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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#404971 | #3004. It's a Mod, Mod, Mod, Mod World | Lspeed# | TL | 1274ms | 3744kb | C++14 | 3.3kb | 2024-05-05 04:39:10 | 2024-05-05 04:39:11 |
Judging History
answer
#include<bits/stdc++.h>
#define x first
#define y second
#define eb emplace_back
#define pb push_back
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
#define ROF(i,a,b) for(int i=(a);i>=(b);--i)
#define all(x) (x).begin(),(x).end()
#define mp make_pair
#define sz(x) (int)(x).size()
#define make_unique(x) sort(all(x)), (x).erase(unique(all(x)), (x).end())
using namespace std;
typedef long long i64;
//typedef __int128 i128;
typedef long double ld;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<i64> vl;
typedef vector<vl> vvl;
typedef pair<int,int> pii;
typedef pair<i64,i64> pll;
typedef tuple<int,int,int> iii;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
int readInt() { int a; scanf("%d",&a); return a; }
i64 readLong() { i64 a; scanf("%lld",&a); return a; }
char readChar() { char a; scanf(" %c",&a); return a; }
double readDouble() { double a; scanf(" %lf",&a); return a; }
void readString(char *s) { scanf(" %s",s); }
const int mod = 998244353;
int add(int a, int b) { return ((a+=b)>=mod) ? a-mod:a; }
int mul(int a, int b) { return a*1ll*b%mod; }
int pw(int a, int b) {
int ans = 1, res = a;
for(int i = 1; i <= b; i*=2, res=mul(res,res)) {
if(i&b) {
ans = mul(ans, res);
}
}
return ans;
}
void solve() {
int p = readInt();
int q = readInt();
int n = readInt();
p%= q;
i64 A = p*1ll*n*(n+1)/2;
if(q <= 1000) {
i64 sum = 0;
i64 cur = 0;
i64 m = 0;
FOR(i,1,q) {
cur += p;
if(cur >= q) {
m += 1;
cur -= q;
}
sum += m;
//printf("%d: %lld %lld\n",i,cur,m);
}
i64 k = n/q;
i64 ans = k*sum + m*q*k*(k-1)/2;
m *= k;
n %= q;
assert(cur == 0);
FOR(i, 1, n) {
cur += p;
if(cur >= q) {
m += 1;
cur -= q;
}
//printf("%d: %lld %lld\n",i,cur,m);
ans += m;
}
printf("%lld\n",A-q*ans);
return ;
}
if(n <= 1000) {
i64 sum = 0;
i64 cur = 0;
i64 m = 0;
FOR(i,1,n) {
cur += p;
if(cur >= q) {
m += 1;
cur -= q;
}
//printf("%d: %lld\n",i,m);
sum += m;
}
//printf("%lld %lld %lld\n",A,q,sum);
printf("%lld\n",A-q*sum);
return ;
}
vector<int> bucket(1000);
//vector<int> prefix(1000);
i64 ans = 0;
i64 cur = 0;
i64 m = 0;
i64 sum = 0;
FOR(i,1,1000) {
cur += p;
if(cur >= q) {
cur -= q;
m += 1;
}
bucket[i-1] = cur;
sum += m;
//ans += m;
}
sort(all(bucket));
//prefix[0] = bucket[0].y;
//FOR(i,1,999) prefix[i] = prefix[i-1]+bucket[i].y;
//peek the first few
// loop
i64 save_cur = cur;
i64 save_m = m;
i64 save_sum = sum;
// reset cur and m
cur = 0;
m = 0;
int i = 0;
while(n >= 1000) {
// cur, m
// ans
// binary search to update m and ans
//int idx = upper_bound(all(bucket), pii(cur,1<<30))-bucket.begin()-1;
int idx = lower_bound(all(bucket), q-cur)-bucket.begin();
/*
ans += m*1000+prefix[idx];
cur += save_cur;
if(cur >= q) cur -= q;
m += (idx+1);
*/
ans += m*1000 + save_sum + (1000-idx);
m = p*1ll*(i+1000)/q;
cur += save_cur;
if(cur >= q) cur -= q;
n -= 1000;
i += 1000;
}
FOR(i,1,n) {
cur += p;
if(cur >= q) {
cur -= q;
m += 1;
}
ans += m;
}
printf("%lld\n",A-q*ans);
}
int main() {
int q = readInt();
while(q--) {
solve();
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1274ms
memory: 3744kb
input:
91125 999956 999956 999956 999956 999956 999957 999956 999956 999958 999956 999956 999959 999956 999956 999960 999956 999956 999961 999956 999956 999962 999956 999956 999963 999956 999956 999964 999956 999956 999965 999956 999956 999966 999956 999956 999967 999956 999956 999968 999956 999956 999969 ...
output:
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 499956500946 499956500946 499957500902 499958500857 499959500811 499960500764 499961500716 499962500667 499963500617 499964500566 499965500514 499966500461 499967500407 499968500352 499969500296 499970500239 49...
result:
ok 91125 lines
Test #2:
score: 0
Accepted
time: 32ms
memory: 3716kb
input:
8000 1 1 1 1 1 2 1 1 3 1 1 4 1 1 5 1 1 6 1 1 7 1 1 8 1 1 9 1 1 10 1 1 999991 1 1 999992 1 1 999993 1 1 999994 1 1 999995 1 1 999996 1 1 999997 1 1 999998 1 1 999999 1 1 1000000 1 2 1 1 2 2 1 2 3 1 2 4 1 2 5 1 2 6 1 2 7 1 2 8 1 2 9 1 2 10 1 2 999991 1 2 999992 1 2 999993 1 2 999994 1 2 999995 1 2 999...
output:
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 2 2 3 3 4 4 5 5 499996 499996 499997 499997 499998 499998 499999 499999 500000 500000 1 3 3 4 6 6 7 9 9 10 999991 999993 999993 999994 999996 999996 999997 999999 999999 1000000 1 3 6 6 7 9 12 12 13 15 1499988 1499988 1499989 1499991 1499994 1499994 149999...
result:
ok 8000 lines
Test #3:
score: -100
Time Limit Exceeded
input:
100000 848401 999985 1000000 999527 999616 1000000 999789 999914 1000000 999479 999722 1000000 999841 999933 1000000 406226 999991 1000000 940598 999982 1000000 999708 999994 1000000 948123 999993 1000000 999789 999851 1000000 999522 999893 1000000 999977 999983 1000000 999912 999924 1000000 999232 ...
output:
499992309650 499992847584 499999028720 499990037714 499999288213 499994780341 499990845156 499998993982 499997047626 499998796124 499997350691 499999498946 499993962456 499999037615 499998396930 499994213619 499996210819 499998734816 499998193499 499997294296 499997311600 499997563064 499998257020 4...