#include<bits/stdc++.h>
// #pragma GCC optimize("Ofast")
// #pragma GCC target("avx,avx2,tune=native")
using namespace std;
#define int long long
#define ll long long
#define ld long double
#define pii pair<ll,ll>
#define mp make_pair
#define pb push_back
#define fir first
#define sec second
const ll N = 1e5+100;
const ll INF = (ll)1e18;
const ll MOD = 998244353;
inline ll read(){
    ll ret=0,f=1;char ch=getchar();
    while(!isdigit(ch)){
        if(ch=='-') f*=-1;
        ch=getchar();
    }
    while(isdigit(ch)){
        ret=(ret<<3)+(ret<<1)+ch-'0';
        ch=getchar();
    }
    return ret*f;
}
ll gcd(ll x,ll y){return y==0?x:gcd(y,x%y);}
ll kpow(ll a,ll b,ll mod){
    ll ret=1,base=a%mod;while(b){if(b&1) ret=ret*base%mod;base=base*base%mod;b>>=1;}return ret;
}
inline ll upd(ll x){return (x%MOD+MOD)%MOD;}
ll C[10][10];
inline ll get_d(ll k,ll c,ll w){
    return C[k][c]*kpow(w,k-c,MOD);
}
ll n,m,k,W,a[N];
const ll V = 1e5+2;
struct segment_tree0{
    ll mod;
    int cnt[N*4],sum[N*4],sum_k[6][N*4];
    int tg[N*4];
    segment_tree0(){memset(cnt,0,sizeof(cnt));memset(sum,0,sizeof(sum));memset(sum_k,0,sizeof(sum_k));memset(tg,0,sizeof(tg));}
    inline void push_up(int rt){
        sum[rt]=upd(sum[rt<<1]+sum[rt<<1|1]);
        for(int i=0;i<=k;++i)
            sum_k[i][rt]=upd(sum_k[i][rt<<1]+sum_k[i][rt<<1|1]);
        cnt[rt]=cnt[rt<<1]+cnt[rt<<1|1];
    }
    inline void modify(int rt,int v){
        tg[rt]+=v;
        for(int i=k;i>=0;i--)
            for(int j=i-1;j>=0;j--)
                sum_k[i][rt]=upd(sum_k[i][rt]+1ll*sum_k[j][rt]*get_d(i,j,v));
        sum[rt]=sum_k[k][rt];
    }
    inline void push_down(int rt){
        if(tg[rt]!=0){
            modify(rt<<1,tg[rt]);
            modify(rt<<1|1,tg[rt]);
            tg[rt]=0;
        }
    }
    inline int query_sz(int rt,int l,int r,int idx){
        if(r<=idx) return cnt[rt];
        if(l>idx)  return 0;
        int mid=(l+r)>>1;
        return query_sz(rt<<1,l,mid,idx)+query_sz(rt<<1|1,mid+1,r,idx);
    }
    inline void update_v(int rt,int l,int r,int w,int c){
        if(r<w||l>w) return;
        if(l==r){
            if(c==1){
                ll id=query_sz(1,0,V,w)+1;
                cnt[rt]++;
                for(ll i=0;i<=k;++i)
                    sum_k[i][rt]=upd(1ll*sum_k[i][rt]+1ll*w*kpow(id,i,MOD)%MOD);
            }else{
                ll id=query_sz(1,0,V,w);
                cnt[rt]--;
                for(ll i=0;i<=k;++i)
                    sum_k[i][rt]=upd(1ll*sum_k[i][rt]-1ll*w*kpow(id,i,MOD)%MOD);
            }
            sum[rt]=sum_k[k][rt];
            return ;
        }
        int mid=l+r>>1;
        push_down(rt);
        update_v(rt<<1,l,mid,w,c);
        update_v(rt<<1|1,mid+1,r,w,c);
        push_up(rt);
    }
    inline void update_i(int rt,int l,int r,int ql,int qr,int v){
        if(r<ql||l>qr) return;
        if(ql<=l&&r<=qr){
            if(v==1){
                for(int i=k;i>=0;i--)
                    for(int j=i-1;j>=0;j--)
                        sum_k[i][rt]=upd(1ll*sum_k[i][rt]+1ll*sum_k[j][rt]*get_d(i,j,v));
            }else{
                for(int i=k;i>=0;i--)
                    for(int j=i-1;j>=0;j--)
                        sum_k[i][rt]=upd(1ll*sum_k[i][rt]+1ll*sum_k[j][rt]*get_d(i,j,v));
            }
            sum[rt]=sum_k[k][rt];
            tg[rt]+=v;
            return ;
        }
        int mid=(l+r)>>1;
        push_down(rt);
        update_i(rt<<1,l,mid,ql,qr,v);
        update_i(rt<<1|1,mid+1,r,ql,qr,v);
        push_up(rt);
    }
}sg0;
ll kpw[20][20];
struct segment_tree1{
    int cnt[N*4],sum[N*4],sum_k[6][6][N*4];
    int tg[N*4];
    segment_tree1(){memset(cnt,0,sizeof(cnt));memset(sum,0,sizeof(sum));memset(sum_k,0,sizeof(sum_k));memset(tg,0,sizeof(tg));}
    inline void push_up(int rt){
        sum[rt]=upd(sum[rt<<1]+sum[rt<<1|1]);
        for(int i=0;i<W;++i)
            for(int j=0;j<W;++j)
                sum_k[i][j][rt]=upd(sum_k[i][j][rt<<1]+sum_k[i][j][rt<<1|1]);
        cnt[rt]=cnt[rt<<1]+cnt[rt<<1|1];
    }
    inline void modify(int rt,int v){
        v=(v%W+W)%W;
        ll ret[6][6];
        sum[rt]=0;
        for(int j=0;j<W;++j){
            for(int i=0;i<W;++i)
                ret[j][i]=sum_k[j][(i-v+W*2)%W][rt];
            for(int i=0;i<W;++i)
                sum_k[j][i][rt]=ret[j][i];
            for(int i=0;i<W;++i)
                sum[rt]=upd(sum[rt]+1ll*j*kpw[i][k]%W*sum_k[j][i][rt]%MOD);
        }
    }
    inline void push_down(int rt){
        if(tg[rt]!=0){
            tg[rt<<1]+=tg[rt];tg[rt<<1|1]+=tg[rt];
            modify(rt<<1,tg[rt]);
            modify(rt<<1|1,tg[rt]);
            tg[rt]=0;
        }
    }
    inline ll query_sz(int rt,int l,int r,int idx){
        if(r<=idx) return cnt[rt];
        if(l>idx)  return 0;
        int mid=(l+r)>>1;
        return query_sz(rt<<1,l,mid,idx)+query_sz(rt<<1|1,mid+1,r,idx);
    }
    inline void update_v(int rt,int l,int r,int w,int c){
        if(r<w||l>w) return;
        if(l==r){
            if(c==1){
                ll id=query_sz(1,0,V,w)+1;
                cnt[rt]++;
                sum_k[w%W][id%W][rt]=upd(sum_k[w%W][id%W][rt]+1);
            }else{
                ll id=query_sz(1,0,V,w);
                cnt[rt]--;
                sum_k[w%W][id%W][rt]=upd(sum_k[w%W][id%W][rt]-1);
            }
            sum[rt]=0;
            for(int j=0;j<W;++j)
                for(int i=0;i<W;++i)
                    sum[rt]=upd(sum[rt]+1ll*j*kpw[i][k]%W*sum_k[j][i][rt]%MOD);
            return ;
        }
        int mid=l+r>>1;
        push_down(rt);
        update_v(rt<<1,l,mid,w,c);
        update_v(rt<<1|1,mid+1,r,w,c);
        push_up(rt);
    }
    inline void update_i(int rt,int l,int r,int ql,int qr,int v){
        if(r<ql||l>qr) return;
        if(ql<=l&&r<=qr){
            modify(rt,v);
            tg[rt]+=v;
            return ;
        }
        int mid=(l+r)>>1;
        push_down(rt);
        update_i(rt<<1,l,mid,ql,qr,v);
        update_i(rt<<1|1,mid+1,r,ql,qr,v);
        push_up(rt);
    }
}sg1;
ll b[N];
void multi_test(){
    for(int i=0;i<=6;++i){
        C[i][0]=C[i][i]=1;
        for(int j=1;j<i;++j)
            C[i][j]=C[i-1][j-1]+C[i-1][j];
    }
    n=read(),k=read(),W=read();
    for(int i=0;i<=10;++i)
        for(int j=0;j<=10;++j)
            kpw[i][j]=kpow(i,j,W);
    sg0.mod=998244353;//sg1.mod=W;
    for(int i=1;i<=n;++i){
        a[i]=read();
        b[i]=a[i];
    }
    sort(b+1,b+n+1);
    for(int i=1;i<=n;++i){
        sg0.update_v(1,0,V,b[i],1);
        sg0.update_i(1,0,V,b[i]+1,V,1);
        sg1.update_v(1,0,V,b[i],1);
        sg1.update_i(1,0,V,b[i]+1,V,1);
    }
        // cout<<sg0.sum[1]<<endl;
        // cout<<sg1.sum[1]<<endl<<endl;
    ll q=read();
    while(q--){
        ll pos=read(),x=read();
        sg0.update_v(1,0,V,a[pos],-1);
        sg0.update_i(1,0,V,a[pos]+1,V,-1);
        sg0.update_v(1,0,V,x,1);
        sg0.update_i(1,0,V,x+1,V,1);
        // cout<<sg0.sum[1]<<endl;
        sg1.update_v(1,0,V,a[pos],-1);
        sg1.update_i(1,0,V,a[pos]+1,V,-1);
        sg1.update_v(1,0,V,x,1);
        sg1.update_i(1,0,V,x+1,V,1);
        // cout<<sg1.sum[1]<<endl<<endl;
        assert(upd(sg0.sum_k[k][1])==upd(sg0.sum[1]));
        printf("%lld\n",(ll)1ll*upd(sg0.sum_k[k][1]-sg1.sum[1])*kpow(W,MOD-2,MOD)%MOD);
        a[pos]=x;
    }
    return ;
}
/*
Things to notice:
1. do not calculate useless values
2. do not use similar names
 
Things to check:
1. submit the correct file
2. time (it is log^2 or log)
3. memory
4. prove your naive thoughts 
5. long long
6. corner case like n=0,1,inf or n=m
7. fileio in some oi-contest
8. module on time 
9. the number of a same divisor in a math problem
10. multi-information and queries 
*/
signed main(){
    freopen("data.in","r",stdin);
    freopen("my.out","w",stdout);
    ll T=1;
    while(T--) multi_test();
    return 0;
}