1e-14;
inline int ml(const int &x, const int &y) { return 1ll * x * y % Mo; }
inline void mul(int &x, const int &y) { x = ml(x, y); }
inline int qPow(int a, int b) { int r=1; for (;b;b>>=1,mul(a,a)) if (b&1) mul(r,a); return r; }
template<class C> inline bool cmax(C &x, const C &y) { return y>x? x=y, 1: 0; }
struct IO {
char c; int f;
#define gc() (getchar())
template<class C>
inline IO& operator >> (C &x) {
x = 0; f = 1;
while (!isdigit(c = gc()) && ~c) f |= -!(c ^ 45);
while (isdigit(c)) x = (x << 3) + (x << 1) + (c ^ 48), c = gc();
x *= f; return *this;
}
inline bool operator ~ () { return ~c; }
} io;
int T, n, m, vis[N][S], tim;
Lf f[N][S];
char t[N];
namespace ACAM {
int ch[S][26], tot = 1, fail[S], sum[S];
char s[S];
inline void add(char s[], int x) {
int n = strlen(s + 1), u = 1;
For (i, 1, n) {
int c = s[i] - 'a';
if (!ch[u][c]) ch[u][c] = ++tot;
u = ch[u][c];
}
sum[u] += x;
}
inline void build() {
For (i, 0, 25) ch[0][i] = 1;
queue<int > q; q.push(1);
fail[1] = 0;
while (!q.empty()) {
int u = q.front(); q.pop(); sum[u] += sum[fail[u]];
For (i, 0, 25) (ch[u][i]? q.push(ch[u][i]), fail[ch[u][i]]: ch[u][i]) = ch[fail[u]][i];
}
}
}
using namespace ACAM;
inline bool ok(Lf x) {
f[0][1] = 0; vis[0][1] = ++tim;
For (i, 0, n - 1) For (j, 1, tot) if (vis[i][j] == tim) {
int c = t[i + 1] - 'a', k = ch[j][c];
if (vis[i + 1][j] ^ tim) vis[i + 1][j] = tim, f[i + 1][j] = f[i][j];
else cmax(f[i + 1][j], f[i][j]);
if (vis[i + 1][k] ^ tim) vis[i + 1][k] = tim, f[i + 1][k] = f[i][j] + sum[k] - x;
else cmax(f[i + 1][k], f[i][j] + sum[k] - x);
}
For (i, 1, tot) if (vis[n][i] == tim && f[n][i] > eps) return 1;
return 0;
}
inline void solve() {
For (i, 1, tot) fail[i] = sum[i] = 0, memset(ch[i], 0, sizeof ch[i]);
tot = 1;
io >> n >> m;
scanf("%s", t + 1);
int x;
For (i, 1, m) scanf("%s", s + 1), io >> x, add(s, x);
build();
Lf l = 0, r = 2e8;
while (r - l > eps) {
Lf mid = (l + r) / 2;
if (ok(mid)) l = mid;
else r = mid;
}
For (i, 1, n) {
ll x = round(l * i);
if (fabs(x - l * i) < n * eps) { printf("%d\n", ml(x % Mo, qPow(i, Mo - 2))); return; }
}
}
int main() {
io >> T;
while (T--) solve();
return 0;
}
Details
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Test #1:
score: 0
Time Limit Exceeded
input:
80 4 7 ggeg g 92946 d 65678 gg 50828 wrj 93954 gge 53780 a 94179 geg 40837 5 6 hiiii ii 67984 foh 69185 hi 88153 pj 39431 i 32219 wfmve 96834 8 12 wvxxvwww xw 1522 rzl 16262 wx 77596 v 69622 vw 82225 nykkmkv 19236 xv 83470 o 16781 w 2405 m 98319 ww 13889 qggbvty 16331 8 14 jjjiiijh i 96670 z 74397 i...