QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#375720 | #2833. Hamilton | Tx_Lcy | WA | 1ms | 3948kb | C++14 | 1.3kb | 2024-04-03 15:10:59 | 2024-04-03 15:11:00 |
Judging History
answer
//A tree without skin will surely die.
//A man without face will be alive.
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define mid ((l+r)>>1)
#define lowbit(x) (x&-x)
#define all(x) (x).begin(),(x).end()
#define rep(i,j,k) for (int i=j;i<=k;++i)
#define per(i,j,k) for (int i=j;i>=k;--i)
int const N=2e3+10;
string s[N];
int n,a[N][N],p[N];
inline void add(int x,int y){
vector<int>g;g.push_back(y);
rep(i,x+1,n)
if (p[i]) g.push_back(p[i]);
rep(i,1,x) g.push_back(p[i]);
rep(i,1,g.size()) p[i]=g[i-1];
}
inline void solve(){
while (cin>>n){
rep(i,1,n) cin>>s[i],s[i]=" "+s[i];
rep(i,1,n) rep(j,1,n) a[i][j]=s[i][j]-'0';
rep(i,1,n) p[i]=0;
p[1]=1,p[2]=2;
rep(i,3,n){
int pl=0;
rep(j,1,i-1)
if (a[p[j]][p[j%n+1]] && !a[p[j%n+1]][p[(j%n+1)%n+1]]){pl=j+1;break;}
if (pl){
if (!a[p[i]][p[pl%n+1]]) add(pl,i);
else add(pl%n+1,i);
}else add(i-1,i);
}
int tag=1;
rep(i,1,n-1)
if (a[p[i]][p[i%n+1]]!=a[p[i%n+1]][p[(i%n+1)%n+1]]){tag=i%n+1;break;}
rep(i,tag,n) cout<<p[i]<<' ';
rep(i,1,tag-1) cout<<p[i]<<' ';
cout<<'\n';
}
}
signed main(){
ios::sync_with_stdio(false);
cin.tie(0),cout.tie(0);
int t=1;
// cin>>t;
while (t--) solve();
cerr<<"Time: "<<(double)clock()/CLOCKS_PER_SEC<<" s\n";
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3948kb
input:
3 001 000 100 4 0000 0000 0000 0000
output:
1 2 3 4 3 1 2
result:
ok 2 cases.
Test #2:
score: 0
Accepted
time: 0ms
memory: 3936kb
input:
3 000 000 000 3 010 100 000 3 011 100 100 3 011 101 110
output:
3 1 2 1 2 3 2 3 1 3 1 2
result:
ok 4 cases.
Test #3:
score: -100
Wrong Answer
time: 0ms
memory: 3944kb
input:
4 0000 0000 0000 0000 4 0000 0001 0000 0100 4 0100 1010 0100 0000 4 0111 1000 1000 1000 4 0010 0011 1101 0110 4 0111 1011 1100 1100 4 0111 1011 1101 1110 4 0000 0011 0101 0110 4 0101 1010 0100 1000 4 0011 0011 1100 1100 4 0010 0001 1000 0100
output:
4 3 1 2 2 4 3 1 1 2 4 3 3 1 2 4 1 4 2 3 3 1 2 4 4 3 1 2 3 1 2 4 1 2 4 3 4 2 3 1 2 3 1 4
result:
wrong answer case #11: found 3 indices