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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#465942#1877. Matryoshka DollsGenshinImpactsFaultTL 5ms26172kbC++143.0kb2024-07-07 14:00:112024-07-07 14:00:11

Judging History

你现在查看的是最新测评结果

  • [2024-07-07 14:00:11]
  • 评测
  • 测评结果:TL
  • 用时:5ms
  • 内存:26172kb
  • [2024-07-07 14:00:11]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int N = 500010, BLO = 3;
int n, m;
int a[N], rev[N];
int pre[N], nxt[N], spre[N], snxt[N];
bool vis[N];
ll ans[N], cur, scur;
vector<pair<pair<int, int>, int> > q[N / BLO + 10];
vector<pair<int, int> > vec[N / BLO + 10];
int t1[N], lt1, t2[N], lt2, t[N], lt;

ll solve(int l, int r) {
	int bll = (l - 1) / BLO + 1, blr = (r - 1) / BLO + 1;
	ll res = 0;
	if(bll == blr) {
		lt = 0;
		for(auto v : vec[bll]) {
			if(v.second >= l && v.second <= r) t[++lt] = v.second;
		}
		for(int i = 2; i <= lt; i++) res += abs(t[i] - t[i - 1]);
		return res;
	}
	lt1 = lt2 = 0;
	for(auto v : vec[bll]) {
		if(v.second >= l) t1[++lt1] = v.second;
	}
	for(auto v : vec[blr]) {
		if(v.second <= r) t2[++lt2] = v.second;
	}
	lt = 0;
	for(int i = 1, j = 1; i <= lt1 || j <= lt2;) {
		if(j > lt2 || (i <= lt1 && a[t1[i]] < a[t2[j]])) {
			t[++lt] = t1[i], ++i;
		}
		else {
			t[++lt] = t2[j], ++j;
		}
	}
	for(int i = 2; i <= lt; i++) res += abs(t[i] - t[i - 1]);
	return res;
}
void build() {
	cur = 0;
	int tmp = 0;
	pre[0] = 0, nxt[n + 1] = n + 1;
	for(int j = 1; j <= n; j++) {
		if(!vis[j]) continue;
		if(tmp != 0) {
			cur += abs(rev[tmp] - rev[j]);
		}
		nxt[tmp] = j, pre[j] = tmp;
		tmp = j;
	}
	nxt[tmp] = n + 1, pre[n + 1] = tmp;
	for(int j = 0; j <= n + 1; j++) {
		spre[j] = pre[j], snxt[j] = nxt[j];
	}
	lt = 0;
}
void erase(int x, int flag) {
	x = a[x];
	if(pre[x] != 0) {
		cur -= abs(rev[pre[x]] - rev[x]);
	}
	if(nxt[x] != n + 1) {
		cur -= abs(rev[nxt[x]] - rev[x]);
	}
	if(pre[x] != 0 && nxt[x] != n + 1) {
		cur += abs(rev[nxt[x]] - rev[pre[x]]);
	}
	if(flag) {
		t[++lt] = x, t[++lt] = pre[x], t[++lt] = nxt[x];
	}
	nxt[pre[x]] = nxt[x], pre[nxt[x]] = pre[x];
	if(!flag) {
		snxt[pre[x]] = nxt[x], spre[nxt[x]] = pre[x];
	}
}
int main() {
	ios::sync_with_stdio(0); cin.tie(nullptr);
	cin >> n >> m;
	for(int i = 1; i <= n; i++) {
		cin >> a[i], rev[a[i]] = i;
	}
	for(int i = 1; i <= n; i++) {
		vec[(i - 1) / BLO + 1].push_back({a[i], i});
	}
	for(int i = 1; i <= (n - 1) / BLO + 1; i++) {
		sort(vec[i].begin(), vec[i].end());
	}
	for(int i = 1; i <= m; i++) {
		int l, r; cin >> l >> r;
		if(r - l + 1 <= BLO) {
			ans[i] = solve(l, r);
			continue;
		}
		q[(l - 1) / BLO + 1].push_back({{l, r}, i});
	}
	for(int i = 1; i <= (n - 1) / BLO + 1; i++) {
		sort(q[i].begin(), q[i].end(), [](pair<pair<int, int>, int> x, pair<pair<int, int>, int> y) {
			return x.first.second > y.first.second;
		});
		for(int j = 1; j <= n; j++) vis[j] = 0;
		for(int j = (i - 1) * BLO + 1; j <= n; j++) vis[a[j]] = 1;
		build();
		int l = (i - 1) * BLO + 1, r = n;
		for(auto v : q[i]) {
			for(; r > v.first.second; erase(r, 0), --r);
			scur = cur;
			for(; l < v.first.first; erase(l, 1), ++l);
			ans[v.second] = cur;
			cur = scur;
			l = (i - 1) * BLO + 1;
			for(; lt; --lt) {
				pre[t[lt]] = spre[t[lt]];
				nxt[t[lt]] = snxt[t[lt]];
			}
		}
	}
	for(int i = 1; i <= m; i++) cout << ans[i] << "\n";
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 5ms
memory: 26092kb

input:

5 5
1 5 2 4 3
1 5
1 4
1 3
1 2
1 1

output:

7
5
3
1
0

result:

ok 5 number(s): "7 5 3 1 0"

Test #2:

score: 0
Accepted
time: 0ms
memory: 26172kb

input:

1 1
1
1 1

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: -100
Time Limit Exceeded

input:

100000 1
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50 52 54 56 58 60 62 64 66 68 70 72 74 76 78 80 82 84 86 88 90 92 94 96 98 100 102 104 106 108 110 112 114 116 118 120 122 124 126 128 130 132 134 136 138 140 142 144 146 148 150 152 154 156 158 160 162 164 166 168 170 172 ...

output:

4999950000

result: