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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#389385#3272. 简单数据结构SamponYW20 58ms10624kbC++145.1kb2024-04-14 10:51:122024-04-14 10:51:12

Judging History

你现在查看的是最新测评结果

  • [2024-04-14 10:51:12]
  • 评测
  • 测评结果:20
  • 用时:58ms
  • 内存:10624kb
  • [2024-04-14 10:51:12]
  • 提交

answer

#include <bits/stdc++.h>
#define db double
#define il inline
#define re register
#define ll long long
#define ui unsigned
#define ull ui ll
#define i128 __int128
#define pii pair<int, int>
#define fi first
#define se second
#define eb emplace_back
#define SZ(v) (int)v.size()
#define ALL(v) v.begin(), v.end()
#define mems(v, x) memset(v, x, sizeof(v))
#define memc(a, b) memcpy(a, b, sizeof(a))
#define FOR(i, L, R) for(re int i = (L); i <= (R); ++i)
#define ROF(i, R, L) for(re int i = (R); i >= (L); --i)
#define LS i << 1, l, mid
#define RS i << 1 | 1, mid + 1, r
#define popc(x) __builtin_popcount(x)
using namespace std;
#define N 200005
int n, m, a[N], cnt[N];
struct op {int op, a, b; ll v;} p[N];
vector<int> ins[N];
namespace Lseg {
  struct Line {
    int k; ll b;
    il ll F(ll x) {return k * x + b;}
  } T[N];
  int rt, cnt, ls[N], rs[N];
  il void clr() {FOR(i, 1, cnt) ls[i] = rs[i] = 0; rt = 0;}
  il void insert(int &i, Line v, int l = 1, int r = n) {
    if(!i) {T[i = ++cnt] = v; return ;} int mid = l + r >> 1;
    if(T[i].F(mid) > v.F(mid)) swap(T[i], v);
    if(T[i].F(l) > v.F(l)) insert(ls[i], v, l, mid);
    if(T[i].F(r) > v.F(r)) insert(rs[i], v, mid + 1, r);
  }
  il void ins(int k, ll b) {insert(rt, {k, b});}
  il ll query(int i, int p, int l = 1, int r = n) {
    if(!i) return 1e18; ll s = T[i].F(p);
    if(l == r) return s; int mid = l + r >> 1;
    if(mid >= p) s = min(s, query(ls[i], p, l, mid));
    else s = min(s, query(rs[i], p, mid + 1, r)); return s;
  }
  il ll qry(int p) {return query(rt, p);}
}
/*
a[i] + i * cnt[j] >= v[j]
v[j] - i * cnt[j] <= a[i]
*/
il void solve(int l, int r, vector<int> &q) {
  if(q.empty()) return ;
  if(l == r) {for(auto x : q) ins[r].eb(x); return ;}
  int mid = l + r >> 1; vector<int> Lq, Rq;
  Lseg::clr(); FOR(i, l, mid) if(p[i].op == 1) Lseg::ins(-cnt[i], p[i].v);
  for(auto x : q) if(Lseg::qry(x) <= a[x]) Lq.eb(x); else Rq.eb(x);
  solve(l, mid, Lq), solve(mid + 1, r, Rq);
}
struct segt {
  ll s[N * 4], is[N * 4];
  int cnt[N * 4], tag[N * 4], mxr[N * 4];
  ll mx[N * 4]; int md[N * 4];
  il void build(int i = 1, int l = 1, int r = n) {
    md[i] = -1; if(l == r) return ;
    int mid = l + r >> 1; build(LS), build(RS);
  }
  il void pushup(int i) {
    int L = i << 1, R = L | 1;
    s[i] = s[L] + s[R], is[i] = is[L] + is[R], cnt[i] = cnt[L] + cnt[R];
    mxr[i] = max(mxr[L], mxr[R]), mx[i] = max(mx[L], mx[R]);
  }
  il void mpu(int i, int v) {
    s[i] = 1ll * cnt[i] * v, mx[i] = md[i] = v;
  }
  il void push(int i, int v) {
    s[i] += is[i] * v, tag[i] += v;
    mx[i] += 1ll * mxr[i] * v;
  }
  il void pushdown(int i) {
    int L = i << 1, R = L | 1;
    if(~md[i]) mpu(L, md[i]), mpu(R, md[i]), md[i] = -1;
    if(tag[i]) push(L, tag[i]), push(R, tag[i]), tag[i] = 0;
  }
  il void upd(int x, int v, int i = 1, int l = 1, int r = n) {
    if(l == r) {
      if(~v) mx[i] = s[i] = v, mxr[i] = is[i] = x, cnt[i] = 1;
      else mx[i] = s[i] = mxr[i] = is[i] = cnt[i] = 0; return ;
    }
    int mid = l + r >> 1; pushdown(i);
    if(mid >= x) upd(x, v, LS); else upd(x, v, RS); pushup(i);
  }
  il ll query(int el, int er, int i = 1, int l = 1, int r = n) {
    if(l >= el && r <= er) return s[i]; int mid = l + r >> 1; pushdown(i); ll ns = 0;
    if(mid >= el) ns += query(el, er, LS); if(mid < er) ns += query(el, er, RS); return ns;
  }
  il int binary(int el, int er, ll v, int i = 1, int l = 1, int r = n) {
    if(!cnt[i]) return -1; if(l >= el && r <= er) {if(mx[i] < v) return -1; if(l == r) return r;}
    int mid = l + r >> 1, ns = -1; pushdown(i); if(mid >= el) ns = binary(el, er, v, LS);
    if(~ns) return ns; if(mid < er) ns = binary(el, er, v, RS); return ns;
  }
  il void mdf(int el, int er, ll v, int i = 1, int l = 1, int r = n) {
    if(!cnt[i]) return ; if(l >= el && r <= er) return mpu(i, v); int mid = l + r >> 1; pushdown(i);
    if(mid >= el) mdf(el, er, v, LS); if(mid < er) mdf(el, er, v, RS); pushup(i);
  }
  il void op() {push(1, 1);}
  il void odt(int l, int r, ll v) {int k = binary(l, r, v); if(~k) mdf(k, r, v);}
  il void print(int i = 1, int l = 1, int r = n) {
    if(l == r) return ;
    if(l == r) {cout << s[i] << " \n"[r == n]; return ;}
    int mid = l + r >> 1; pushdown(i);
    print(LS), print(RS);
  }
} s, t;
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0), cout.tie(0);
  cin >> n >> m;
  FOR(i, 1, n) cin >> a[i];
  vector<pii> pos; int tot = 0;
  FOR(i, 1, m) {
    auto &[op, a, b, v] = p[i];
    cin >> op;
    if(op == 1) cin >> v;
    if(op == 2) ++tot;
    if(op == 3) cin >> a >> b;
    cnt[i] = tot;
  }
  vector<int> q;
  FOR(i, 1, n) q.eb(i);
  solve(1, m + 1, q);
  s.build(), t.build();
  FOR(i, 1, n) s.upd(i, a[i]);
  FOR(i, 1, m) {
    auto [op, a, b, v] = p[i];
    for(auto x : ins[i]) s.upd(x, -1), t.upd(x, v);
    // for(auto x : ins[i]) cerr << x << " " << i << "\n";
    if(op == 1) t.odt(1, n, v); if(op == 2) s.op(), t.op();
    if(op == 3) cerr << i << "\n", cout << s.query(a, b) + t.query(a, b) << "\n";
    // if(i == 5) t.print();
    // if(i == 6) t.print();
    t.print();
  }
  cerr << 1.0 * clock() / CLOCKS_PER_SEC << "\n";
  return 0;
}

詳細信息

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 10
Accepted
time: 58ms
memory: 10452kb

input:

5000 5000
29940 259997 53132 912489 608312 594283 432259 344137 889466 383028 320097 337418 571199 372832 563110 542407 133378 998389 238387 120880 477310 634888 191990 133585 935315 558139 141724 893331 190118 991968 843042 384930 935256 891482 123419 91431 955722 376987 197566 106433 234494 645967...

output:

512185934
455189773
121665669
408693244
291779262
45671866
242375008
302245547
222004631
41963113
343434445
347127029
183849524
2144625
278637672
220461451
20719635
108759503
22099550
34631220
55848925
92362584
36949030
86469096
43509864
50829332
1334865
76069109
114623436
13564322
79974466
15230088...

result:

ok 1671 numbers

Test #2:

score: -10
Wrong Answer
time: 35ms
memory: 9644kb

input:

5000 5000
754848159362 799142221874 945332296572 929342054343 220343371940 207059247564 870301066785 609144766745 830351478389 198801101804 768950635554 592202774571 800496073014 730985048260 581401590014 934021096780 587980626010 77068543347 206074783770 390850923112 122794404396 281461236458 11092...

output:


result:

wrong answer Answer contains longer sequence [length = 1647], but output contains 0 elements

Subtask #2:

score: 20
Accepted

Subtask #3:

score: 0
Wrong Answer

Test #1:

score: 15
Accepted
time: 57ms
memory: 10624kb

input:

5000 5000
29940 259997 53132 912489 608312 594283 432259 344137 889466 383028 320097 337418 571199 372832 563110 542407 133378 998389 238387 120880 477310 634888 191990 133585 935315 558139 141724 893331 190118 991968 843042 384930 935256 891482 123419 91431 955722 376987 197566 106433 234494 645967...

output:

512185934
455189773
121665669
408693244
291779262
45671866
242375008
302245547
222004631
41963113
343434445
347127029
183849524
2144625
278637672
220461451
20719635
108759503
22099550
34631220
55848925
92362584
36949030
86469096
43509864
50829332
1334865
76069109
114623436
13564322
79974466
15230088...

result:

ok 1671 numbers

Test #2:

score: -15
Wrong Answer
time: 35ms
memory: 9428kb

input:

5000 5000
754848159362 799142221874 945332296572 929342054343 220343371940 207059247564 870301066785 609144766745 830351478389 198801101804 768950635554 592202774571 800496073014 730985048260 581401590014 934021096780 587980626010 77068543347 206074783770 390850923112 122794404396 281461236458 11092...

output:


result:

wrong answer Answer contains longer sequence [length = 1647], but output contains 0 elements

Subtask #4:

score: 0
Skipped

Dependency #1:

0%