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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#50542 | #2281. BnPC | dariusuzumaki | TL | 3ms | 3668kb | C++ | 2.2kb | 2022-09-27 01:55:58 | 2022-09-27 01:56:00 |
Judging History
answer
#include <bits/stdc++.h>
#include <unordered_map>
#include <iostream>
#include <queue>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef unsigned int ui;
typedef double db;
typedef long double ldb;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int, int> ii;
typedef vector<int> vi;
typedef vector<vi> vvi;
#define LI(i, a, b) for (int i = a; i <= b; i++) // forloop inclusive
#define LE(i, a, b) for (int i = a; i < b; i++) // forloop exclusive
#define LBI(i, a, b) for (int i = a; i >= b; i--) // forloop backward inclusive
#define LBE(i, a, b) for (int i = a; i > b; i--) // forloop backward inclusive
#define Min(a, b) ((a) < (b) ? (a) : (b))
#define Max(a, b) ((a) < (b) ? (b) : (a))
void b()
{
ll n, k;
cin >> n >> k;
unordered_map<string, ll> attr;
unordered_map<string, multiset<ll> > challs;
string name;
ll score, res = 0;
LE(i, 0, n)
{
cin >> name >> score;
attr.insert(pair<string, ll >(name, score));
}
cin >> n;
LE(i, 0, n)
{
cin >> name >> score;
challs[name].insert(score);
}
for(auto &a : challs) {
k -= (*a.second.rbegin() - attr[a.first] > 0) ? *a.second.rbegin() - attr[a.first] : 0;
if (k < 0) {
cout << 0 << "\n";
return;
}
attr[a.first] = Max(attr[a.first], *a.second.rbegin());
if (*a.second.rbegin() < attr[a.first])
{
res += attr[a.first] * a.second.size();
continue;
}
res += attr[a.first] * distance(a.second.begin(), a.second.find(attr[a.first]));
}
while (k--)
{
ll h = 0;
string attribute;
for (auto a : attr)
{
ll old_score = (a.second) * distance(challs[a.first].begin(), challs[a.first].find(attr[a.first]));
ll np = res - old_score + (a.second + 1) * challs[a.first].size();
if (h < np)
{
h = np;
attribute = a.first;
}
}
attr[attribute]++;
res = h;
}
cout << res << "\n";
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0);
b();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3568kb
input:
3 14 THISISTHEONE 8 B 0 C 0 8 THISISTHEONE 10 C 0 B 1 B 0 THISISTHEONE 0 C 1 THISISTHEONE 0 THISISTHEONE 0
output:
82
result:
ok single line: '82'
Test #2:
score: 0
Accepted
time: 3ms
memory: 3620kb
input:
3 99 THEFIRSTINCREASE 6 SECONDINCREASE 4 ZZZ 1 9 THEFIRSTINCREASE 4 ZZZ 0 THEFIRSTINCREASE 6 SECONDINCREASE 8 THEFIRSTINCREASE 2 SECONDINCREASE 1 ZZZ 0 SECONDINCREASE 8 THEFIRSTINCREASE 3
output:
429
result:
ok single line: '429'
Test #3:
score: 0
Accepted
time: 2ms
memory: 3668kb
input:
5 20 A 100 B 200 C 300 D 400 E 500 949 A 39 A 23 C 163 A 98 B 36 A 3 A 52 B 152 B 167 B 65 C 142 B 66 B 117 C 288 C 155 E 341 A 97 D 173 E 31 A 62 D 90 E 361 A 42 D 85 E 1 C 141 B 77 B 194 D 221 E 203 D 345 E 48 B 26 D 46 B 74 E 380 B 181 C 243 B 112 A 99 E 403 C 20 E 453 C 149 B 26 E 245 A 74 D 304...
output:
285180
result:
ok single line: '285180'
Test #4:
score: 0
Accepted
time: 2ms
memory: 3644kb
input:
2 1 A 10 B 12 3 A 10 B 10 B 10
output:
35
result:
ok single line: '35'
Test #5:
score: 0
Accepted
time: 2ms
memory: 3624kb
input:
1 1 OVERENTHUSIASTICNESS 41 1 OVERENTHUSIASTICNESS 0
output:
42
result:
ok single line: '42'
Test #6:
score: -100
Time Limit Exceeded
input:
100000 1000000000 A 1000000000 B 1000000000 C 1000000000 D 1000000000 E 1000000000 F 1000000000 G 1000000000 H 1000000000 I 1000000000 J 1000000000 K 1000000000 L 1000000000 M 1000000000 N 1000000000 O 1000000000 P 1000000000 Q 1000000000 R 1000000000 S 1000000000 T 1000000000 U 1000000000 V 1000000...