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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#40069#2831. Game Theoryhit47WA 52ms7812kbC++1.8kb2022-07-16 01:01:502022-07-16 01:01:51

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-07-16 01:01:51]
  • 评测
  • 测评结果:WA
  • 用时:52ms
  • 内存:7812kb
  • [2022-07-16 01:01:50]
  • 提交

answer

#pragma GCC optimize(2)
#include<bits/stdc++.h>
#define ll long long 
const ll mod=998244353,N=2e5+10;
using namespace std;
int tree[N*4],lan[N*4],n;
char s[N];
void build(int root,int l,int r)
{
	lan[root]=0;
	if(l==r){
		tree[root]=(int)(s[l]-'0');
		return;
	}
	int mid=l+r>>1;
	build(root<<1,l,mid);
	build(root<<1|1,mid+1,r);
	tree[root]=tree[root<<1]+tree[root<<1|1];
}
void update(int root,int l,int r,int left,int right)
{
	if(lan[root])
	{
		lan[root]=0;
		int mid=l+r>>1;
		if(l!=r)lan[root<<1]=1,lan[root<<1|1]=1,tree[root<<1]=mid+1-l-tree[root<<1],tree[root<<1|1]=r-mid-tree[root<<1|1];
	}
	if(l>=left && r<=right)
	{
		tree[root]=r+1-l-tree[root];lan[root]=1;
		return;
	}
	if(l>right || r<left)return;
	int mid=l+r>>1;
	update(root<<1,l,mid,left,right);
	update(root<<1|1,mid+1,r,left,right);
	tree[root]=tree[root<<1]+tree[root<<1 | 1];
}
long long query(int root,int l,int r,int left,int right)
{
	if(lan[root])
	{
		lan[root]=0;
		int mid=l+r>>1;
		if(l!=r)lan[root<<1]=1,lan[root<<1|1]=1,tree[root<<1]=mid+1-l-tree[root<<1],tree[root<<1|1]=r-mid-tree[root<<1|1];
	}
	if(l>=left && r<=right)return tree[root];
	if(l>right || r<left)return 0;
	int mid=l+r>>1;
	return query(root<<1,l,mid,left,right)+query(root<<1|1,mid+1,r,left,right);
}
long long erfen(int l,int r)
{
	if(l==r)return 0;
	int mid=l+r>>1;
	long long l1=query(1,1,n,l,mid),r1=query(1,1,n,mid+1,r);
	long long res=0;
	res+=r1*(mid+1-l-l1);
	if(l1)res+=erfen(l,mid);
	if(r1)res+=erfen(mid+1,r);
	return res; 
}
int main()
{
	int q,i,j;
	long long ans,t;
	while(scanf("%d%d",&n,&q)!=EOF)
	{
		scanf("%s",s+1);
		build(1,1,n);
		for(i=1;i<=q;++i)
		{
			int l,r;
			scanf("%d%d",&l,&r);
			update(1,1,n,l,r);
			ans=erfen(1,n)+query(1,1,n,1,n);
			printf("%lld\n",ans%mod);
		}
	}
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 5768kb

input:

3 2
010
1 2
2 3
5 1
00000
1 5

output:

1
3
5

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 7812kb

input:

1 1
0
1 1

output:

1

result:

ok single line: '1'

Test #3:

score: -100
Wrong Answer
time: 52ms
memory: 5856kb

input:

2 2
01
2 2
2 2
2 2
01
1 2
1 2
1 2
1
1 1
1 1
1 2
1
1 1
1 1
2 2
00
1 2
1 2
2 2
11
1 2
1 2
2 2
01
2 2
1 1
2 2
10
2 2
1 2
2 2
01
1 2
1 2
1 2
0
1 1
1 1
2 2
01
1 2
2 2
1 2
0
1 1
1 1
1 2
1
1 1
1 1
2 2
10
1 2
1 1
1 2
0
1 1
1 1
2 2
01
1 2
1 2
2 2
10
1 2
1 1
1 2
0
1 1
1 1
1 2
0
1 1
1 1
1 2
1
1 1
1 1
2 2
10
1 ...

output:

0
2
1
2
0
1
0
1
2
0
0
2
0
1
2
0
1
2
1
0
1
2
1
0
0
1
2
2
1
0
1
2
2
2
1
0
1
0
0
1
0
1
0
2
2
1
0
1
2
1
1
0
2
0
2
2
1
0
0
1
2
0
0
1
0
1
0
1
1
0
1
2
2
0
0
2
0
1
0
1
1
0
1
0
1
0
0
1
0
1
0
1
2
0
2
0
1
0
0
1
1
0
1
0
1
2
0
2
1
0
0
2
1
2
0
1
2
2
1
0
0
1
2
0
2
0
0
1
0
1
1
0
1
0
1
0
1
0
1
2
1
0
2
1
0
2
0
1
0
1
...

result:

wrong answer 2nd lines differ - expected: '3', found: '2'