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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#389985 | #1817. AND Permutation | black_moonrise# | WA | 0ms | 3872kb | C++14 | 3.3kb | 2024-04-14 23:12:39 | 2024-04-14 23:12:39 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e5 + 5;
const int MAXP = 1e7 + 5;
const int P = 1e9 + 7;
typedef long long ll;
int inv[7];
int power(int x, int y) {
if (y == 0) return 1;
int tmp = power(x, y / 2);
if (y % 2 == 0) return 1ll * tmp * tmp % P;
else return 1ll * tmp * tmp % P * x % P;
}
struct SegmentTree {
struct Node {
int lc, rc;
int ret[6], cnt[6];
} a[MAXP];
int size, n;
void init(int x) {
n = x;
}
void update(int root) {
for (int i = 0; i < 6; i++) {
a[root].cnt[i] = min(a[a[root].lc].cnt[i] + a[a[root].rc].cnt[i], P);
a[root].ret[i] = (a[a[root].lc].ret[i] + a[a[root].rc].ret[i]) % P;
}
}
int modify(int root, int l, int r, int pos, int v) {
int ans = ++size;
a[ans] = a[root];
int tret = 1;
int tcnt = 1;
for (int i = 0; i < 6; i++) {
a[ans].cnt[i] = min(a[ans].cnt[i] + tcnt, P);
a[ans].ret[i] = (a[ans].ret[i] + tret) % P;
tcnt = min(1ll * tcnt * (v + i) / (i + 1), (ll) P);
tret = 1ll * tret * (v + i) % P * inv[i + 1] % P;
}
if (l == r) return ans;
int mid = (l + r) / 2;
if (mid >= pos) a[ans].lc = modify(a[ans].lc, l, mid, pos, v);
else a[ans].rc = modify(a[ans].rc, mid + 1, r, pos, v);
update(ans);
return ans;
}
int modify(int root, int pos, int v) {
return modify(root, 1, n, pos, v);
}
pair <int, int> query(int root, int l, int r, int k, int s) {
if (l == r) return make_pair(l, 0);
int mid = (l + r) / 2;
if (a[a[root].lc].cnt[s] > k) return query(a[root].lc, l, mid, k, s);
else {
pair <int, int> tmp = query(a[root].rc, mid + 1, r, k - a[a[root].lc].cnt[s], s);
tmp.second += a[a[root].lc].cnt[s];
return tmp;
}
}
pair <int, int> query(int root, int k, int s) {
if (k >= a[root].cnt[s]) return make_pair(n + 1, a[root].cnt[s]);
else return query(root, 1, n, k, s);
}
int conv[6];
int sum(int root, int l, int r, int qr, int s) {
if (qr >= r) {
int ans = 0;
for (int i = 0; i <= s; i++)
ans = (ans + 1ll * conv[i] * a[root].ret[s - i]) % P;
return ans;
}
if (l > qr) return 0;
int mid = (l + r) / 2;
return (sum(a[root].lc, l, mid, qr, s) + sum(a[root].rc, mid + 1, r, qr, s)) % P;
}
int sum(int root, int r, int x, int s) {
if (r <= 0) return 0;
int tmp = 1;
for (int i = 0; i <= s; i++) {
conv[i] = tmp;
tmp = 1ll * tmp * (P - x - i) % P * inv[i + 1] % P;
}
return sum(root, 1, n, r, s);
}
} ST;
int n, s, q, a[MAXN], p[MAXN], root[MAXN];
int query(int rt, int qr, int x, int s) {
if (s == 0) return rt >= x && p[x] <= qr;
else return ST.sum(root[rt], qr, x - 1, s - 1);
}
int main() {
scanf("%d%d%d", &n, &s, &q);
for (int i = 1; i <= s; i++)
inv[i] = power(i, P - 2);
for (int i = 1; i <= n; i++) {
scanf("%d", &a[i]);
p[a[i]] = i;
}
ST.init(n);
for (int i = 1; i <= n; i++)
root[i] = ST.modify(root[i - 1], p[i], i);
for (int i = 1; i <= q; i++) {
int k, x; scanf("%d%d", &x, &k);
int rt = n, ans = 0;
for (int j = s - 1; j >= 0; j--) {
pair <int, int> tmp;
tmp = ST.query(root[rt], k, j);
ans = (ans + query(rt, tmp.first - 1, x, j)) % P;
ans = (ans - query(x - 1, tmp.first - 1, x + 1, j) + P) % P;
if (tmp.first > n) break;
else {
rt = a[tmp.first];
k -= tmp.second;
}
}
printf("%d\n", ans);
}
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3872kb
input:
6 0 1 4 5 2 6
output:
0
result:
wrong output format Unexpected end of file - int64 expected