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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#422483 | #2070. Heavy Stones | 5k_sync_closer | TL | 0ms | 3676kb | C++14 | 867b | 2024-05-27 14:59:25 | 2024-05-27 14:59:25 |
Judging History
answer
#include <cstdio>
#include <cstring>
#include <algorithm>
#define int long long
using namespace std;
int n, a[200050], f[5050][5050];
signed main()
{
// freopen("freight.in", "r", stdin);
// freopen("freight.out", "w", stdout);
scanf("%lld", &n);
for (int i = 1; i <= n; ++i)
scanf("%lld", a + i);
for (int l = 0; l < n; ++l)
{
for (int r = n + 1; r > l + 1; --r)
{
f[l][r] = 1e18;
if (l != 0)
f[l][r] = min(f[l][r], a[l] * (l + n - r + 1) + f[l - 1][r]);
if (r != n + 1)
f[l][r] = min(f[l][r], a[r] * (l + n - r + 1) + f[l][r + 1]);
if (l == 0 && r == n + 1)
f[l][r] = 0;
}
}
for (int i = 1; i <= n; ++i)
printf("%lld ", a[i] * (n - 1) + f[i - 1][i + 1]);
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3676kb
input:
5 2 1 3 5 4
output:
35 35 36 43 49
result:
ok single line: '35 35 36 43 49 '
Test #2:
score: 0
Accepted
time: 0ms
memory: 3620kb
input:
10 18 37 81 6 58 99 87 34 75 9
output:
2637 2637 2657 2657 2695 2949 2995 2905 2880 2880
result:
ok single line: '2637 2637 2657 2657 2695 2949 2995 2905 2880 2880 '
Test #3:
score: -100
Time Limit Exceeded
input:
200000 479735 430060 863649 878892 889364 241972 927862 32858 714406 674598 88114 438434 167733 457299 951288 510096 635193 504974 649221 617914 223711 812277 364169 746142 836563 825312 994240 198961 567906 905208 509572 744710 891294 928176 833980 985385 858440 50835 86130 324862 796245 935992 383...