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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#503019#8527. Power Divisionsucup-team4435#WA 1ms5644kbC++207.1kb2024-08-03 15:52:002024-08-03 15:52:01

Judging History

你现在查看的是最新测评结果

  • [2024-08-03 15:52:01]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:5644kb
  • [2024-08-03 15:52:00]
  • 提交

answer

#include "bits/stdc++.h"

#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep1(i, n) for (int i = 1; i < (n); ++i)
#define rep1n(i, n) for (int i = 1; i <= (n); ++i)
#define repr(i, n) for (int i = (n) - 1; i >= 0; --i)
#define pb push_back
#define eb emplace_back
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define each(x, a) for (auto &x : a)
#define ar array
#define vec vector
#define range(i, n) rep(i, n)

using namespace std;

using ll = long long;
using ull = unsigned long long;
using ld = double;
using str = string;
using pi = pair<int, int>;
using pl = pair<ll, ll>;

using vi = vector<int>;
using vl = vector<ll>;
using vpl = vector<pl>;
using vpi = vector<pair<int, int>>;
using vvi = vector<vi>;

int Bit(int mask, int b) { return (mask >> b) & 1; }

template<class T>
bool ckmin(T &a, const T &b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}

template<class T>
bool ckmax(T &a, const T &b) {
    if (b > a) {
        a = b;
        return true;
    }
    return false;
}

const int INFi = 2e9;
const ll INF = 2e18;

template<typename T>
int normalize(T value, int mod) {
    if (value < -mod || value >= 2 * mod) value %= mod;
    if (value < 0) value += mod;
    if (value >= mod) value -= mod;
    return value;
}

template<int mod>
struct static_modular_int {
    using mint = static_modular_int<mod>;

    int value;

    static_modular_int() : value(0) {}

    static_modular_int(const mint &x) : value(x.value) {}

    template<typename T, typename U = std::enable_if_t<std::is_integral<T>::value>>
    static_modular_int(T value) : value(normalize(value, mod)) {}

    template<typename T>
    mint power(T degree) const {
        degree = normalize(degree, mod - 1);
        mint prod = 1, a = *this;
        for (; degree > 0; degree >>= 1, a *= a)
            if (degree & 1)
                prod *= a;

        return prod;
    }

    mint inv() const {
        return power(-1);
    }

    mint &operator=(const mint &x) {
        value = x.value;
        return *this;
    }

    mint &operator+=(const mint &x) {
        value += x.value;
        if (value >= mod) value -= mod;
        return *this;
    }

    mint &operator-=(const mint &x) {
        value -= x.value;
        if (value < 0) value += mod;
        return *this;
    }

    mint &operator*=(const mint &x) {
        value = int64_t(value) * x.value % mod;
        return *this;
    }

    mint &operator/=(const mint &x) {
        return *this *= x.inv();
    }

    friend mint operator+(const mint &x, const mint &y) {
        return mint(x) += y;
    }

    friend mint operator-(const mint &x, const mint &y) {
        return mint(x) -= y;
    }

    friend mint operator*(const mint &x, const mint &y) {
        return mint(x) *= y;
    }

    friend mint operator/(const mint &x, const mint &y) {
        return mint(x) /= y;
    }

    mint &operator++() {
        ++value;
        if (value == mod) value = 0;
        return *this;
    }

    mint &operator--() {
        --value;
        if (value == -1) value = mod - 1;
        return *this;
    }

    mint operator++(int) {
        mint prev = *this;
        value++;
        if (value == mod) value = 0;
        return prev;
    }

    mint operator--(int) {
        mint prev = *this;
        value--;
        if (value == -1) value = mod - 1;
        return prev;
    }

    mint operator-() const {
        return mint(0) - *this;
    }

    bool operator==(const mint &x) const {
        return value == x.value;
    }

    bool operator!=(const mint &x) const {
        return value != x.value;
    }

    bool operator<(const mint &x) const {
        return value < x.value;
    }

    template<typename T>
    explicit operator T() {
        return value;
    }

    friend std::istream &operator>>(std::istream &in, mint &x) {
        std::string s;
        in >> s;
        x = 0;
        for (const auto c: s)
            x = x * 10 + (c - '0');

        return in;
    }

    friend std::ostream &operator<<(std::ostream &out, const mint &x) {
        return out << x.value;
    }

    static int primitive_root() {
        if constexpr (mod == 1'000'000'007) return 5;
        if constexpr (mod == 998'244'353) return 3;
        if constexpr (mod == 786433) return 10;

        static int root = -1;
        if (root != -1)
            return root;

        std::vector<int> primes;
        int value = mod - 1;
        for (int i = 2; i * i <= value; i++)
            if (value % i == 0) {
                primes.push_back(i);
                while (value % i == 0)
                    value /= i;
            }

        if (value != 1) primes.push_back(value);
        for (int r = 2;; r++) {
            bool ok = true;
            for (auto p: primes) {
                if ((mint(r).power((mod - 1) / p)).value == 1) {
                    ok = false;
                    break;
                }
            }
            if (ok) return root = r;
        }
    }
};

constexpr int MOD = 1'000'000'007;
// constexpr int MOD = 998'244'353;
using mint = static_modular_int<MOD>;


const int N = 3e5 + 5;
int a[N];
mint dp[N];

struct MySet {
    set<int> q;

    void Add(int x) {
        auto it = q.lower_bound(x);
        while (it != q.end()) {
            if (*it > x) break;
            it = q.erase(it);
            x++;
        }
        q.insert(x);
    }
};

void rec(int l, int r) {
    if (l == r) return;
    if (l + 1 == r) {
        dp[r] += dp[l];
        return;
    }
    int mid = (l + r) / 2;
    rec(l, mid);
    {
        // left >= right
        MySet L, S;
        int ri = mid;
        for(int li = mid - 1; li >= l; --li) {
            L.Add(a[li]);
            S.Add(a[li]);

            int high = *L.q.rbegin();
            while (ri < r && *S.q.rbegin() < high + 1) {
                S.Add(a[ri++]);
            }
            if (S.q.size() != 1 || *S.q.rbegin() != high + 1) {
                continue;
            }
            dp[ri] += dp[li];
        }
    }
    {
        // left < right
        MySet R, S;
        int li = mid - 1;
        S.Add(a[li]);
        for(int ri = mid; ri < r; ++ri) {
            R.Add(a[ri]);
            S.Add(a[ri]);

            int high = *R.q.rbegin();
            while (li > l && *S.q.rbegin() < high + 1) {
                S.Add(a[--li]);
            }
            if (S.q.size() != 1 || *S.q.rbegin() != high + 1 || R.q.size() == 1) {
                continue;
            }
            dp[ri + 1] += dp[li];
        }
    }
    rec(mid, r);
}

void solve() {
    int n;
    cin >> n;
    rep(i, n) cin >> a[i];
    dp[0] = 1;
    rec(0, n);
    cout << dp[n] << '\n';
}

signed main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    cout << setprecision(15) << fixed;

    int t = 1;
//    cin >> t;

    rep(_, t) {
        solve();
    }

    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 5644kb

input:

5
2 0 0 1 1

output:

6

result:

ok 1 number(s): "6"

Test #2:

score: 0
Accepted
time: 1ms
memory: 4764kb

input:

1
0

output:

1

result:

ok 1 number(s): "1"

Test #3:

score: 0
Accepted
time: 0ms
memory: 4700kb

input:

2
1 1

output:

2

result:

ok 1 number(s): "2"

Test #4:

score: 0
Accepted
time: 1ms
memory: 4924kb

input:

3
2 1 1

output:

3

result:

ok 1 number(s): "3"

Test #5:

score: 0
Accepted
time: 0ms
memory: 4784kb

input:

4
3 2 2 3

output:

4

result:

ok 1 number(s): "4"

Test #6:

score: 0
Accepted
time: 0ms
memory: 4764kb

input:

5
3 4 4 2 4

output:

2

result:

ok 1 number(s): "2"

Test #7:

score: -100
Wrong Answer
time: 1ms
memory: 4776kb

input:

7
3 4 3 5 6 3 4

output:

4

result:

wrong answer 1st numbers differ - expected: '6', found: '4'