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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#285950#7607. The Doubling Game 2SortingWA 4ms51524kbC++205.3kb2023-12-17 00:38:422023-12-17 00:38:43

Judging History

你现在查看的是最新测评结果

  • [2023-12-17 00:38:43]
  • 评测
  • 测评结果:WA
  • 用时:4ms
  • 内存:51524kb
  • [2023-12-17 00:38:42]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std ;
typedef long long ll ;
typedef unsigned long long ull ;
typedef pair < int , int > pii ;
typedef vector < int > vi ;
#define fi first
#define se second
mt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());

#define rep(i, a, b) for(int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()


const int MAXN = 3e5 + 7 ;
const int MOD = 1e9 + 7 ;
const int LOG = 22 ;

int n ;
vector < int > v[ MAXN ] ;
int subtree[ MAXN ] ;


ll dp[ MAXN ][ LOG ] , wtf[ MAXN ][ LOG ] ; //
ll root[ MAXN ][ LOG ] ; //
ll complete[ MAXN ] ;

int mxpw[ MAXN ] ;
ll f[ ( 1 << LOG ) ][ LOG ] ;
int bit_rv[ 2 * ( 1 << LOG ) ] ;

bool cmp ( int x , int y ) {
    return ( mxpw[ x ] < mxpw[ y ] ) ;
}

void dfs ( int x , int prv ) {
    vector < int > children ;
    for ( auto y : v[ x ] ) {
        if ( y == prv ) { continue ; }
        dfs ( y , x ) ;
        children.push_back ( y ) ;
    }
    sort ( children.begin ( ) , children.end ( ) , cmp ) ;
    mxpw[ x ] = 0 ;
    subtree[ x ] = 1 ;
    for ( int i = 0 ; i < LOG ; ++ i ) {
        f[ 0 ][ i ] = 0 ;
    }
    f[ 0 ][ LOG - 1 ] = 1 ;
    for ( auto y : children ) {
        subtree[ x ] += subtree[ y ] ;
        int rem = mxpw[ x ] ;
        mxpw[ x ] = max ( mxpw[ x ] , min ( mxpw[ x ] + 2 , mxpw[ y ] + 2 ) ) ;
        // while ( mxpw[ x ] < LOG - 1 && ( 1 << mxpw[ x ] ) < 2 * subtree[ x ] ) { ++ mxpw[ x ] ; }
        if ( rem < mxpw[ x ] ) {
            int lo = ( 1 << rem ) ;
            int hi = ( 1 << mxpw[ x ] ) - 1 ;
            for ( int i = lo ; i <= hi ; ++ i ) {
                for ( int j = 0 ; j < LOG ; ++ j ) {
                    f[ i ][ j ] = 0 ;
                }
            }
        }
        for ( int i = ( 1 << mxpw[ x ] ) - 1 ; i >= 0 ; -- i ) {
            for ( int dig = 0 ; dig <= mxpw[ x ] ; ++ dig ) {
                wtf[ i ][ dig ] = 0 ;
            }
            wtf[ i ][ LOG - 1 ] = 0 ;
        }
        for ( int i = ( 1 << mxpw[ x ] ) - 1 ; i >= 0 ; -- i ) {
            for ( int j = 0 ; j <= mxpw[ y ] ; ++ j ) { 
                if ( ( i & ( 1 << j ) ) == 0 ) { 
                    for ( int dig = 0 ; dig <= mxpw[ x ] ; ++ dig ) {
                        if ( j >= dig ) { continue ; }
                        wtf[ ( i + ( 1 << j ) ) ][ dig ] = ( wtf[ ( i + ( 1 << j ) ) ][ dig ] + f[ i ][ dig ] * root[ y ][ j ] ) % MOD ;
                    }
                    wtf[ ( i + ( 1 << j ) ) ][ LOG - 1 ] = ( wtf[ ( i + ( 1 << j ) ) ][ LOG - 1 ] + f[ i ][ LOG - 1 ] * root[ y ][ j ] ) % MOD ;
                    wtf[ i ][ j ] = ( wtf[ i ][ j ] + f[ i ][ LOG - 1 ] * dp[ y ][ j ] ) % MOD ; 
                }
                wtf[ i ][ j ] = ( wtf[ i ][ j ] + f[ i ][ j ] * complete[ y ] ) % MOD ;
            }
            wtf[ i ][ LOG - 1 ] = ( wtf[ i ][ LOG - 1 ] + f[ i ][ LOG - 1 ] * complete[ y ] ) % MOD ;
        }
        for ( int i = ( 1 << mxpw[ x ] ) - 1 ; i >= 0 ; -- i ) {
            for ( int dig = 0 ; dig <= mxpw[ x ] ; ++ dig ) {
                f[ i ][ dig ] = wtf[ i ][ dig ] ;
            }
            f[ i ][ LOG - 1 ] = wtf[ i ][ LOG - 1 ] ;
        }
    }
    /**
    for ( int i = 0 ; i < ( 1 << mxpw[ x ] ) ; ++ i ) {
        for ( int j = 0 ; j <= mxpw[ x ] ; ++ j )  {
            printf ( "vertex %d --> f[ %d ][ %d ] = %lld\n" , x , i , j , f[ i ][ j ] ) ;
        }
        printf ( "vertex %d --> f[ %d ][ -1 ] = %lld\n" , x , i , f[ i ][ LOG - 1 ] ) ;
    }
    **/
    for ( int mask = 0 ; mask < ( 1 << mxpw[ x ] ) ; ++ mask ) {
        int lw = bit_rv[ ( ( ~mask ) & -( ~mask ) ) ] ; // smallest 0 bit id
        for ( int p1 = 0 ; p1 < LOG ; ++ p1 ) {
            if ( ( mask & ( 1 << p1 ) ) > 0 ) { continue ; }
            if ( p1 == LOG - 1 ) { //
                if ( ( ( mask + ( 1 << lw ) ) & ( mask + ( 1 << lw ) + 1 ) ) == 0 ) { 
                    dp[ x ][ lw ] = ( dp[ x ][ lw ] + f[ mask ][ p1 ] ) % MOD ;
                }
                if ( ( mask & ( mask + 1 ) ) == 0 ) {
                    root[ x ][ lw ] = ( root[ x ][ lw ] + f[ mask ][ p1 ] ) % MOD ;
                    complete[ x ] = ( complete[ x ] + f[ mask ][ p1 ] ) % MOD ;
                }
            }
            else {
                if ( ( mask + ( 1 << lw ) ) == ( 1 << p1 ) - 1 ) {
                    dp[ x ][ lw ] = ( dp[ x ][ lw ] + f[ mask ][ p1 ] ) % MOD ;
                }
                if ( mask == ( 1 << p1 ) - 1 ) {
                    complete[ x ] = ( complete[ x ] + f[ mask ][ p1 ] ) % MOD ;
                }
            }
        }
    }
    /**
    printf ( "----- vertex %d\n" , x ) ;
    printf ( "complete[ %d ] = %lld\n" , x , complete[ x ] ) ;
    for ( int i = 0 ; i <= mxpw[ x ] ; ++ i ) {
        printf ( "dp[ %d ][ %d ] = %lld\n" , x , i , dp[ x ][ i ] ) ;
        printf ( "root[ %d ][ %d ] = %lld\n" , x , i , root[ x ][ i ] ) ;
    }
    **/
}

void solve ( ) {
    cin >> n ;
    for ( int i = 1 , x , y ; i < n ; ++ i ) {
        cin >> x >> y ;
        v[ x ].push_back ( y ) ;
        v[ y ].push_back ( x ) ;
    }
    for ( int i = 0 ; i < 2 * ( 1 << LOG ) ; ++ i ) {
        bit_rv[ i ] = -1 ;
    }
    for ( int i = 0 ; i <= LOG ; ++ i ) {
        bit_rv[ ( 1 << i ) ] = i ;
    }
    dfs ( 1 , -1 ) ;
    cout << complete[ 1 ] << "\n" ;
}

int main ( ) {
    ios_base :: sync_with_stdio ( false ) ;
    cin.tie ( NULL ) ;
    int t = 1 ; // cin >> t ;
    while ( t -- ) { solve ( ) ; }
    return 0 ;
}


詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 49208kb

input:

5
1 2
1 3
1 4
4 5

output:

21

result:

ok single line: '21'

Test #2:

score: 0
Accepted
time: 0ms
memory: 47224kb

input:

1

output:

1

result:

ok single line: '1'

Test #3:

score: 0
Accepted
time: 4ms
memory: 51524kb

input:

128
11 32
116 81
65 4
117 47
5 81
104 30
61 8
82 59
95 20
92 29
29 127
97 39
123 33
59 128
115 33
83 67
74 16
77 33
64 73
124 123
8 127
61 51
101 122
35 90
119 116
112 27
81 93
109 123
54 1
119 100
116 16
65 47
67 27
22 105
76 87
36 39
27 96
72 31
91 123
21 105
118 12
110 48
121 72
14 115
24 16
106 ...

output:

508800953

result:

ok single line: '508800953'

Test #4:

score: -100
Wrong Answer
time: 0ms
memory: 49360kb

input:

256
53 177
57 242
74 90
107 104
209 169
132 70
152 142
71 168
143 99
91 130
202 140
49 165
209 193
209 137
159 188
247 48
49 21
20 208
155 185
120 231
83 87
37 84
143 18
106 8
114 79
191 158
208 256
133 252
215 92
199 108
166 168
39 217
85 69
204 139
100 75
111 6
230 198
79 130
26 155
155 38
55 81
1...

output:

711068857

result:

wrong answer 1st lines differ - expected: '999869740', found: '711068857'