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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#466617#3098. Ancient MachineBalintR0 42ms9836kbC++204.1kb2024-07-07 23:17:372024-07-07 23:17:37

Judging History

你现在查看的是最新测评结果

  • [2024-07-07 23:17:37]
  • 评测
  • 测评结果:0
  • 用时:42ms
  • 内存:9836kb
  • [2024-07-07 23:17:37]
  • 提交

Anna

#include <bits/stdc++.h>
#include "Anna.h"
using namespace std;

typedef unsigned uint;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<pii> vpii;
typedef complex<double> cpx;
template <typename T> using minPq = priority_queue<T, vector<T>, greater<T>>;
#define ms(a, x) memset(a, x, sizeof(a))
#define pb push_back
#define fs first
#define sn second
#define ALL(v) begin(v), end(v)
#define SZ(v) ((int) (v).size())
#define lbv(v, x) (lower_bound(ALL(v), x) - (v).begin())
#define ubv(v, x) (upper_bound(ALL(v), x) - (v).begin())
template <typename T> inline void UNIQUE(vector<T> &v){sort(ALL(v)); v.resize(unique(ALL(v)) - v.begin());}
const int INF = 0x3f3f3f3f;
const ll LLINF = 0x3f3f3f3f3f3f3f3f;
const double PI = acos(-1);
#define FR(i, n) for(int i = 0; i < (n); i++)
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define FORR(i, a, b) for(int i = (a); i >= (b); i--)
#define dbg(x) {cerr << #x << ' ' << x << endl;}
#define dbgArr(arr, n) {cerr << #arr; FR(_i, n) cerr << ' ' << (arr)[_i]; cerr << endl;}
template <typename T, typename U>
ostream& operator<<(ostream &os, pair<T, U> p){return os << "(" << p.fs << ", " << p.sn << ")";}

namespace { // clown
    const int B = 28;
    const int K = 40;
    ll fib[K];

    void init(){
        fib[0] = 1;
        fib[1] = 2;
        FOR(i, 2, K) fib[i] = fib[i-1] + fib[i-2];
    }
}

void Anna(int n, vector<char> str){
    init();
    
    vi vec;
    bool foundX = false;
    FR(i, n){
        if(!foundX){
            if(str[i] == 'X') vec.pb(1), vec.pb(0), foundX = true;
            else vec.pb(0);
        }
        else {
            vec.pb(str[i] == 'Z' && str[i-1] != 'Z');
        }
    }
    while(SZ(vec) % K) vec.pb(0);

    for(int i = 0; i < SZ(vec); i += K){
        int x = 0;
        FR(j, K) x += vec[i+j]*fib[j];
        assert(x < (1<<B));
        FR(j, B) Send((x >> j) & 1);
    }
}

Bruno

#include <bits/stdc++.h>
#include "Bruno.h"
using namespace std;

typedef unsigned uint;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<pii> vpii;
typedef complex<double> cpx;
template <typename T> using minPq = priority_queue<T, vector<T>, greater<T>>;
#define ms(a, x) memset(a, x, sizeof(a))
#define pb push_back
#define fs first
#define sn second
#define ALL(v) begin(v), end(v)
#define SZ(v) ((int) (v).size())
#define lbv(v, x) (lower_bound(ALL(v), x) - (v).begin())
#define ubv(v, x) (upper_bound(ALL(v), x) - (v).begin())
template <typename T> inline void UNIQUE(vector<T> &v){sort(ALL(v)); v.resize(unique(ALL(v)) - v.begin());}
const int INF = 0x3f3f3f3f;
const ll LLINF = 0x3f3f3f3f3f3f3f3f;
const double PI = acos(-1);
#define FR(i, n) for(int i = 0; i < (n); i++)
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define FORR(i, a, b) for(int i = (a); i >= (b); i--)
#define dbg(x) {cerr << #x << ' ' << x << endl;}
#define dbgArr(arr, n) {cerr << #arr; FR(_i, n) cerr << ' ' << (arr)[_i]; cerr << endl;}
template <typename T, typename U>
ostream& operator<<(ostream &os, pair<T, U> p){return os << "(" << p.fs << ", " << p.sn << ")";}

namespace { // clown
    const int B = 28;
    const int K = 40;
    ll fib[K];

    void init(){
        fib[0] = 1;
        fib[1] = 2;
        FOR(i, 2, K) fib[i] = fib[i-1] + fib[i-2];
    }
}

void Bruno(int n, int l, vector<int> vec){
    vi arr(l/B*K);
    init();
    for(int a = 0, b = 0; b < SZ(vec); b += B, a += K){
        int x = 0;
        FR(j, B) x += vec[b+j] << j;
        FORR(j, K-1, 0) if(x >= fib[j]) x -= fib[j], arr[a+j] = 1;
    }
    arr.pb(1);

    vector<bool> rem(n);
    vi ps;
    FR(i, l) if(arr[i]) ps.pb(i);

    if(SZ(ps) == 1){
        FR(i, n) Remove(i);
        return;
    }

    FOR(i, 1, SZ(ps)) ps[i]--;

    FOR(i, 1, SZ(ps)){
        FORR(j, ps[i]-1, ps[i-1]+1) Remove(j), rem[j] = true;
        Remove(ps[i]), rem[ps[i]] = true;
    }
    FR(i, n) if(!rem[i]) Remove(i), rem[i] = true;
}

详细

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 3812kb

input:

18
Y X Y Z X Z X X Z Z Y Y Z Y Y Z X X

output:

28
0100111100110000000000000000

input:

28
0100111100110000000000000000

output:

0 28 2

result:

wrong answer your query is valid but your solution is not optimal: read 2 but expected 3

Subtask #2:

score: 0
Wrong Answer

Test #12:

score: 0
Wrong Answer
time: 42ms
memory: 9836kb

input:

100000
X Z X Z Z X Y Z Y X Y X Z Z Z Y X Z Y X Y Y X Y Y Y Z Y Z Z Y X X Y X X Y Y X X X Z Y Y Y Z Z Z Z Y X Y Y Z Z Z X Y Z X X X X Y X Y X X Z X Z Z Z X Y X X X Z X Z X X X Y Y Y Y Z X X Y Z Y Y X Z X Z Z Z Z Z Y Z Y X Y Y Y Y X Z Z Y Z Z Y Z Z Z X Z Z X X Z Z Z Z X X Z Y Y Z Y Y Z Z Y Y Z Y Z Y Z...

output:

70028
001001010000000100111000000010000111011100001001010001011010111011100000110000110011111111101011000010001011101111011010001111001001010101010110000100010001010100111001000111111010000111000000100111101010111011101110010011001011011011111111001101010001110100010110001110010100100001000100100110...

input:

70028
001001010000000100111000000010000111011100001001010001011010111011100000110000110011111111101011000010001011101111011010001111001001010101010110000100010001010100111001000111111010000111000000100111101010111011101110010011001011011011111111001101010001110100010110001110010100100001000100100110...

output:

0 70028 12936

result:

wrong answer your query is valid but your solution is not optimal: read 12936 but expected 22133