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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#303017 | #7906. Almost Convex | qiling | TL | 1ms | 4224kb | C++14 | 2.4kb | 2024-01-11 16:53:17 | 2024-01-11 16:53:17 |
Judging History
answer
#include <map>
#include <cmath>
#include <iostream>
#include <algorithm>
using namespace std;
#define N 2010
#define eps 1e-8
#define x first
#define y second
#define endl '\n'
#define PDD pair<double, double>
int n;
PDD q[N], q1[N];
int stk[N], top;
bool st[N];
PDD operator- (PDD a, PDD b) { return {a.x - b.x, a.y - b.y};}
double cross (PDD a, PDD b) { return a.x * b.y - b.x * a.y;}
double area (PDD a, PDD b, PDD c) { return cross(b - a, c - a);}
void andrew() {
sort(q + 1, q + n + 1);
for (int i = 1; i <= n; ++ i) {
while(top >= 2 && area(q[stk[top - 1]], q[stk[top]], q[i]) <= 0) {
if(area(q[stk[top - 1]], q[stk[top]], q[i]) < 0) st[stk[top --]] = false;
else top --;
}
stk[++ top] = i;
st[i] = true;
}
st[1] = false;
for (int i = n; i >= 1; -- i) {
if(st[i]) continue;
while(top >= 2 && area(q[stk[top - 1]], q[stk[top]], q[i]) <= 0) {
if(area(q[stk[top - 1]], q[stk[top]], q[i]) < 0) st[stk[top --]] = false;
else top --;
}
stk[++ top] = i;
st[i] = true;
}
}
int dcmp(double a, double b) {
if(fabs(a - b) < eps) return 0;
if(a < b) return -1;
return 1;
}
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> n;
for (int i = 1; i <= n; ++ i) {
cin >> q[i].x >> q[i].y;
q1[i] = q[i];
}
andrew();
map<PDD, PDD> l, r;
stk[0] = stk[top - 1];
for (int i = 1; i < top; ++ i) {
l[q[stk[i]]] = q[stk[i - 1]];
r[q[stk[i]]] = q[stk[i + 1]];
}
int ans = 1;
PDD o;
auto cmp = [&](PDD a, PDD b) {
a = a - o;
b = b - o;
if(dcmp(atan2(a.y, a.x), atan2(b.y, b.x)) == 0) return a.x < b.x;
return dcmp(atan2(a.y, a.x), atan2(b.y, b.x)) < 0;
};
for (int i = 1; i <= n; ++ i) {
if(st[i]) continue;
o = q[i];
for (int j = 1; j <= n; ++ j) {
q1[j] = q[j];
}
swap(q1[1], q1[i]);
sort(q1 + 2, q1 + n + 1, cmp);
for (int j = 2; j < n; ++ j) {
if((r[q1[j]] == q1[j + 1] && q1[j]== l[q1[j + 1]]) ||
(l[q1[j]] == q1[j + 1] && q1[j] == r[q1[j + 1]])) {
++ ans;
}
}
if(r[q1[n]] == q1[2] && q1[n] == l[q1[2]]) {
++ ans;
}
}
cout << ans << endl;
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 4224kb
input:
7 1 4 4 0 2 3 3 1 3 5 0 0 2 4
output:
9
result:
ok 1 number(s): "9"
Test #2:
score: 0
Accepted
time: 0ms
memory: 4028kb
input:
5 4 0 0 0 2 1 3 3 3 1
output:
5
result:
ok 1 number(s): "5"
Test #3:
score: 0
Accepted
time: 0ms
memory: 3748kb
input:
3 0 0 3 0 0 3
output:
1
result:
ok 1 number(s): "1"
Test #4:
score: 0
Accepted
time: 0ms
memory: 4160kb
input:
6 0 0 3 0 3 2 0 2 1 1 2 1
output:
7
result:
ok 1 number(s): "7"
Test #5:
score: 0
Accepted
time: 0ms
memory: 3872kb
input:
4 0 0 0 3 3 0 3 3
output:
1
result:
ok 1 number(s): "1"
Test #6:
score: -100
Time Limit Exceeded
input:
2000 86166 617851 383354 -277127 844986 386868 -577988 453392 -341125 -386775 -543914 -210860 -429613 606701 -343534 893727 841399 339305 446761 -327040 -218558 -907983 787284 361823 950395 287044 -351577 -843823 -198755 138512 -306560 -483261 -487474 -857400 885637 -240518 -297576 603522 -748283 33...