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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#398191#6630. Triangle CollectionSorahISA#0 0ms0kbC++202.3kb2024-04-25 07:20:562024-07-04 03:37:39

Judging History

你现在查看的是最新测评结果

  • [2024-07-04 03:37:39]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-04-25 07:20:56]
  • 提交

answer

#ifndef SorahISA
#define SorahISA
#include SorahISA __FILE__ SorahISA

void solve() {
    int N, Q; cin >> N >> Q;
    
    vector<int> C(N+1);
    for (int i = 1; i <= N; ++i) cin >> C[i];
    
    for (int q = 1; q <= Q; ++q) {
        int l, d; cin >> l >> d, C[l] += d;
        
        int ans = 0;
        auto L = C;
        for (int i = 1, j = 1, k = 1; i <= N; ++i) {
            if (L[i] < 2) continue;
            while (L[i] >= 2) {
                while (j <= min(2*i-1, N) and (~L[j] & 1)) ++j;
                while (k <= min(2*i-1, N) and L[k] == (k == i ? 2 : 0)) ++k;
                     if (j <= min(2*i-1, N)) L[i] -= 2, L[j] -= 1, ++ans; //, debug(i, i, j);
                else if (k <= min(2*i-1, N)) L[i] -= 2, L[k] -= 1, ++ans; //, debug(i, i, k);
            }
        }
        cout << ans << "\n";
    }
}

int32_t main() {
    fastIO();
    
    int t = 1; // cin >> t;
    for (int _ = 1; _ <= t; ++_) {
        solve();
    }
    
    return 0;
}

#else

#ifdef local
#define _GLIBCXX_DEBUG 1
#endif
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;

using i64 = long long;
#define int i64
using f80 = long double;
#define double f80
using pii = pair<int, int>;
template <typename T> using Prior = std::priority_queue<T>;
template <typename T> using prior = std::priority_queue<T, vector<T>, greater<T>>;

#define eb emplace_back
#define ef emplace_front
#define ee emplace
#define pb pop_back
#define pf pop_front
#define ALL(x) begin(x), end(x)
#define RALL(x) rbegin(x), rend(x)
#define SZ(x) ((int)(x).size())

#ifdef local
#define fastIO() void()
#define debug(...) \
    fprintf(stderr, "\u001b[33m"), \
    fprintf(stderr, "At [%s], line %d: (%s) = ", __FUNCTION__, __LINE__, #__VA_ARGS__), \
    _do(__VA_ARGS__), \
    fprintf(stderr, "\u001b[0m")
template <typename T> void _do(T &&_t) { cerr << _t << "\n"; }
template <typename T, typename ...U> void _do(T &&_t, U &&..._u) { cerr << _t << ", ", _do(_u...); }
#else
#define fastIO() ios_base::sync_with_stdio(0), cin.tie(0)
#define debug(...) void()
#endif

template <typename T, typename U> bool chmin(T &lhs, U rhs) { return lhs > rhs ? lhs = rhs, 1 : 0; }
template <typename T, typename U> bool chmax(T &lhs, U rhs) { return lhs < rhs ? lhs = rhs, 1 : 0; }

#endif

詳細信息

Subtask #1:

score: 0
Time Limit Exceeded

Test #1:

score: 0
Time Limit Exceeded

input:

1 23
1485
1 -12
1 -30
1 -20
1 6
1 24
1 5
1 31
1 14
1 -34
1 -22
1 -45
1 37
1 46
1 9
1 22
1 -9
1 9
1 -46
1 -47
1 39
1 36
1 -36
1 50

output:


result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Time Limit Exceeded

Test #28:

score: 0
Time Limit Exceeded

input:

1999 2000
1 1 1 1 0 2 0 2 1 0 2 1 2 2 2 1 2 0 0 1 2 2 0 1 0 1 0 2 0 0 2 1 1 1 1 0 1 2 1 2 1 1 1 1 1 0 2 2 0 2 1 1 2 0 0 2 0 0 2 1 2 0 0 1 1 2 0 2 2 2 1 2 0 2 1 2 0 1 2 2 2 1 1 2 1 1 1 1 0 0 1 1 0 1 2 1 0 0 2 0 2 2 2 0 1 1 2 0 0 1 0 0 2 1 2 1 2 0 1 1 2 2 0 0 1 2 2 1 2 1 2 2 2 0 0 1 1 2 1 1 2 2 2 2 2 ...

output:


result:


Subtask #4:

score: 0
Time Limit Exceeded

Test #35:

score: 0
Time Limit Exceeded

input:

2000 1999
0 1 0 3 0 1 0 0 0 0 0 0 0 2 0 0 0 0 3 1 1 0 2 0 0 3 0 0 0 0 0 4 0 0 1 0 1 0 0 0 0 1 2 1 0 0 0 0 7 0 1 3 1 0 1 1 0 3 2 1 0 1 1 3 3 1 0 2 0 0 0 0 0 0 0 0 1 0 0 0 2 0 0 0 0 0 1 2 3 0 1 0 3 3 0 0 0 0 1 0 1 2 0 0 2 2 0 1 2 1 2 0 0 0 1 1 0 1 2 0 0 0 0 2 0 5 0 0 0 0 0 1 0 0 2 0 1 2 0 1 0 0 0 2 0 ...

output:


result:


Subtask #5:

score: 0
Skipped

Dependency #1:

0%