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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#408695#6705. MedianMessywindAC ✓9ms3688kbC++201.4kb2024-05-10 21:27:442024-05-10 21:27:44

Judging History

你现在查看的是最新测评结果

  • [2024-05-10 21:27:44]
  • 评测
  • 测评结果:AC
  • 用时:9ms
  • 内存:3688kb
  • [2024-05-10 21:27:44]
  • 提交

answer

#include<bits/stdc++.h>
#include<unordered_map>

using namespace std;

#define int long long
#define endl '\n'
#define ULL unsigned long long
#define xx first
#define yy second
#define PII pair

const int MAXN = 1e2 + 10;
const int MOD = 998244353;
const int mod = 1e9 + 7;
const double eps = 1e-8;
int _x[] = { 1,-1,0,0 };
int _y[] = { 0,0,1,-1 };
int arr[MAXN];

int gr[MAXN][MAXN];
int to[MAXN][2];


bool floyd(int n)
{
	for(int k=1;k<=n;k++)
		for(int i=1;i<=n;i++)
			for (int z = 1; z <= n; z++)
				if (gr[i][k] && gr[k][z])
					gr[i][z] = 1;
	for(int i=1;i<=n;i++)
		for (int z = 1; z <= n; z++)
		{
			if (gr[i][z] && gr[z][i])
				return false;
			if (gr[i][z])
			{
				to[i][0]++;
				to[z][1]++;
			}
		}
	return 1;
}

void init()
{
	memset(gr, 0, sizeof(gr));
	memset(to, 0, sizeof(to));
}

signed main(void)
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int t;
	cin >> t;
	while (t--)
	{
		int n, m;
		cin >> n >> m;
		init();
		for (int i = 1; i <= m; i++)
		{
			int a, b;
			cin >> a >> b;
			gr[a][b] = 1;
		}
		if (!floyd(n))
		{
			for (int i = 1; i <= n; i++)
				cout << 0;
			cout << endl;
			continue;
		}
		for (int i = 1; i <= n; i++)
		{
			if (to[i][0] < ((n+1) >> 1) && to[i][1] < ((n+1) >> 1))
				cout << 1;
			else
				cout << 0;
		}
		cout << endl;

	}


	return 0;
}

这程序好像有点Bug,我给组数据试试?

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 3688kb

input:

2
5 4
1 2
3 2
2 4
2 5
3 2
1 1
2 3

output:

01000
000

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 9ms
memory: 3656kb

input:

66
13 2
9 13
7 11
11 19
9 1
8 1
5 1
2 8
4 2
2 1
5 2
6 3
3 11
3 2
4 6
6 10
9 8
3 5
1 7
5 8
3 9
4 9
6 7
3 1
2 3
11 6
9 4
1 6
5 2
1 5
4 6
8 4
15 15
10 6
15 8
7 6
11 1
5 2
3 4
11 13
4 6
10 12
10 13
1 6
15 2
5 12
13 14
5 3
15 86
14 12
8 1
14 9
8 15
5 10
1 9
11 2
6 2
7 10
10 13
14 5
4 13
5 8
4 10
13 9
6 9...

output:

1111111111111
01001000111
111
11111111111
111111111111111
001001000000000
00100
01100
1111111
1000000000000
111101101
111111111
000011111011101
010111111
001100000
0100001001101
1111111111111
001000010000000
10010111011
001000000000100
11111111111
00100000011
11111
01000000110
11101110111
00000
1111...

result:

ok 66 lines