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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#406149 | #7613. Inverse Problem | ucup-team3215 | WA | 580ms | 26536kb | C++20 | 5.1kb | 2024-05-06 21:11:56 | 2024-05-06 21:11:57 |
Judging History
answer
#include <array>
#include <algorithm>
#include <cstdint>
#include <iostream>
#include <numeric>
#include <vector>
using namespace std;
constexpr int mod = 1e9 + 7;
auto& mul(auto&& a, auto b) { return a = a * (uint64_t) b % mod; }
int inv(int a) { for (int r = 1, b = mod - 2; ; b /= 2, mul(a, a)) if (!b) return r; else if (b % 2) mul(r, a); }
using namespace std;
struct HS {
static constexpr int mlf = 8;
int cap;
vector<array<int, 2>> knx;
vector<int> head;
HS(): cap{4 * mlf - 1}, head(cap + 1, -1) {
}
void emplace(int k) {
knx.push_back({k, head[k & cap]});
head[k & cap] = knx.size() - 1;
maybe_rehash();
}
int find(int k) {
for (int i = head[k & cap]; ~i; i = knx[i][1]) if (knx[i][0] == k) return i;
return -1;
}
void clear() {
knx.clear();
head.assign(cap + 1, -1);
}
void maybe_rehash() {
if (knx.size() * mlf <= cap) return;
head.assign((cap += cap + 1) + 1, -1);
for (int i = 0; i < knx.size(); ++i) {
knx[i][1] = head[knx[i][0] & cap];
head[knx[i][0] & cap] = i;
}
}
};
vector<HS> high(1);
vector<int> inv_(1);
vector<char> done;
vector<array<int, 2>> cur;
vector<int> qs;
vector<vector<int>> ans;
void gen_high(const vector<int>& prof, int n0, int n, int c, int p) {
high[n0 - n].emplace(p);
int i = 0;
for (int cc = prof[n]; ++cc <= min(n, c); ) {
for (; i < cc; ++i) mul(p, inv_[n0 - i]);
gen_high(prof, n0, n - cc, cc, p);
}
}
void restore_high(const vector<int>& prof, int n0, int n, int c, auto&& cur, auto&& idx, auto&& cidx) {
++idx;
while (cidx < cur.size() && ::cur[cidx][0] == idx) {
auto [x, i] = ::cur[cidx++];
ans[i].insert(ans[i].end(), cur.begin(), cur.end());
}
if (cidx == cur.size()) return;
for (int cc = prof[n]; ++cc <= min(n, c); ) {
cur.push_back(cc);
restore_high(prof, n0, n - cc, cc, cur, idx, cidx);
cur.pop_back();
}
}
void solve(const vector<int>& prof, int n0, int n, int c, int p, auto&& cur) {
for (int i = 0; i < qs.size(); ++i) if (!done[i] && ~high[n0 - n].find(mul(+p, qs[i]))) {
done[i] = 1;
ans[i] = cur;
::cur.push_back({high[n0 - n].find(mul(+p, qs[i])), i});
}
int i = 0;
for (; n + c <= n0 && c <= prof[n + c]; ++c) {
for (; i < c; ++i) mul(p, n0 - i);
cur.push_back(c);
solve(prof, n0, n + c, c, p, cur);
cur.pop_back();
}
}
uint64_t eval_high(vector<int> profile) {
int N = profile.size();
vector<uint64_t> cnt(N * N);
cnt[N * N - 1] = 1;
uint64_t ans = 0;
for (int n = N; --n; )
for (int c = N; --c; ) if (cnt[n * N + c]) {
for (int cc = min(n, c); cc > profile[n]; cc--) {
cnt[(n - cc) * N + cc] += cnt[n * N + c];
}
ans += cnt[n * N + c];
}
return ans;
}
uint64_t eval_low(vector<int> profile) {
int N = profile.size();
vector<uint64_t> cnt(N * N);
cnt[0] = 1;
uint64_t ans = 0;
for (int n = 0; n < N; ++n)
for (int c = 0; c <= n; ++c) if (cnt[n * N + c]) {
for (int cc = max(c, 1); n + cc < N && cc <= profile[n + cc]; ++cc) {
cnt[(n + cc) * N + cc] += cnt[n * N + c];
}
ans += cnt[n * N + c];
}
return ans;
}
uint64_t eval(vector<int> profile) {
return eval_high(profile) + eval_low(profile);
}
vector<int> makeprof(int n, vector<int> from) {
vector<int> prof(n + 1, 0);
int j = n;
for (int i = 0; i < from.size() - 1; ++i) {
while (j >= from[i]) prof[j--] = i;
}
while (j >= 0) prof[j--] = n;
return prof;
}
vector<int> getopt(int n) {
static vector<vector<int>> precalc = [] {
int n = 124;
vector<vector<int>> res(n);
vector<int> tmpl(10, n);
while (n-- > 1) {
int64_t bst = eval(makeprof(n, tmpl));
for (int ch = 1; ch--; ) {
for (int i = 1; i < tmpl.size() - 1; ++i)
for (auto d: {-1, 1}) if (tmpl[i] + d >= 0 && tmpl[i] + d <= n + 1) {
tmpl[i] += d;
int64_t cur = eval(makeprof(n, tmpl));
if (cur > bst) tmpl[i] -= d;
else if (cur < bst) ch = 1, bst = cur;
sort(tmpl.rbegin() + 1, tmpl.rend());
}
}
res[n] = tmpl;
}
return res;
}();
return makeprof(n, precalc[n]);
}
int main() {
int tc; cin >> tc;
qs.resize(tc);
ans.resize(tc);
for (int i = 0; i < tc; ++i) {
cin >> qs[i];
done.push_back(qs[i] <= 2);
qs[i] = inv(qs[i]);
}
for (int n = 1; !all_of(done.begin(), done.end(), identity{}); ++n) {
inv_.push_back(inv(n));
high.push_back({});
for (auto& x: high) x.clear();
cur.clear();
gen_high(getopt(n), n, n, n, 1);
solve(getopt(n), n, 0, 1, mul(n + 1, n + 2), vector<int>{});
sort(cur.begin(), cur.end());
restore_high(getopt(n), n, n, n, vector<int>{}, 0, 0);
// cout << n << '\n';
}
for (int i = 0; i < tc; ++i) {
if (qs[i] == 1) cout << "1\n";
else {
cout << accumulate(ans[i].begin(), ans[i].end(), 0) + 2 << "\n1 2\n";
for (int j = 0, k = 2; j < ans[i].size(); ++j)
while (ans[i][j]--) cout << j + 1 << ' ' << ++k << '\n';
}
}
}
详细
Test #1:
score: 100
Accepted
time: 130ms
memory: 3656kb
input:
4 2 360 1 509949433
output:
2 1 2 5 1 2 1 3 2 4 2 5 1 10 1 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 10
result:
ok OK (4 test cases)
Test #2:
score: -100
Wrong Answer
time: 580ms
memory: 26536kb
input:
9 185396120 468170792 837583517 696626231 338497514 762842660 800028852 928391161 733524004
output:
10 1 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 10 42 1 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 10 9 11 10 12 11 13 12 14 13 15 14 16 14 17 15 18 15 19 16 20 16 21 17 22 17 23 17 24 18 25 18 26 18 27 19 28 19 29 19 30 20 31 20 32 20 33 21 34 21 35 21 36 22 37 22 38 22 39 22 40 22 41 22 42 39 1 2 1 3 2 4 3 5 4 6 5 7 6 ...
result:
wrong answer Liczba kolorowań jest błędna!