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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#465891 | #7738. Equivalent Rewriting | evirir# | WA | 0ms | 13676kb | C++14 | 3.0kb | 2024-07-07 13:02:56 | 2024-07-07 13:02:57 |
Judging History
answer
#pragma GCC optimize("Ofast")
#include<bits/stdc++.h>
using namespace std;
#define pb push_back
#define fi first
#define se second
#define sz(a) (int)(a.size())
#define all(a) a.begin(),a.end()
#define lb lower_bound
#define ub upper_bound
#define owo ios_base::sync_with_stdio(0);cin.tie(0);
#define MOD (ll)(998244353)
#define INF (ll)(1e18)
#define debug(...) fprintf(stderr, __VA_ARGS__),fflush(stderr)
#define time__(d) for(long blockTime = 0; (blockTime == 0 ? (blockTime=clock()) != 0 : false);\
debug("%s time : %.4fs\n", d, (double)(clock() - blockTime) / CLOCKS_PER_SEC))
typedef long long int ll;
typedef long double ld;
typedef pair<ll,ll> PII;
typedef pair<int,int> pii;
typedef vector<vector<int>> vii;
typedef vector<vector<ll>> VII;
ll gcd(ll a,ll b){if(!b)return a;else return gcd(b,a%b);}
const int MAXN = 2e5+5;
vector<int>g[MAXN],gr[MAXN];
int out[MAXN];
int main()
{
owo
int t;
cin>>t;
while(t--){
int n,m;
cin>>n>>m;
vii pos(m);
for(int i=0;i<n;i++){
g[i].clear();
gr[i].clear();
out[i] = 0;
}
for(int i=0;i<n;i++){
int p;
cin>>p;
while(p--){
int x;
cin>>x;
pos[x-1].pb(i);
}
}
for(int i=0;i<m;i++){
for(int j=0;j+1<sz(pos[i]);j++){
int v = pos[i].back();
int u = pos[i][j];
g[v].pb(u);
gr[u].pb(v);
cout<<v<<" "<<u<<'\n';
out[v]++;
}
}
priority_queue<int>p0;
for(int i=0;i<n;i++){
if(!out[i]){
p0.push(i);
}
}
vector<int>perm(n);
for(int i=0;i<n;i++){
int v = p0.top();
p0.pop();
perm[v] = i;
for(int x:gr[v]){
out[x]--;
if(!out[x]){
p0.push(x);
}
}
}
bool ok = 0;
for(int i=0;i<n;i++){
if(i!=perm[i])ok = 1;
}
if(ok){
cout<<"Yes"<<'\n';
for(int x:perm)cout<<x+1<<" ";
cout<<'\n';
continue;
}
priority_queue<int,vector<int>,greater<int>>p1;
for(int i=0;i<n;i++){
out[i] = sz(gr[i]);
if(!out[i])p1.push(i);
}
//vector<int>perm(n);
for(int i=0;i<n;i++){
int v = p1.top();
p1.pop();
perm[v] = i;
for(int x:gr[v]){
out[x]--;
if(!out[x]){
p1.push(x);
}
}
}
if(ok){
cout<<"Yes"<<'\n';
for(int x:perm)cout<<x+1<<" ";
cout<<'\n';
continue;
}
cout<<"No"<<'\n';
}
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 13676kb
input:
3 3 6 3 3 1 5 2 5 3 2 2 6 2 3 3 1 3 2 2 3 1 1 3 2 2 1
output:
1 0 1 0 Yes 2 3 1 1 0 1 0 No No
result:
wrong answer Token parameter [name=yesno] equals to "1", doesn't correspond to pattern "Yes|No" (test case 1)