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#302239#4824. Bracket-and-bar SequencesLoging#0 1ms3840kbC++202.0kb2024-01-10 17:57:322024-01-10 17:57:32

Judging History

你现在查看的是最新测评结果

  • [2024-01-10 17:57:32]
  • 评测
  • 测评结果:0
  • 用时:1ms
  • 内存:3840kb
  • [2024-01-10 17:57:32]
  • 提交

answer

#include <bits/stdc++.h>

#define ll long long

using namespace std;

int T,n;
ll now,f[100],g[100];
char s[100];

inline ll calc(int l,int r){
//	cout<<l<<" "<<r<<endl;
	if(l>r)return 1;
	if(l==r)return 1;
	if(l==r-2)return 1;
	int res=0,id=0;
	for(int i=l;i<=r;i++){
		if(s[i]=='(')res++;
		if(s[i]==')')res--;
		if(!res){
			id=i;
			break;
		}
	}
	int m=(r-l-2)/3;
	int p=(id-l-2)/3;
	int q=(r-id)/3;
	ll sum=0;
	for(int i=0;i<p;i++){
		if(i==0){
			sum+=f[m];
		}else{
			sum+=2*f[i]*f[m-i];
		}
	}
	if(id==0||s[l+1]=='|'){
		return sum+(calc(l+2,id-1)-1)*f[q]+calc(id+1,r);
	}else{
		return sum+f[p]*f[q]+(calc(l+1,id-2)-1)*f[q]+calc(id+1,r);
	}
}

inline void calc2(int l,int r,int n,ll now){
	if(l>r)return;
//	cout<<l<<" "<<r<<" "<<n<<" "<<now<<endl;
	int p=0;
	for(int i=0;i<n;i++){
		ll res=0;
		if(i==0){
			res=f[n-1];
		}else{
			res=2*f[i]*f[n-1-i];
		}
		if(now<=res){
			p=i;
			break;
		}else{
			now-=res;
		}
	}
	int id=l+p*3+2;
	int q=n-p-1;
//	cout<<p<<" "<<q<<" "<<now<<endl;
	if(p==0||now<=f[p]*f[q]){
		s[l]='(';
		s[l+1]='|';
		s[id]=')';
		ll k=((now-1)/f[q])+1;
		ll kk=(now-1)%f[q]+1;
		calc2(l+2,id-1,p,k);
		calc2(id+1,r,q,kk);
	}else{
		s[l]='(';
		s[id-1]='|';
		s[id]=')';
		now-=f[p]*f[q];
		ll k=((now-1)/f[q])+1;
		ll kk=(now-1)%f[q]+1;
		calc2(l+1,id-2,p,k);
		calc2(id+1,r,q,kk);
	}
}

int main(){
	f[0]=1;
	f[1]=g[1]=1;
	for(int i=2;i<=25;i++){
		f[i]=0;
		for(int j=0;j<=i-1;j++){
			if(j==0){
				f[i]+=f[i-1];
			}else{
				f[i]+=2*f[j]*f[i-1-j];
			}
		}
//		cout<<i<<" "<<f[i]<<endl;
		g[i]=g[i-1]+f[i];
	}
	scanf("%s",s+1);
	if(s[1]=='e'){
		scanf("%d",&T);
		while(T--){
			scanf("%d",&n);
			scanf("%s",s+1);
			now=calc(1,3*n);
			printf("%lld\n",now);
		}
	}else{
		scanf("%d",&T);
		while(T--){
			scanf("%d",&n);
			scanf("%lld",&now);
			calc2(1,3*n,n,now);
			for(int i=1;i<=3*n;i++)putchar(s[i]);puts("");
		}
	}
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3840kb

input:

encode
3
1
(|)
4
((((|)|)|)|)
5
(|(|))((|(|))|)

output:

1
45
55

input:

decode
3
1
1
4
45
5
55

output:

(|)
((((|)|)|)|)
(|(|))((|(|))|)

result:

ok 3 lines

Test #2:

score: 100
Accepted
time: 0ms
memory: 3648kb

input:

encode
1
1
(|)

output:

1

input:

decode
1
1
1

output:

(|)

result:

ok single line: '(|)'

Test #3:

score: 100
Accepted
time: 1ms
memory: 3636kb

input:

encode
3
2
((|)|)
1
(|)
2
(|(|))

output:

3
1
2

input:

decode
3
2
3
1
1
2
2

output:

((|)|)
(|)
(|(|))

result:

ok 3 lines

Test #4:

score: 0
Stage 1: Program answer Time Limit Exceeded

input:

encode
1000
3
(|)(|)(|)
3
(|)(|(|))
3
(|)((|)|)
3
(|(|))(|)
3
(|(|)(|))
3
(|(|(|)))
3
(|((|)|))
3
((|)|)(|)
3
((|)|(|))
3
((|)(|)|)
3
((|(|))|)
3
(((|)|)|)
4
(|)(|)(|)(|)
4
(|)(|)(|(|))
4
(|)(|)((|)|)
4
(|)(|(|))(|)
4
(|)(|(|)(|))
4
(|)(|(|(|)))
4
(|)(|((|)|))
4
(|)((|)|)(|)
4
(|)((|)|(|))
4
(|)((|)...

output:


input:


output:


result: