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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#478239#4398. Luxury cruise shiphorzward#AC ✓4ms10936kbC++171.2kb2024-07-14 19:27:062024-07-14 19:27:06

Judging History

你现在查看的是最新测评结果

  • [2024-07-14 19:27:06]
  • 评测
  • 测评结果:AC
  • 用时:4ms
  • 内存:10936kb
  • [2024-07-14 19:27:06]
  • 提交

answer

/*
|----|   |----|
|    |   |    |
|    ----|    |
|             |
|    ----|    |
|    |   |    |
|----|   |----|

*/

#include <bits/stdc++.h>
#define int long long
#define fastio ios::sync_with_stdio(0), cin.tie(0)

using namespace std;

const int inf = 1e18;
const int N = 1e6;
vector<int> dp(N, inf);
int x[] = {7, 31, 365};

void solve()
{
    int n;
    cin >> n;
    dp[0] = 0;
    for(int i = 0; i < 3; i++) {
        for(int j = 0; j < N; j++) {
            if(j - x[i] >= 0) dp[j] = min(dp[j], dp[j - x[i]] + 1);
        }
    }
    while(n--) {
        int now = 0;
        cin >> now;
        // 處理now < N的狀況
        if(now < N) {
            cout << (dp[now] == inf ? -1 : dp[now]) << '\n';
        }
        else {
            int tmp = now - N;
            tmp = (tmp % 365 == 0 ? tmp / 365 : tmp / 365 + 1);
            int after = now - tmp * 365;
            cout << (dp[after] == inf ? -1 : tmp + dp[after]) << '\n';
        }
    }
    return;
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int t = 1;
    // cin >> t;
    while(t--)
    {
        solve();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 4ms
memory: 10936kb

input:

1000
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101...

output:

-1
-1
-1
-1
-1
-1
1
-1
-1
-1
-1
-1
-1
2
-1
-1
-1
-1
-1
-1
3
-1
-1
-1
-1
-1
-1
4
-1
-1
1
-1
-1
-1
5
-1
-1
2
-1
-1
-1
6
-1
-1
3
-1
-1
-1
7
-1
-1
4
-1
-1
-1
8
-1
-1
5
-1
-1
2
9
-1
-1
6
-1
-1
3
10
-1
-1
7
-1
-1
4
11
-1
-1
8
-1
-1
5
12
-1
-1
9
-1
-1
6
13
-1
3
10
-1
-1
7
14
-1
4
11
-1
-1
8
15
-1
5
12
-1
-...

result:

ok 1000 lines