QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#462624#8339. Rooted TreecastcTL 1461ms115028kbC++20975b2024-07-03 22:20:152024-07-03 22:20:16

Judging History

你现在查看的是最新测评结果

  • [2024-07-03 22:20:16]
  • 评测
  • 测评结果:TL
  • 用时:1461ms
  • 内存:115028kb
  • [2024-07-03 22:20:15]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define int long long
const int N=5e7+10,M=1e9+9;
int ny[N],dp[N],zt[N],maxx,f[N];
int ksm(int a,int b,int c){
    int b1=b;
    zt[1]=a%c;
    int cnt=1;
    int ans=1;
    while(b1){
        cnt++;
        zt[cnt]=zt[cnt-1]*zt[cnt-1]%c;
        b1>>=1;
    }
    cnt=0;
    while(b){
        cnt++;
        if(b&1){
            //cnt++;
            ans*=zt[cnt];
            ans%=c; 
        }
        b>>=1;
    }
    return ans;
}
signed main(){
    int m,k;
    cin>>m>>k;
    f[0]=1; 
    for(int i=1;i<=k;i++){
        f[i]=f[i-1]-1+m;
    }
    dp[0]=0;
    ny[1]=1;
    for(int i=1;i<=k;i++){
        int zqx=ksm(f[i],M-2,M);
        dp[i]=((dp[i-1]*f[i-1])%M*zqx%M-(dp[i-1]*zqx%M)+M)%M+m*dp[i-1]%M*zqx%M+m*zqx%M;
        dp[i]%=M;
    }
    int ans1=dp[k]*f[k]%M;
    for(int i=1;i<k;i++){
        ans1+=dp[i];
        ans1%=M;
    }
    cout<<ans1<<endl;
    return 0;
} 

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 9752kb

input:

6 2

output:

18

result:

ok 1 number(s): "18"

Test #2:

score: 0
Accepted
time: 1ms
memory: 9612kb

input:

2 6

output:

600000038

result:

ok 1 number(s): "600000038"

Test #3:

score: 0
Accepted
time: 131ms
memory: 20996kb

input:

83 613210

output:

424200026

result:

ok 1 number(s): "424200026"

Test #4:

score: 0
Accepted
time: 1461ms
memory: 115028kb

input:

48 6713156

output:

198541581

result:

ok 1 number(s): "198541581"

Test #5:

score: 0
Accepted
time: 1ms
memory: 9676kb

input:

1 111

output:

6216

result:

ok 1 number(s): "6216"

Test #6:

score: -100
Time Limit Exceeded

input:

28 7304152

output:

457266679

result: