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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#380031#8570. Idola-Treeucup-team191#WA 1636ms56744kbC++232.0kb2024-04-06 20:44:352024-04-06 20:44:35

Judging History

你现在查看的是最新测评结果

  • [2024-04-06 20:44:35]
  • 评测
  • 测评结果:WA
  • 用时:1636ms
  • 内存:56744kb
  • [2024-04-06 20:44:35]
  • 提交

answer

#include <bits/stdc++.h>
#define x first
#define y second
using namespace std;
using ll=long long;
using pii=pair<int,int>;
using vi=vector<int>;
using vl=vector<ll>;
#define pb push_back
#define all(a) begin(a),end(a)

const int N=300010,MOD=998244353,M=5e7+10;
const char en='\n';
const ll LLINF=1ll<<60;

int t,n,k,ss[N],par[N];
ll sussI[N],sussO[N];
ll st[M];
vi ch[N],ch1[N];

void dfs(int i,int p=0)
{
	ss[i]=1;
	sussI[i]=0;
	par[i]=p;
	for (auto x: ch[i]) if (x!=p)
	{
		dfs(x,i);
		ch1[i].pb(x);
		ss[i]+=ss[x];
		sussI[i]+=sussI[x];
	}
	sussI[i]+=ss[i];
}

void dfs2(int i)
{
	ll su=sussO[i];
	for (auto x: ch1[i]) su+=sussI[x];
	for (auto x: ch1[i])
	{
		sussO[x]=su-sussI[x]+(n-ss[x]);
		dfs2(x);
	}
}

int mul(int a,int b)
{
	return a*1ll*b%MOD;
}

int sq(int a)
{
	return mul(a,a);
}

int cb(int a)
{
	return mul(a,sq(a));
}

void ad(int&a,int b)
{
	a+=b;
	if (a>=MOD) a-=MOD;
}

int add(int a,int b)
{
	if (a+b>=MOD) return a+b-MOD;
	return a+b;
}

int main()
{
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	cin>>t;
	while (t--)
	{
		cin>>n>>k;
		for (int i=1;i<=n;++i) ch[i].clear(),ch1[i].clear();
		for (int i=1;i<n;++i)
		{
			int a,b;
			cin>>a>>b;
			ch[a].pb(b);
			ch[b].pb(a);
		}
		if (n==2)
		{
			int an=0;
			for (int i=1;i<=k;++i) ad(an,cb(sq(i)));
			cout<<an<<en;
			continue;
		}
		k-=n-1;
		int ro=1;
		while (ch[ro].size()==1) ++ro;
		sussO[ro]=0;
		dfs(ro);
		dfs2(ro);
		ll po=0;
		for (int i=2;i<=n;++i) po+=ss[i]*1ll*sussO[i]+(n-ss[i])*1ll*sussI[i]-ss[i]*1ll*(n-ss[i]);
		vl vals;
		for (int i=1;i<=n;++i) if (ch[i].size()==1) vals.pb(2*sussO[i]+n-2+1);
		sort(all(vals));
		queue<ll> q;
		po%=MOD;
		int pt=1,an=cb(po),vs=vals.size();
		q.push(vals[0]);
		//cout<<po<<en;
		for (int i=0;i<k;++i)
		{
			ll u=q.front();
			q.pop();
			po=(po+u+2*i)%MOD;
			//cout<<po<<en;
			ad(an,cb(po));
			ll nov=u+2*(n-2);
			while (pt<vs && vals[pt]<nov) q.push(vals[pt]),++pt;
			q.push(nov);
		}
		cout<<an<<en;
	}
}

详细

Test #1:

score: 100
Accepted
time: 2ms
memory: 9584kb

input:

2
4 3
1 4
1 3
2 1
4 4
1 4
1 3
2 1

output:

3375
25327

result:

ok 2 tokens

Test #2:

score: 0
Accepted
time: 0ms
memory: 11812kb

input:

4
4 3
1 4
1 3
2 1
4 4
1 4
1 3
2 1
5 4
1 4
1 3
1 2
5 4
5 5
1 4
1 3
1 2
5 4

output:

3375
25327
54872
249984

result:

ok 4 tokens

Test #3:

score: -100
Wrong Answer
time: 1636ms
memory: 56744kb

input:

4
300000 50000000
216838 200677
44849 12926
125086 157230
26195 29767
241694 21336
21336 24457
105861 84565
184655 45583
175336 97945
286044 30927
295273 249694
109469 1566
193560 251229
176229 288707
206166 13532
166218 264413
299977 95587
159105 48116
57912 82606
97296 193689
115029 121192
68068 1...

output:

794192074
705873422
585085721
388230489

result:

wrong answer 1st words differ - expected: '968050473', found: '794192074'