QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#391570#2161. The Cost of Speed LimitsRobeZHWA 0ms3652kbC++231.9kb2024-04-16 17:13:522024-04-16 17:13:53

Judging History

你现在查看的是最新测评结果

  • [2024-04-16 17:13:53]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3652kb
  • [2024-04-16 17:13:52]
  • 提交

answer

#pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include<bits/stdc++.h>
// #include<atcoder/all>
#define FR(i,n) for(int i=0;i<n;++i)
// #define rep(i,n) for(int i=1;i<=n;++i)
#define eb emplace_back
#define st first
#define nd second
#define x1 fxxkcjb
#define y1 fxxkyzc
#define x2 fxxkzzy
#define y2 fxxknitit
using namespace std;
namespace R=ranges;
template<typename T>
using func=function<T>;
template<typename T>
using vec=vector<T>;
using ll=long long;
using ld=long double;
using i128=__int128;
using pii=pair<int,int>;
const int inf=(int)2e9+9;
void sol(){
    int n,c;cin>>n>>c;
    vector g(n,vector<pii>());
    vector<int>len(n-1);
    FR(tim,n-1){
        int u,v,w;cin>>u>>v>>w;--u,--v;
        g[u].eb(v,w);g[v].eb(u,w);
        len[tim]=w;
    }
    vector dp(n,vector<int>(n-1));
    vector<ll>dp2(n-1);
    func<void(int,int,int)>dfs=[&](int x,int fa,int lalen){
        // cerr<<x<<endl;
        if(x!=0){
            FR(i,n-1)dp[x][i]=(len[i]<lalen?inf:len[i]-lalen);
        }else{
            FR(i,n-1)dp[x][i]=dp2[i]=0;
        }
        for(auto[y,dis]:g[x])if(y!=fa){
            dfs(y,x,dis);
            FR(i,n-1)dp[x][i]=min((ll)inf,(ll)dp[x][i]+dp[y][i]);
        }
        if(x!=0){
            FR(i,n-1)dp2[i]=dp[x][i]+c;
        }else{
            FR(i,n-1)dp2[i]=0;
        }
        for(auto[y,dis]:g[x])if(y!=fa){
            ll mi=R::min(dp[y]);
            FR(i,n-1)dp2[i]=min((ll)inf,(ll)dp2[i]+c+mi);
        }
        FR(i,n-1){
            dp[x][i]=min((ll)dp[x][i],dp2[i]);
            // cerr<<x<<" "<<i<<" "<<dp[x][i]<<endl;
        }
    };
    dfs(0,-1,-1);
    int ans=dp[0][0];
    FR(i,n-1)ans=min(ans,dp[0][i]);
    cout<<ans<<"\n";
}
int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    sol();
    return 0;
}
/*
5 2
1 2 10
1 3 5
1 4 7
2 5 9
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3652kb

input:

13 20
1 8 101
1 9 30
1 2 100
1 3 100
2 4 75
2 5 70
2 6 82
2 7 77
3 10 73
3 11 69
3 12 83
3 13 79

output:

272

result:

ok single line: '272'

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3640kb

input:

9 10
1 6 26
2 6 27
3 6 28
4 6 29
5 6 30
7 9 14
8 9 1
9 6 10

output:

75

result:

wrong answer 1st lines differ - expected: '60', found: '75'