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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#359359#410. Telegraphjerzyk0 1ms3856kbC++202.3kb2024-03-20 16:56:522024-03-20 16:56:53

Judging History

你现在查看的是最新测评结果

  • [2024-03-20 16:56:53]
  • 评测
  • 测评结果:0
  • 用时:1ms
  • 内存:3856kb
  • [2024-03-20 16:56:52]
  • 提交

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
using namespace __gnu_pbds;
using namespace std;
#define pb push_back
#define st first
#define nd second
typedef long long ll;
typedef long double ld;
const ll I = 1000LL * 1000LL * 1000LL * 1000LL * 1000LL * 1000LL;
const ll M = 1000LL * 1000LL * 1000LL + 7LL;
const int N = 1<<17;
bool czd[N];
ll cst[N], dp[N];
vector<int> ed[N];
int il[N], poi[N];

int LiczD(int n)
{
    int v, cnt = 0;
    queue<int> q;
    for(int i = 1; i <= n; ++i)
        if(il[i] == 0) q.push(i);

    while(q.size() > 0)
    {
        ++cnt;
        v = q.front(); q.pop(); 
        czd[v] = true;
        ll ma = 0;
        for(int i = 0; i < (int)ed[v].size(); ++i)
            {dp[v] += dp[ed[v][i]] + cst[ed[v][i]]; ma = max(ma, cst[ed[v][i]]);}
        dp[v] -= ma;
        --il[poi[v]];
        if(il[poi[v]] == 0)
            q.push(poi[v]);
    }
    return cnt;
}

ll LiczC(int v)
{
    ll ans = 0LL, ma = -I;
    int x = poi[v];
    vector<int> ver;
    ver.pb(v);
    while(x != v)
    {
        ver.pb(x);
        x = poi[x];
    }
    for(int i = 0; i < (int)ver.size(); ++i)
    {
        int pr; 
        if(i > 0) pr = ver[i - 1];
        else pr = ver.back();
        v = ver[i]; 
        ll cur = 0LL;
        for(int j = 0; j < (int)ed[v].size(); ++j)
            if(czd[ed[v][j]])
                {ans += dp[ed[v][j]] + cst[ed[v][j]]; cur = max(cur, cst[ed[v][j]]);}


        cur -= cst[pr];
        ma = max(ma, cur);
        //cout << "cycle: " << v << " " << cur << " " << ma << " " << ans << "\n";
    }
    for(int i = 0; i < (int)ver.size(); ++i)
        czd[ver[i]] = true;

    ans -= ma;
    return ans;
}

void Solve()
{
    int n, xd;
    ll ans = 0LL;
    cin >> n;
    for(int i = 1; i <= n; ++i)
    {
        cin >> poi[i] >> cst[i];
        ed[poi[i]].pb(i); ++il[poi[i]];
    }
    xd = LiczD(n);
    for(int i = 1; i <= n; ++i)
        if(!czd[i])
        {
            ++xd;
            ans += LiczC(i);
        }
    
    if(xd == 1)
        cout << 0 << "\n";
    else
        cout << ans << "\n";
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    //int t; cin >> t;
    //while(t--)
        Solve();

    return 0;
}

詳細信息

Subtask #1:

score: 0
Wrong Answer

Test #1:

score: 10
Accepted
time: 1ms
memory: 3608kb

input:

10
3 85377744
3 191391530
4 553475509
8 344887257
9 812158120
1 880268352
4 686078706
7 182546394
4 220137367
3 89957933

output:

1081551750

result:

ok single line: '1081551750'

Test #2:

score: 0
Accepted
time: 1ms
memory: 3856kb

input:

10
3 688989554
5 112566798
1 294281317
1 96941112
6 746415334
2 612836992
9 629868215
1 406822326
10 638640051
8 199983696

output:

503789227

result:

ok single line: '503789227'

Test #3:

score: 0
Accepted
time: 1ms
memory: 3608kb

input:

10
3 292601364
7 33742065
7 35087125
3 996478615
4 828156197
3 197921984
8 426174077
4 631098259
5 57142735
5 457493107

output:

1212506407

result:

ok single line: '1212506407'

Test #4:

score: 0
Accepted
time: 1ms
memory: 3852kb

input:

10
6 43696822
9 954917333
7 923376581
5 896016118
1 762413411
4 930490625
3 369963586
9 855374192
2 475645419
1 567518871

output:

1936096612

result:

ok single line: '1936096612'

Test #5:

score: -10
Wrong Answer
time: 0ms
memory: 3784kb

input:

10
6 647308632
3 876092601
4 664182389
6 648069973
7 844154274
5 663059265
1 166269448
3 79650124
7 894148102
7 825028282

output:

2396902653

result:

wrong answer 1st lines differ - expected: '2396141312', found: '2396902653'

Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Skipped

Dependency #1:

0%

Subtask #4:

score: 0
Skipped

Dependency #1:

0%