#include <bits/stdc++.h> 

using namespace std;

#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second

typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;

const int MX = 1 << 20;
const int X = 101;
const int Y = 10047;

int n;
int cnt[MX];
VI vecs[X];
vector<PII> vecPairs[X];
int g[MX];

void precalc()
{
	FOR(i, 1, X)
		FOR(j, 0, Y)
		{
			int gc = gcd(i, j);
			g[Y * i + j] = (Y * i + j) / gc;
		}
}

void solve()
{
	if (n == 3)
	{
		cout << 3 << '\n';
		return;
	}
	FOR(i, 0, X)
	{
		vecs[i].clear();
		vecPairs[i].clear();
	}
	FOR(i, 0, n)
	{
		int t, v;
		cin >> t >> v;
		vecs[v].PB(v * t);
	}
	int ans = 0;
	FOR(k, 1, X)
	{
		sort(ALL(vecs[k]));
		for (int j = 0; j < SZ(vecs[k]); )
		{
			int l = j;
			while (l < SZ(vecs[k]) && vecs[k][l] == vecs[k][j])
			{
				l++;
			}
			ans = max(ans, l - j);
			vecPairs[k].PB({vecs[k][j], l - j});
			j = l;
		}
	}
	int used = 0;
	const int MAGIC = max(1000, (int)(0.14 * n));
	FOR(x1, 1, X)
	{
		for (auto [y1, c] : vecPairs[x1])
		{
			used++;
			if (used > MAGIC)
				break;
			int cur = 0;
			FOR(x2, x1 + 1, X)
			{
				auto le = lower_bound(ALL(vecPairs[x2]), MP(y1, 0)),
					ri = lower_bound(ALL(vecPairs[x2]), MP(y1 + (x2 - x1) * 100 + 1, 0));
				int dx = x2 - x1;
				int dx2 = Y * dx - y1;
				for (auto it = le; it != ri; it++)
				{
					int& res = cnt[dx2 + it->F];
					res += it->S;
					cur = max(cur, res);
				}
			}
			FOR(x2, x1 + 1, X)
			{
				auto le = lower_bound(ALL(vecPairs[x2]), MP(y1, 0)),
					ri = lower_bound(ALL(vecPairs[x2]), MP(y1 + (x2 - x1) * 100 + 1, 0));
				int dx = x2 - x1;
				int dx2 = Y * dx - y1;
				for (auto it = le; it != ri; it++)
				{
					cnt[dx2 + it->F] -= it->S;
				}
			}
			ans = max(ans, cur + c);
		}
	}
	cout << ans << "\n";
}

int main()
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	precalc();
	while (cin >> n)
	{
		solve();
	}
	return 0;
}