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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#489190#5. 在线 O(1) 逆元qwef_70 1566ms515504kbC++23563b2024-07-24 18:52:032024-07-24 18:52:03

Judging History

This is a historical verdict posted at 2024-07-24 18:52:03.

  • [2024-11-05 22:02:31]
  • 管理员手动重测本题所有提交记录
  • Verdict: 60
  • Time: 4395ms
  • Memory: 515536kb
  • [2024-07-24 18:52:03]
  • Judged
  • Verdict: 70
  • Time: 1566ms
  • Memory: 515504kb
  • [2024-07-24 18:52:03]
  • Submitted

answer

//#include <bits/stdc++.h>
#include "inv.h"
typedef long long ll;
const int N=1.31e8+114,p=998244353;
int a[N];
inline void add(int& a,int b){a=(a+b>=p?a+b-p:a+b);}
void init(int _){
	a[1]=1;
	for(int i=2;i<N;++i) a[i]=(ll)(p-p/i)*a[p%i]%p;
}
int inv(int x){
	for(int i=1,j=x;;++i,add(j,x))
		if(j<N){
			int k=0,o=a[j];
			do{
				if(i&1) add(k,o);
				o=(o>=499122177?o+o-p:o+o);
			}while(i>>=1);
			return k;
		}
}
//int main(){
//	init(998244353);
//	int x;
//	std::cin >> x;
//	std::cout << query(x) << std::endl;
//	return 0;
//}

Details


Pretests


Final Tests

Test #1:

score: 30
Accepted
time: 809ms
memory: 515404kb

Test #2:

score: 40
Accepted
time: 1566ms
memory: 515504kb

Test #3:

score: 0
Time Limit Exceeded