#pragma GCC optimize ("Ofast")
#pragma GCC optimize ("unroll-loops")

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

const int MAXN = 6000;
const int INF = 1e9;

template<int MOD>
struct mint
{
    int x;
    mint() : x(0) {}
    mint(int _x) : x(_x) {}
    mint operator + (int ot) const { return x+ot>=MOD ? x+ot-MOD : x+ot; }
    mint operator - (int ot) const { return x<ot ? x+MOD-ot : x-ot; }
    mint operator - () const { return x ? MOD-x : 0; }
    mint operator * (int ot) const { return 1ll*x*ot%MOD; }
    mint operator += (int ot) { return *this = *this + ot; }
    mint operator -= (int ot) { return *this = *this - ot; }
    mint operator *= (int ot) { return *this = *this * ot; }
    operator int() const { return x; }
    bool operator < (int ot) const { return x<ot; }
};

template<int MOD>
mint<MOD> mpow(mint<MOD> a, ll b)
{
    mint<MOD> ret=1;
    while(b)
    {
        if(b&1) ret*=a;
        b>>=1; a=a*a;
    }
    return ret;
}
template<int MOD>
mint<MOD> inv(mint<MOD> a) { return mpow<MOD>(a, MOD-2); }

const int MOD1 = 1e9+7;
const int MOD2 = 998244353;
const int P1 = 3;
const int P2 = 7;

typedef pair<mint<MOD1>, mint<MOD2>> pmm;

pmm operator + (const pmm &p, const pmm &q) { return {p.first+q.first, p.second+q.second}; }
pmm operator - (const pmm &p, const pmm &q) { return {p.first-q.first, p.second-q.second}; }
pmm operator * (const pmm &p, const pmm &q) { return {p.first*q.first, p.second*q.second}; }
pmm operator - (const pmm &p) { return {-p.first, -p.second}; }
pmm& operator += (pmm &p, const pmm &q) { p=p+q; return p; }
pmm& operator -= (pmm &p, const pmm &q) { p=p-q; return p; }
pmm& operator *= (pmm &p, const pmm &q) { p=p*q; return p; }
pmm mpow(pmm a, ll b) { return {mpow(a.first, b), mpow(a.second, b)}; }
pmm inv(pmm a) { return {inv(a.first), inv(a.second)}; }

int N, A[MAXN+10], B[MAXN+10];
pmm PP[MAXN+10], IP[MAXN+10];
pmm HA[MAXN+10], HB[MAXN+10];
int ans=INF;

int main()
{
    ios_base::sync_with_stdio(false); cin.tie(NULL);
    
    scanf("%d", &N);
    for(int i=1; i<=N; i++) scanf("%d", &A[i]);
    for(int i=1; i<=N; i++) scanf("%d", &B[i]);
    
    {
        vector<int> VA, VB;
        for(int i=1; i<=N; i++) VA.push_back(A[i]);
        for(int i=1; i<=N; i++) VB.push_back(B[i]);
        sort(VA.begin(), VA.end());
        sort(VB.begin(), VB.end());
        if(VA!=VB) return !printf("-1\n");
    }

    if(N==1) return !printf("0\n");
    for(int i=1; i<=N; i++) A[i+N]=A[i], B[i+N]=B[i];

    PP[0]={1, 1}; IP[0]={1, 1};
    PP[1]={P1, P2}; IP[1]=inv(PP[1]);
    for(int i=2; i<=N+N; i++) PP[i]=PP[i-1]*PP[1];
    for(int i=2; i<=N+N; i++) IP[i]=IP[i-1]*IP[1];

    for(int i=1; i<=N+N; i++) HA[i]=HA[i-1]+PP[i]*pmm{A[i], A[i]};
    for(int i=1; i<=N+N; i++) HB[i]=HB[i-1]+PP[i]*pmm{B[i], B[i]};

    vector<pair<pmm, int>> V4;
    for(int i=1; i<N; i++) V4.push_back({(HA[N-1]-HA[i-1])*IP[i-1] + HA[i-1]*PP[N-i], i});
    sort(V4.begin(), V4.end());

    for(int cyc=0; cyc<N; cyc++)
    {
        vector<pair<pmm, int>> V, V2, V3;

        for(int i=1; i<=N; i++) if(B[i+cyc]==A[cyc+1] || B[i+cyc]==A[cyc+N]) V.push_back({(HB[cyc+i-1]-HB[cyc])*IP[cyc]+(HB[cyc+N]-HB[cyc+i])*IP[cyc+1], cyc+i});
        for(int i=2; i<=N; i++) V2.push_back({(HA[cyc+N]-HA[cyc+i-1])*IP[cyc+i-1] + (HA[cyc+i-1]-HA[cyc+1])*IP[cyc]*PP[N-i], cyc+i});
        V3=V4;

        sort(V.begin(), V.end());
        sort(V2.begin(), V2.end());

        for(int l=0, r, j=0; l<V2.size(); l=r)
        {
            for(r=l; r<V2.size() && V2[r].first==V2[l].first; r++);
            int val=INF;
            for(; j<V.size() && V[j].first<=V2[l].first; j++) if(V[j].first==V2[l].first) val=min(val, V[j].second);
            if(val!=INF) for(int i=l; i<r; i++) ans=min(ans, (V2[i].second-2-cyc)*N+val-1-cyc);
        }
        for(int l=0, r, j=0; l<V3.size(); l=r)
        {
            for(r=l; r<V3.size() && V3[r].first==V3[l].first; r++);
            int val=0;
            for(; j<V.size() && V[j].first<=V3[l].first; j++) if(V[j].first==V3[l].first) val=max(val, V[j].second);
            if(val!=0) for(int i=l; i<r; i++) ans=min(ans, (N+cyc-V3[i].second)%(N-1)*N+N+cyc-val);
        }
        V4=V2;
    }

    if(ans==INF) printf("-1\n");
    else printf("%d\n", ans);
}