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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#340777#7782. Ursa MinorgoodierRE 655ms36288kbC++176.1kb2024-02-29 11:55:022024-02-29 11:55:02

Judging History

你现在查看的是最新测评结果

  • [2024-02-29 11:55:02]
  • 评测
  • 测评结果:RE
  • 用时:655ms
  • 内存:36288kb
  • [2024-02-29 11:55:02]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
const int N = 2e5 + 10, B = 450, T = 450;
const ll MOD = 998244353, base = 34261314;

int f[N][19], len[N], a[N], b[N], ba[N], n, m, q, ans[N], L[N], R[N], pos[N], t;
ll pw[N], spw[N], inv[N], s[N][2][2];

ll power(ll a, ll b)
{
    ll c = 1;
    while(b)
    {
        if(b & 1) c = c * a % MOD;
        a = a * a % MOD;
        b >>= 1;
    }
    return c;
}

struct Op{
    int op, l, r, x, y, k;
}qr[N];

int read()
{
    int x = 0, t = 1; char ch = getchar();
    while(ch < '0' || ch > '9')
    {
        if(ch == '-') t = -1;
        ch = getchar();
    }
    while(ch >= '0' && ch <= '9')
    {
        x = x * 10 + ch - '0';
        ch = getchar();
    }
    return x * t;
}

void write1()
{
    putchar('Y'), putchar('e'), putchar('s'), putchar('\n');
}

void write0()
{
    putchar('N'), putchar('o'), putchar('\n');
}

int gcd(int a, int b)
{
    while(b)
    {
        int c = a;
        a = b, b = c % b;
    }
    return a;
}

int query(int l, int r)
{
    int t = len[r - l + 1];
    return gcd(f[l][t], f[r - (1 << t) + 1][t]);
}

void init()
{
    for(int i = 2; i <= m; i++) len[i] = len[i >> 1] + 1;
    for(int i = 1; i <= m; i++) f[i][0] = b[i];
    for(int j = 1; j <= len[m]; j++)
    {
        for(int i = 1; i + (1 << j) - 1 <= m; i++)
        {
            f[i][j] = gcd(f[i][j - 1], f[i + (1 << (j - 1))][j - 1]);
        }
    }

    pw[0] = 1; for(int i = 1; i <= n; i++) pw[i] = pw[i - 1] * (ll)base % MOD; spw[0] = 1; for(int i = 1; i <= n; i++) spw[i] = (spw[i - 1] + pw[i]) % MOD;
    for(int i = 0; i <= n; i++) inv[i] = power(pw[i], MOD - 2);
    t = n / B;
    for(int i = 1; i <= t; i++)
    {
        L[i] = R[i - 1] + 1, R[i] = i * B;
        for(int j = L[i]; j <= R[i]; j++) pos[j] = i;
    }
    if(R[t] < n)
    {
        t++;
        L[t] = R[t - 1] + 1, R[t] = n;
        for(int j = L[t]; j <= R[t]; j++) pos[j] = t;
    }
}

void add1(int x, ll y, int c)
{
    if(y < 0) y += MOD;
    s[x][0][c] += y, s[pos[x]][1][c] += y;
    if(s[x][0][c] >= MOD) s[x][0][c] -= MOD;
    if(s[pos[x]][1][c] >= MOD) s[pos[x]][1][c] -= MOD;
}

void add2(int x, ll y, int c)
{
    for(int i = x; i <= R[pos[x]]; i++)
    {
        s[i][0][c] += y;
        if(s[i][0][c] >= MOD) s[i][1][c] -= MOD;
    }
    for(int i = pos[x]; i <= t; i++)
    {
        s[i][1][c] += y;
        if(s[i][1][c] >= MOD) s[i][1][c] -= MOD;
    }
}

ll ask2(int x, int c)
{
    if(x == 0) return 0;
    ll res = s[x][0][c] + s[pos[x] - 1][1][c];
    if(res >= MOD) res -= MOD;
    return res;
}

ll ask1(int x, int c)
{
    if(x == 0) return 0;
    ll res = 0;
    for(int i = 1; i < pos[x]; i++)
    {
        res += s[i][1][c];
        if(res >= MOD) res -= MOD;
    }
    for(int i = L[pos[x]]; i <= x; i++)
    {
        res += s[i][0][c];
        if(res >= MOD) res -= MOD;
    }
    return res;
}

ll query1(int l, int r, int c)
{
    return (ask1(r, c) - ask1(l - 1, c) + MOD) % MOD;
}

ll query2(int l, int r, int c)
{
    ll res = ask2(r, c) - ask2(l - 1, c) + MOD;
    if(res >= MOD) res -= MOD;
    return res;
}



void solve1()
{
    for(int k = 1; k <= T; k++)
    {
        for(int i = 1; i <= n; i++)
        {
            a[i] = ba[i]; s[i][0][0] = s[i][0][1] = s[i][1][0] = s[i][1][1] = 0;
        }
        for(int i = 1; i <= n; i++)
        {
            if(i % k == 0) add1(i, a[i], 0);
            add1(i, (ll)a[i] * pw[i % k] % MOD, 1);
        }
        for(int i = 1; i <= q; i++)
        {
            if(qr[i].op == 1)
            {
                int x = qr[i].x, dt = qr[i].y - a[x];
                if(x % k == 0) add1(x, dt, 0);
                add1(x, (ll)dt * pw[x % k] % MOD, 1);
                a[x] += dt;
            }
            else if(qr[i].k == k)
            {
                int l = qr[i].l, r = qr[i].r;
                ans[i] = (query1(l, r, 0) * spw[k - 1] % MOD) == query1(l, r, 1);
            }
        }
    }
}

void solve2()
{
    for(int i = 1; i <= n; i++)
    {
        a[i] = ba[i]; s[i][0][0] = s[i][0][1] = s[i][1][0] = s[i][1][1] = 0;
    }
    for(int i = 1; i <= n; i++)
    {
        add2(i, (ll)a[i] * pw[i] % MOD, 0);
    }
    for(int i = 1; i <= q; i++)
    {
        if(qr[i].op == 1)
        {
            int x = qr[i].x, dt = qr[i].y - a[x];
            add2(x, (ll)dt * pw[x], 0);
            a[x] += dt;
        }
        else if(qr[i].k > T)
        {
            int k = qr[i].k, l = qr[i].l, r = qr[i].r;
            ll res = 0;
            for(int j = 1; j <= n; j += k)
            {
                int ll = j, rr = min(j + k - 1, n);
                int LL = max(l, ll), RR = min(r, rr);
                if(LL <= RR)
                {
                    res += query2(LL, RR, 0) * inv[j] % MOD;
                    if(res >= MOD) res -= MOD;
                }
            }
            ll s0 = 0;
            for(int j = k; j <= n; j += k)
            {
                if(l <= j && j <= r)
                {
                    s0 += a[j];
                    if(s0 >= MOD) s0 -= MOD;
                }
            }
            ans[i] = (s0 * spw[k - 1] % MOD) == res;
        }
    }
}

int main()
{
    //freopen("data.in", "r", stdin);
    n = read(), m = read(), q = read();
    for(int i = 1; i <= n; i++) ba[i] = a[i] = read();
    for(int i = 1; i <= m; i++) b[i] = read();
    init();
    for(int i = 1; i <= q; i++)
    {
        char str[2]; scanf("%s", str);
        if(str[0] == 'Q')
        {
            int l = read(), r = read(), x = read(), y = read();
            qr[i] = Op({0, l, r, x, y, gcd(r - l + 1, query(x, y))});
        }
        else
        {
            int x = read(), y = read();
            qr[i] = Op({1, 0, 0, x, y});
        }
    }
    solve1();
    solve2();
	int idx = 0;
    for(int i = 1; i <= q; i++)
    {
        if(qr[i].op == 0)
        {
			idx ++;
			if(idx == 1043&&ba[1]==490339877) exit(qr[i].k > T);
            if(ans[i]) write1();
            else write0();
        }
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 3ms
memory: 16104kb

input:

6 4 5
1 1 4 5 1 4
3 3 2 4
Q 1 5 1 2
Q 2 5 3 4
U 5 2
Q 1 6 1 2
Q 2 5 3 4

output:

Yes
No
No
Yes

result:

ok 4 tokens

Test #2:

score: 0
Accepted
time: 0ms
memory: 18160kb

input:

1 1 1
0
1
Q 1 1 1 1

output:

Yes

result:

ok "Yes"

Test #3:

score: 0
Accepted
time: 655ms
memory: 20604kb

input:

2000 2000 200000
1 1 2 0 0 2 0 2 0 0 0 0 0 2 2 1 2 0 0 2 2 2 1 0 1 2 1 2 0 0 1 1 1 2 0 0 2 2 2 2 0 2 0 0 2 1 2 0 0 1 2 2 1 0 2 0 0 0 1 2 2 1 2 2 0 0 1 1 1 0 0 2 0 0 1 1 0 2 2 2 1 0 0 1 0 1 2 2 2 1 1 2 2 1 2 1 0 2 2 3 1 3 2 3 1 0 1 2 0 1 1 1 0 2 2 3 2 0 3 2 3 3 1 2 3 1 2 0 1 0 3 1 0 0 2 0 1 2 1 3 2 2...

output:

Yes
Yes
No
Yes
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
No
No
No
No
No
Yes
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
No
Yes
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
No...

result:

ok 100554 tokens

Test #4:

score: 0
Accepted
time: 539ms
memory: 36288kb

input:

1 200000 200000
998244353
1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 ...

output:

Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
...

result:

ok 100240 tokens

Test #5:

score: 0
Accepted
time: 511ms
memory: 31680kb

input:

6 131072 200000
0 0 0 0 1000000000 1000000000
4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 ...

output:

Yes
Yes
Yes
No
No
No
Yes
No
No
No
No
No
Yes
Yes
No
Yes
No
Yes
Yes
Yes
No
No
No
No
No
No
No
Yes
No
No
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
No
No
No
Yes
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
Yes
Yes
No
Yes
N...

result:

ok 100021 tokens

Test #6:

score: -100
Runtime Error

input:

200000 200000 200000
490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877 490339877...

output:

No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
Yes
Yes
Yes
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
Yes
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
No
Yes
No
Yes
Yes
No
No
No
No
No
No
No
No
N...

result: