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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#468719#1899. Maximaze XOR sumbinminh01WA 0ms4024kbC++238.5kb2024-07-08 23:34:262024-07-08 23:34:27

Judging History

你现在查看的是最新测评结果

  • [2024-07-08 23:34:27]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:4024kb
  • [2024-07-08 23:34:26]
  • 提交

answer

#include<bits/allocator.h>
#pragma GCC optimize("Ofast,unroll-loops")
#ifdef ONLINE_JUDGE
#pragma GCC target("avx2,fma,bmi,bmi2,popcnt,lzcnt")
#endif
 
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define ull unsigned long long
#define int128 __int128_t
#define double long double
#define gcd __gcd
#define lcm(a, b) ((a)/gcd(a, b)*(b))
#define sqrt sqrtl
#define log2 log2l
#define log10 log10l
#define floor floorl
#define to_string str
#define yes cout << "YES"
#define no cout << "NO"
#define trav(i, a) for (auto &i: (a))
#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define sz(a) (int)a.size()
#define Max(a) *max_element(all(a))
#define Min(a) *min_element(all(a))
#define Find(a, n) (find(all(a), n) - a.begin())
#define Count(a, n) count(all(a), n)
#define Upper(a, n) (upper_bound(all(a), n) - a.begin())
#define Lower(a, n) (lower_bound(all(a), n) - a.begin())
#define next_perm(a) next_permutation(all(a))
#define prev_perm(a) prev_permutation(all(a))
#define sorted(a) is_sorted(all(a))
#define sum(a) accumulate(all(a), 0)
#define sumll(a) accumulate(all(a), 0ll)
#define Sort(a) sort(all(a))
#define Reverse(a) reverse(all(a))
#define Unique(a) Sort(a), (a).resize(unique(all(a)) - a.begin())
#define pb push_back
#define eb emplace_back
#define popcount __builtin_popcount
#define popcountll __builtin_popcountll
#define clz __builtin_clz
#define clzll __buitlin_clzll
#define ctz __builtin_ctz
#define ctzll __builtin_ctzll
#define open(s) freopen(s, "r", stdin)
#define write(s) freopen(s, "w", stdout)
#define fileopen(s) open((string(s) + ".inp").c_str()), write((string(s) + ".out").c_str());
#define For(i, a, b) for (auto i = (a); i < (b); i++)
#define Fore(i, a, b) for (auto i = (a); i >= (b); i--)
#define FOR(i, a, b) for (auto i = (a); i <= (b); i++)
#define ret(s) return void(cout << s);

const int mod = 1e9 + 7, mod2 = 998244353;
const double PI = acos(-1), eps = 1e-9;
const ull npos = string::npos;
const int dx[] = {0, 0, -1, 1}, dy[] = {-1, 1, 0, 0};
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using cd = complex<double>;
mt19937 mt(chrono::system_clock::now().time_since_epoch().count());
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<ll> vll;
typedef vector<vll> vvll;
typedef vector<double> vdo;
typedef vector<vdo> vvdo;
typedef vector<string> vs;
typedef vector<pii> vpair;
typedef vector<vpair> vvpair;
typedef vector<bool> vb;
typedef vector<vb> vvb;
typedef vector<char> vc;
typedef vector<vc> vvc;
typedef vector<cd> vcd;
typedef priority_queue<int> pq;
typedef priority_queue<int, vi, greater<int>> pqg;
typedef priority_queue<ll> pqll;
typedef priority_queue<ll, vll, greater<ll>> pqgll;

ll add(ll a, ll b, int m) {if (a >= m) a%=m;if (b >= m) b%=m;a+=b;return a >= m ? a - m: a;}
ll sub(ll a, ll b, int m) {if (a >= m) a%=m;if (b >= m) b%=m;a-=b;return a < 0 ? a + m: a;}
ll mul(ll a, ll b, int m) {if (a >= m) a%=m;if (b >= m) b%=m;return a*b % m;}
ll bin_mul(ll a, ll b, ll m) {if (a >= m) a%=m;if (b >= m) b%=m;ll x = 0;while (b) {if (b & 1) x = (x + a) % m;a = (a + a) % m;b>>=1;}return x;}
ll power(ll a, ll b, int m) {ll x = 1;if (a >= m) a%=m; while (b) {if (b & 1) x = x*a % m;a = a*a % m;b>>=1;}return x;}
ll power(ll a, ll b) {ll x = 1;while (b) {if (b & 1) x = x*a;a = a*a;b>>=1;}return x;}
ll ceil(ll a, ll b) {return (a + b - 1)/b;}
ll to_int(const string &s) {ll x = 0; for (int i = (s[0] == '-'); i < sz(s); i++) x = x*10 + s[i] - '0';return x*(s[0] == '-' ? -1: 1);}
bool is_prime(ll n) {if (n < 2) return 0;if (n < 4) return 1;if (n % 2 == 0 || n % 3 == 0) return 0;for (ll i = 5; i*i <= n; i+=6) {if(n % i == 0 || n % (i + 2) == 0) return 0;}return 1;}
bool is_square(ll n) {ll k = sqrt(n); return k*k == n;}
ll factorial(int n) {ll x = 1;for (int i = 2; i <= n; i++) x*=i;return x;}
ll factorial(int n, int m) {ll x = 1;for (ll i = 2; i <= n; i++) x = x*i % m;return x;}
bool is_power(ll n, ll k) {while (n % k == 0) n/=k;return n == 1ll;}
string str(ll n) {if (n == 0) return "0"; string s = ""; bool c = 0; if (n < 0) c = 1, n = -n; while (n) {s+=n % 10 + '0'; n/=10;} if (c) s+='-'; Reverse(s); return s;}
string repeat(const string &s, int n) {if (n < 0) return ""; string x = ""; while (n--) x+=s; return x;}
string bin(ll n) {string s = ""; while (n) {s+=(n & 1) + '0'; n>>=1;} Reverse(s); return s;}
void sieve(vector<bool> &a) {int n = a.size(); a[0] = a[1] = 0; for (int i = 4; i < n; i+=2) a[i] = 0; for (int i = 3; i*i < n; i+=2) {if (a[i]) {for (int j = i*i; j < n; j+=(i << 1)) a[j] = 0;}}}
void sieve(bool a[], int n) {a[0] = a[1] = 0; for (int i = 4; i < n; i+=2) a[i] = 0; for (int i = 3; i*i < n; i+=2) {if (a[i]) {for (int j = i*i; j < n; j+=(i << 1)) a[j] = 0;}}}
void sieve(vector<int> &a) {int n = a.size(); for (int i = 2; i < n; i+=2) a[i] = 2; for (int i = 3; i*i < n; i+=2) {if (!a[i]) {for (int j = i; j < n; j+=(i << 1)) a[j] = i;}} for (int i = 3; i < n; i+=2) {if (!a[i]) a[i] = i;}}
void sieve(int a[], int n) {for (int i = 2; i < n; i+=2) a[i] = 2; for (int i = 3; i*i < n; i+=2) {if (!a[i]) {for (int j = i; j < n; j+=(i << 1)) a[j] = i;}} for (int i = 3; i < n; i+=2) {if (!a[i]) a[i] = i;}}
vector<pii> factorize(int n) {vector<pii> a; for (int i = 2; i*i <= n; i++) {if (n % i == 0) {int k = 0; while (n % i == 0) k++, n/=i; a.emplace_back(i, k);}} if (n > 1) a.emplace_back(n, 1); return a;}
int rand(int l, int r) {return uniform_int_distribution<int>(l, r)(mt);}
int Log2(int n) {return 31 - __builtin_clz(n);}
template<class T> void compress(vector<T> &a) {vector<T> b; for (T &i: a) b.push_back(i); sort(all(b)); b.resize(unique(all(b)) - b.begin()); for (T &i: a) i = lower_bound(all(b), i) - b.begin() + 1;}

template<class A, class B> istream& operator>>(istream& in, pair<A, B> &p) {in >> p.first >> p.second; return in;}
template<class A, class B> ostream& operator<<(ostream& out, const pair<A, B> &p) {out << p.first << ' ' << p.second; return out;}
template<class T> istream& operator>>(istream& in, vector<T> &a) {for (auto &i: a) in >> i; return in;}
template<class T> ostream& operator<<(ostream& out, const vector<T> &a) {for (auto &i: a) out << i << ' '; return out;}
template<class T> istream& operator>>(istream& in, vector<vector<T>> &a) {for (auto &i: a) in >> i; return in;}
template<class T> ostream& operator<<(ostream& out, const vector<vector<T>> &a) {for (auto &i: a) out << i << '\n'; return out;}
template<class T> istream& operator>>(istream& in, deque<T> &a) {for (auto &i: a) in >> i; return in;}
template<class T> ostream& operator<<(ostream& out, const deque<T> &a) {for (auto &i: a) out << i << ' '; return out;}
// istream& operator>>(istream& in, __int128_t &a) {string s; in >> s; a = 0; for (auto &i: s) a = a*10 + (i - '0'); return in;}
// ostream& operator<<(ostream& out, __int128_t a) {string s = ""; while (a > 0) {s+=(int)(a % 10) + '0'; a/=10;} Reverse(s); out << s; return out;}

vi cal(vi a, vi b) {
    vi c;
    set_symmetric_difference(all(a), all(b), back_inserter(c));
    return c;
}
struct xor_basis {
    int d, s;
    vector<pair<ll, vi>> a;
    xor_basis(int n) {
        d = n;
        s = 0;
        a.assign(d, make_pair(0ll, vi()));
    }
    bool add(ll x, vi b) {
        for (int i = d - 1; i >= 0; i--) {
            if ((x >> i) & 1) {
                if (!a[i].first) {
                    a[i].first = x;
                    a[i].second.swap(b);
                    s++;
                    return 1;
                }
                x^=a[i].first;
                b = cal(b, a[i].second);
            }
        }
        return 0;
    }
};
int main() {
    ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL);
    cout << fixed << setprecision(10);
    int n; cin >> n;
    xor_basis c(60);
    vll a(n), b(n);
    ll x = 0, y = 0;
    trav(i,a) cin >> i, x^=i;
    trav(i,b) cin >> i, y^=i;
    For(i,0,n) c.add(a[i]^b[i], {i});
    vi p;
    Fore(i,59,0){
        if (((x >> i) & 1) && ((y >> i) & 1)) continue;
        if (!c.a[i].first) continue;
        if (!((x >> i) & 1) && (!(y >> i) & 1)) {
            x^=c.a[i].first, y^=c.a[i].first;
            p = cal(p, c.a[i].second);
        } else {
            ll v = c.a[i].first^(1ll << i);
            vi t = c.a[i].second;
            c.a[i].first = 0; c.a[i].second.clear();
            c.add(v, t);
        }
    }
    trav(i,p) i++;
    cout << x + y << ' ' << sz(p) << '\n' << p;
    cerr << "\nProcess returned 0 (0x0)   execution time :  " << 0.001*clock() << " s";
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3924kb

input:

2
1 1
2 2

output:

6 1
1 

result:

ok n=2

Test #2:

score: 0
Accepted
time: 0ms
memory: 3964kb

input:

3
2 1 4
4 0 4

output:

7 0

result:

ok n=3

Test #3:

score: 0
Accepted
time: 0ms
memory: 4024kb

input:

10
12 0 4 3 1 1 12 3 11 11
3 3 14 6 14 15 1 15 5 2

output:

26 1
1 

result:

ok n=10

Test #4:

score: 0
Accepted
time: 0ms
memory: 4012kb

input:

50
9 27 19 1 31 10 2 7 25 26 12 25 15 18 11 15 30 25 31 2 5 30 8 18 8 17 14 2 17 7 26 26 10 25 26 5 3 5 1 17 18 12 4 17 14 19 30 30 20 2
13 18 3 8 18 11 31 20 21 14 17 29 31 2 5 28 31 17 10 13 6 10 22 18 10 2 0 15 7 14 4 15 25 10 3 30 3 21 0 12 11 19 4 16 27 10 26 3 2 5

output:

35 0

result:

ok n=50

Test #5:

score: -100
Wrong Answer
time: 0ms
memory: 4004kb

input:

100
50 13 42 41 8 21 50 18 21 50 9 27 51 10 43 26 29 6 52 44 52 19 39 47 59 35 42 6 27 41 8 25 32 32 45 18 57 5 46 32 60 24 63 56 31 32 58 15 0 36 31 33 31 50 14 45 31 27 15 55 8 53 10 5 8 24 15 35 45 34 16 31 44 51 34 13 30 49 0 4 62 6 8 30 44 29 59 60 45 40 1 0 40 29 35 18 42 52 15 28
35 43 24 14 ...

output:

69 0

result:

wrong answer Jury has better answer