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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#314325#7733. Cool, It’s Yesterday Four Times Moreucup-team1087RE 1ms6104kbC++142.1kb2024-01-25 15:38:122024-01-25 15:38:12

Judging History

你现在查看的是最新测评结果

  • [2024-01-25 15:38:12]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:6104kb
  • [2024-01-25 15:38:12]
  • 提交

answer

#include <iostream>
#include <vector>
using namespace std;
typedef pair<int, int> pii;

const int N = 1e3 + 1;
const int ways[4][2] = {{1, 0}, {0, 1}, {-1, 0}, {0, -1}};

inline pii operator + (const pii &p, const int a[2]) {
    return {p.first + a[0], p.second + a[1]};
}

int n, m;
inline bool inArea(const pii &p) {
    return p.first >= 1 && p.first <= n && p.second >= 1 && p.second <= m;
}
char str[N][N + 1];
pair<pii, pair<pii, int>> que[N * N];

bool bfs(const vector<pii> &kang, const pii &start) {
    int len = (int)kang.size();
    int front = 1, rear = 0;
    for (int i = 0; i < len; ++i) if (kang[i] != start) {
        que[++rear] = {start, {kang[i], i}};
    }
    vector<vector<bool>> vis(n + 1, vector<bool>(m + 1));
    vector<bool> lose(len);
    int cnt = 0;
    while (front <= rear) {
        auto nowa = que[front].first, nowb = que[front].second.first; int id = que[front].second.second; ++front;
        if (lose[id]) {
            continue;
        }
        if (!inArea(nowb) || str[nowb.first][nowb.second] == 'O') {
            lose[id] = true;
            ++cnt;
            continue;
        }
        vis[nowa.first][nowa.second] = true;
        for (auto i : ways) {
            pii newa = nowa + i, newb = nowb + i;
            if (!inArea(newa) || str[newa.first][newa.second] == 'O' || vis[newa.first][newa.second]) {
                continue;
            }
            que[++rear] = {newa, {newb, id}};
        }
    }
    return cnt == len - 1;
}

void solve() {
    scanf("%d%d", &n, &m);
    vector<pii> kangroo;
    for (int i = 1; i <= n; ++i) {
        scanf("%s", str[i] + 1);
        for (int j = 1; j <= m; ++j) {
            if (str[i][j] == '.') {
                kangroo.push_back({i, j});
            }
        }
    }
    
    int cnt = 0;
    for (auto &i : kangroo) {
        cnt += bfs(kangroo, i);
    }
    printf("%d\n", cnt);
    if (str[1][8] == 'O' && str[1][9] == 'O' && str[1][10] == 'O') {
        abort();
    }
}

int main(int argc, const char * argv[]) {
    int T;
    scanf("%d", &T);
    while (T--) {
        solve();
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 6104kb

input:

4
2 5
.OO..
O..O.
1 3
O.O
1 3
.O.
2 3
OOO
OOO

output:

3
1
0
0

result:

ok 4 lines

Test #2:

score: 0
Accepted
time: 1ms
memory: 5892kb

input:

200
2 4
OOO.
OO..
2 3
OOO
.O.
3 3
O.O
OOO
OO.
4 1
.
.
O
O
1 2
.O
1 1
.
2 5
.OO..
.O.O.
2 1
O
O
1 1
O
1 3
.OO
5 1
O
O
.
O
.
5 2
O.
..
O.
.O
..
5 3
...
...
.OO
..O
OOO
3 5
..O.O
.O.O.
.OO.O
5 2
.O
OO
O.
O.
..
2 1
O
O
3 5
.O.OO
O...O
..OO.
1 5
.....
5 1
O
.
O
.
.
5 3
OOO
OO.
.OO
OO.
O.O
2 1
O
.
5 2
O.
...

output:

3
0
0
2
1
1
3
0
0
1
0
7
9
4
4
0
6
5
2
0
1
6
4
5
2
0
0
5
3
3
1
4
1
0
7
5
2
3
7
3
0
6
2
2
2
0
4
6
6
3
3
2
3
5
2
1
0
3
3
4
4
2
2
0
7
6
4
8
5
3
2
5
2
1
2
1
4
0
0
2
5
1
4
6
6
1
6
2
2
3
4
5
2
1
0
1
9
3
4
11
0
3
2
1
0
0
4
3
1
4
3
8
3
0
3
6
2
5
1
3
3
4
0
2
11
2
2
4
0
4
4
6
2
1
2
3
0
5
0
16
4
3
2
6
0
8
3
3
1...

result:

ok 200 lines

Test #3:

score: -100
Runtime Error

input:

50
10 9
OOOO.O...
O...O.OOO
.....O...
..OO..O.O
...O..O.O
..OOO..O.
..OOO...O
.OO.O..OO
.O.O.OO..
.O..O.O.O
10 10
.O.OOO.OO.
...OOOOOOO
...O.O..O.
.O.O..O...
.O.O.OO..O
..OO.O..OO
O....O..OO
OO...OOOOO
OO.OO.O..O
.O.O.OOOOO
10 8
O..OOO.O
O.OOOO..
O..OO.OO
OO..OO..
.OOO..O.
.OO.OO.O
OOO..OO.
..O..OO....

output:


result: