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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#511011 | #3403. Crossing Rivers | PetroTarnavskyi# | AC ✓ | 1ms | 3936kb | C++20 | 855b | 2024-08-09 15:09:28 | 2024-08-09 15:09:29 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;
int n, D;
void solve()
{
db sumL = 0;
db LnaV = 0;
FOR (i, 0, n)
{
db p, l, v;
cin >> p >> l >> v;
sumL += l;
LnaV += 2 * l / v;
}
cout << D - sumL + LnaV << '\n';
}
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout << fixed << setprecision(3);
for (int tc = 1; ; tc++)
{
cin >> n >> D;
if (D == 0)
break;
cout << "Case " << tc << ": ";
solve();
cout << "\n";
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3936kb
input:
0 811 8 860 37 20 15 73 29 22 124 42 2 169 86 25 289 18 9 325 176 28 551 68 13 717 24 16 4 573 203 64 8 272 35 19 386 37 30 457 115 18 6 609 70 37 30 110 96 16 229 79 9 329 126 16 468 76 26 575 27 23 2 717 172 89 19 690 15 17 9 993 0 40 11 71 1 22 144 7 17 198 45 9 260 46 27 324 139 12 652 25 16 765...
output:
Case 1: 811.000 Case 2: 481.216 Case 3: 356.929 Case 4: 223.966 Case 5: 624.133 Case 6: 669.527 Case 7: 501.908 Case 8: 272.857 Case 9: 584.470 Case 10: 460.553
result:
ok 19 lines