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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#405470 | #7613. Inverse Problem | ucup-team3215 | ML | 1ms | 3516kb | C++20 | 3.0kb | 2024-05-06 00:00:33 | 2024-05-06 00:00:33 |
Judging History
answer
#include <algorithm>
#include <cstdint>
#include <iostream>
#include <numeric>
#include <vector>
using namespace std;
constexpr int mod = 1e9 + 7;
auto& mul(auto&& a, auto b) { return a = a * (uint64_t) b % mod; }
int inv(int a) { for (int r = 1, b = mod - 2; ; b /= 2, mul(a, a)) if (!b) return r; else if (b % 2) mul(r, a); }
using namespace std;
template <typename K, typename V, int mlf = 8>
struct HT {
int capacity;
vector<pair<K, int>> knx;
vector<V> values;
vector<int> head;
HT(): capacity{4 * mlf}, head(capacity, -1) {
}
void emplace(K k, V v) {
// if (~find(k)) return;
knx.push_back({k, head[k & capacity - 1]});
values.push_back(v);
head[k & capacity - 1] = knx.size() - 1;
maybe_rehash();
}
int find(K k) {
for (int i = head[k & capacity - 1]; ~i; i = knx[i].second) if (knx[i].first == k) return i;
return -1;
}
void clear() {
knx.clear();
values.clear();
head.assign(capacity, -1);
}
void maybe_rehash() {
if (knx.size() * mlf <= capacity) return;
head.assign(capacity *= 2, -1);
for (int i = 0; i < knx.size(); ++i) {
knx[i].second = head[knx[i].first & capacity - 1];
head[knx[i].first & capacity - 1] = i;
}
}
};
vector<HT<int, vector<int>>> even(1);
vector<int> inv_(1);
void gen_even(int n0, int n, int c, int p, auto&& cur) {
even[n0 - n].emplace(p, cur);
for (; c > 0; c -= 2) if (c <= n) {
int np = p;
for (int i = 0; i < c; ++i) mul(np, inv_[n0 - i]);
cur.push_back(c);
gen_even(n0, n - c, c, np, cur);
cur.pop_back();
}
}
vector<int> qs;
vector<vector<int>> ans;
void solve(int n0, int n, int c, int p, auto&& cur) {
if (n % 2 == 0)
for (int i = 0; i < qs.size(); ++i) if (ans[i].empty() && ~even[n].find(mul(+p, qs[i]))) {
ans[i] = cur;
auto& t = even[n].values[even[n].find(mul(+p, qs[i]))];
ans[i].insert(ans[i].end(), t.begin(), t.end());
}
for (; c > 0; c -= 2) if (c <= n) {
int np = p;
for (int i = 0; i < c; ++i) mul(np, n0 - i);
cur.push_back(c);
solve(n0, n - c, c, np, cur);
cur.pop_back();
}
}
int main() {
int tc; cin >> tc;
qs.resize(tc);
ans.resize(tc);
for (int i = 0; i < tc; ++i) {
cin >> qs[i];
if (qs[i] == 1) ans[i] = {-1};
else if (qs[i] == 2) ans[i] = {-1};
qs[i] = inv(qs[i]);
}
for (int n = 1, done = 0; !done++; ++n) {
inv_.push_back(inv(n));
even.push_back({});
for (auto& x: even) x.clear();
gen_even(n, n, n + n % 2, 1, vector<int>{});
solve(n, n, n - n % 2 + 1, mul(n + 1, n + 2), vector<int>{});
for (int i = 0; i < tc; ++i) done &= !ans[i].empty();
}
for (int i = 0; i < tc; ++i) {
if (qs[i] == 1) cout << "1\n";
else {
if (ans[i][0] == -1) ans[i] = {};
cout << accumulate(ans[i].begin(), ans[i].end(), 0) + 2 << '\n' << "1 2\n";
for (int j = 0, k = 2; j < ans[i].size(); ++j)
while (ans[i][j]--) cout << j + 1 << ' ' << ++k << '\n';
}
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3516kb
input:
4 2 360 1 509949433
output:
2 1 2 5 1 2 1 3 2 4 2 5 1 10 1 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 10
result:
ok OK (4 test cases)
Test #2:
score: -100
Memory Limit Exceeded
input:
9 185396120 468170792 837583517 696626231 338497514 762842660 800028852 928391161 733524004
output:
14 1 2 1 3 2 4 3 5 4 6 5 7 6 8 7 9 8 10 9 11 9 12 10 13 10 14 122 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 2 32 2 33 2 34 2 35 2 36 2 37 2 38 2 39 2 40 2 41 2 42 2 43 2 44 3 45 3 46 3 47 3 48 3 49 3 ...