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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#291993#4896. Alice、Bob 与 DFSdo_while_true0 0ms0kbC++202.7kb2023-12-27 15:37:312023-12-27 15:37:32

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你现在查看的是最新测评结果

  • [2023-12-27 15:37:32]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2023-12-27 15:37:31]
  • 提交

answer

#include<cstdio>
#include<vector>
#include<queue>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<ctime>
#include<random>
#include<assert.h>
#define pb emplace_back
#define mp make_pair
#define fi first
#define se second
#define dbg(x) cerr<<"In Line "<< __LINE__<<" the "<<#x<<" = "<<x<<'\n'
#define dpi(x,y) cerr<<"In Line "<<__LINE__<<" the "<<#x<<" = "<<x<<" ; "<<"the "<<#y<<" = "<<y<<'\n'
#define DE(fmt,...) fprintf(stderr, "Line %d : " fmt "\n",__LINE__,##__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>pii;
typedef pair<ll,int>pli;
typedef pair<ll,ll>pll;
typedef pair<int,ll>pil;
typedef vector<int>vi;
typedef vector<ll>vll;
typedef vector<pii>vpii;
typedef vector<pll>vpll;
template<typename T>T cmax(T &x, T y){return x=x>y?x:y;}
template<typename T>T cmin(T &x, T y){return x=x<y?x:y;}
template<typename T>
T &read(T &r){
	r=0;bool w=0;char ch=getchar();
	while(ch<'0'||ch>'9')w=ch=='-'?1:0,ch=getchar();
	while(ch>='0'&&ch<='9')r=r*10+(ch^48),ch=getchar();
	return r=w?-r:r;
}
template<typename T1,typename... T2>
void read(T1 &x,T2& ...y){read(x);read(y...);}
const int N=400010;
const int M=400001;
int n,m;
int c[N],f[N][4];
vi eg[N];
int tree[N],ok[N];
inline int lowbit(int x){return x&(-x);}
void modify(int x,int v){
	if(v==1)ok[x]=1;
	++x;
	for(;x<=M;x+=lowbit(x))tree[x]+=v;
}
int kth(int k){
	int x=0;--k;
	for(int i=18;~i;--i){
		int p=(1<<i);
		if(x+p<=M && k>=p-tree[x+p])
			k-=p-tree[x+p],x+=p;
	}
	return x;
}
signed main(){
	read(n);
	for(int i=1;i<=n;i++)read(c[i]);
	for(int i=1;i<=n;i++){
		int k;read(k);
		for(int j=1;j<=k;j++){
			int x;read(x);
			eg[i].pb(x);
		}
		reverse(eg[i].begin(),eg[i].end());
		if(eg[i].empty())c[i]=1; 
	}
	for(int x=n;x>=1;x--)
		for(int i=1;i<3;i++)
			if(c[x]){
				vi vec;
				int now=i;
				if(now&1)modify(0,1),vec.pb(0);
				if(now&2)modify(1,1),vec.pb(1);
				for(auto v:eg[x]){
					now=ok[0]|(ok[1]<<1);
					int w=0;
					if(c[v]==0)w=f[v][now];
					else w=kth(f[v][now]+1-ok[0]-ok[1]);
					if(!ok[w]){
						modify(w,1);
						vec.pb(w);
					}
				}
				f[x][i]=kth(1);
				for(auto w:vec)ok[w]=0,modify(w,-1);
			}
			else{
				int now=i;
				for(auto v:eg[x]){
					if(f[v][now]==0)now=1;//new S={0}
					else now=2;//new S={1}
				}
				f[x][i]=now==2?0:1;
			}
	for(int i=1;i<=n;i++){
		assert(f[i][1]==f[i][3]);
//		cout<<f[i][0]<<' '<<f[i][1]<<' '<<f[i][2]<<' '<<f[i][3]<<'\n';
	}
	int q,s=0;read(q);
	while(q--){
		int x;read(x);
		s^=f[x][1];
	}
	if(s)puts("Alice");
	else puts("Bob");
    #ifdef do_while_true
//		cerr<<'\n'<<"Time:"<<1.0*clock()/CLOCKS_PER_SEC*1000<<" ms"<<'\n';
	#endif
	return 0;
}

詳細信息

Subtask #1:

score: 0
Runtime Error

Test #1:

score: 0
Runtime Error

input:

1000
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0...

output:


result:


Subtask #2:

score: 0
Runtime Error

Test #18:

score: 0
Runtime Error

input:

7
0 0 1 1 0 1 1
1 2
2 3 4
0
2 5 6
0
1 7
0
1
1

output:


result:


Subtask #3:

score: 0
Runtime Error

Test #55:

score: 0
Runtime Error

input:

7
0 0 1 1 0 1 1
1 2
2 3 4
0
2 5 6
0
1 7
0
1
1

output:


result:


Subtask #4:

score: 0
Runtime Error

Test #103:

score: 0
Runtime Error

input:

10
1 1 1 1 1 1 1 1 1 1
1 2
4 3 5 7 8
1 4
0
1 6
0
0
1 9
1 10
0
1
1

output:


result:


Subtask #5:

score: 0
Skipped

Dependency #4:

0%

Subtask #6:

score: 0
Skipped

Dependency #1:

0%