#include<bits/stdc++.h>
#define pb push_back
#define P make_pair
#define fi first
#define se second
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
inline ll read(){
	ll x=0,c=getchar();
	while(c<'0'||c>'9')c=getchar();
	while(c>='0' && c<='9')x=x*10 + c-'0',c=getchar();
	return x;
}
int n,x,y,ma,mb,q;
const int mod=998244353;
inline void Ad(int &x,int y){x=x+y>=mod?x+y-mod:x+y;}
inline int ad(int x,int y){return x+y>=mod?x+y-mod:x+y;}
const int M=2e5+2;
const int N=5003;
int A[M],B[M];
int a[N][N],C[N],iv[N<<1];
inline int fp(int x,int p=mod-2){
	int res=1;
	for(;p;p>>=1){
		if(p&1)res=1ll*res*x%mod;
		x=1ll*x*x%mod;
	}
	return res;
}
inline void solve(){
	ma=mb=0;
	rep(i,1,q)A[i]=read(),B[i]=read(),ma=max(ma,A[i]),mb=max(mb,B[i]);
	if(x==y){
		rep(i,1,q){
			int res=fp(x,n-A[i]-B[i]);
			rep(j,1,A[i]+B[i])res=1ll*res*(n-j+1)%mod*iv[j]%mod;
			printf("%d\n",res);
		}
		return ;
	}
	C[0]=1;
	rep(i,1,max(ma,mb))C[i]=1ll*C[i-1]*(n-i+2)%mod*iv[i]%mod;
	const int ivx=fp(x),ivy=fp(y),iv=fp(ad(x,mod-y));
	int px=fp(x,n+1),py=fp(y,n+1);
	a[0][0]=ad(px,mod-py);
	rep(i,1,ma)px=1ll*px*ivx%mod,a[i][0]=1ll*px*C[i]%mod;
	rep(i,1,mb)py=1ll*py*ivy%mod,a[0][i]=mod-1ll*py*C[i]%mod;
	rep(i,1,ma)rep(j,1,mb)a[i][j]=0;
	rep(i,0,ma)rep(j,0,mb){
		a[i][j]=1ll*a[i][j]*iv%mod;
		Ad(a[i+1][j],mod-a[i][j]);
		Ad(a[i][j+1],a[i][j]);
	}
	rep(i,1,q)printf("%d\n",a[A[i]][B[i]]);
}
int main(){
	//freopen("data.in","r",stdin);
	//freopen(".in","r",stdin);
	//freopen(".out","w",stdout);
	iv[1]=1;rep(i,2,(N<<1)-1)iv[i]=1ll*iv[mod%i]*(mod-mod/i)%mod;
	while(scanf("%d%d%d%d",&n,&x,&y,&q)!=EOF)solve();
}