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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#348503#7860. Graph of Maximum Degree 3chenxinyang2006#RE 2ms9172kbC++141.9kb2024-03-09 19:04:312024-03-09 19:04:31

Judging History

你现在查看的是最新测评结果

  • [2024-03-09 19:04:31]
  • 评测
  • 测评结果:RE
  • 用时:2ms
  • 内存:9172kb
  • [2024-03-09 19:04:31]
  • 提交

answer

#include <bits/stdc++.h>
#define rep(i,j,k) for(int i=(j);i<=(k);i++)
#define per(i,j,k) for(int i=(j);i>=(k);i--)
#define uint unsigned int
#define ll long long
#define ull unsigned long long
#define db double
#define ldb long double
#define pii pair<int,int>
#define pll pair<ll,ll>
#define mkp make_pair
#define eb emplace_back
#define SZ(S) (int)S.size()
//#define mod 998244353
//#define mod 1000000007
#define inf 0x3f3f3f3f
#define linf 0x3f3f3f3f3f3f3f3f
using namespace std;

template <class T>
void chkmax(T &x,T y){
	if(x < y) x = y;
}

template <class T>
void chkmin(T &x,T y){
	if(x > y) x = y;
}

inline int popcnt(int x){
	return __builtin_popcount(x);
}

inline int ctz(int x){
	return __builtin_ctz(x);
}


/*ll power(ll p,int k = mod - 2){
	ll ans = 1;
	while(k){
		if(k % 2 == 1) ans = ans * p % mod;
		p = p * p % mod;
		k /= 2;	
	}
	return ans;
}*/
int n,m;
vector <int> G[2][100005];
int _u[100005],_v[100005],_c[100005];

int chk(int c,int u,int v){
	int pos = lower_bound(G[c][u].begin(),G[c][u].end(),v) - G[c][u].begin();
	if(pos < SZ(G[c][u]) && G[c][u][pos] == v) return 1;
	return 0;
}

int main(){
//	freopen("test.in","r",stdin);
	scanf("%d%d",&n,&m);
	rep(i,1,m){
		scanf("%d%d%d",&_u[i],&_v[i],&_c[i]);
		G[_c[i]][_u[i]].eb(_v[i]);
		G[_c[i]][_v[i]].eb(_u[i]);
	}
	rep(u,1,n){
		sort(G[0][u].begin(),G[0][u].end());
		sort(G[1][u].begin(),G[1][u].end());
	}

	int ans = 0;
	rep(u,1,n){
		for(int v:G[0][u]) if(v < u) ans += chk(1,u,v);
		for(int v:G[0][u]){
			for(int w:G[0][u]){
				if(v >= w) continue;
				ans += (chk(1,u,v) + chk(1,u,w) + chk(1,v,w) >= 2);
			}
		}
	}
	rep(i,1,m){
		if(_c[i]) continue;
		for(int u:G[0][_u[i]]){
			for(int v:G[0][_v[i]]){
				if(u == v || u == _v[i] || v == _u[i]) continue;
				ans += (chk(1,u,v) + chk(1,u,_v[i]) + chk(1,_u[i],v) == 3);
			}
		}
	}
	printf("%d\n",ans + n);
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 8628kb

input:

3 4
1 2 0
1 3 1
2 3 0
2 3 1

output:

5

result:

ok 1 number(s): "5"

Test #2:

score: 0
Accepted
time: 1ms
memory: 8536kb

input:

4 6
1 2 0
2 3 0
3 4 0
1 4 1
2 4 1
1 3 1

output:

5

result:

ok 1 number(s): "5"

Test #3:

score: 0
Accepted
time: 1ms
memory: 9172kb

input:

20 28
9 6 1
9 6 0
3 8 0
8 4 0
3 8 1
3 4 1
2 13 0
13 1 0
19 1 0
2 1 1
2 19 1
13 19 1
14 15 1
14 15 0
7 12 0
12 17 0
20 17 0
7 17 1
7 20 1
12 20 1
16 18 0
18 10 0
5 10 0
16 10 1
16 5 1
18 5 1
4 6 0
9 11 0

output:

27

result:

ok 1 number(s): "27"

Test #4:

score: 0
Accepted
time: 0ms
memory: 8496kb

input:

100 150
93 23 0
23 81 0
76 81 0
93 81 1
93 76 1
23 76 1
100 65 0
65 56 0
19 56 0
100 56 1
100 19 1
65 19 1
2 98 0
2 98 1
26 63 0
63 90 0
26 63 1
26 90 1
6 11 0
11 67 0
6 11 1
6 67 1
37 89 0
89 64 0
25 64 0
37 64 1
37 25 1
89 25 1
84 10 0
10 29 0
75 29 0
84 29 1
84 75 1
10 75 1
7 70 1
7 70 0
28 92 0
...

output:

141

result:

ok 1 number(s): "141"

Test #5:

score: -100
Runtime Error

input:

100000 133680
36843 86625 0
86625 63051 0
35524 63051 0
36843 63051 1
36843 35524 1
86625 35524 1
55797 82715 0
55797 82715 1
70147 35104 0
35104 91732 0
70147 35104 1
70147 91732 1
94917 70395 0
70395 68250 0
24100 68250 0
94917 68250 1
94917 24100 1
70395 24100 1
83033 18450 1
83033 18450 0
34462 ...

output:


result: